Display MySQL Results into HTML Table with URL - php

Question

The code below isn't working as intended. I was wanting 3 columns with the first column being a site name, the second column being the category, and the third being the URL for RSS (haven't gotten to that part yet). The data is in the database but when I view the result of the statements below, the site name results link to the current web page I am on. I would greatly appreciate any assistance with getting each column of data to display on the page correctly. Thank you
<?php
$query="SELECT * FROM SOMETABLE";
$result=mysql_query($query);
$num = mysql_numrows($result);
echo "
<table border='1'>
<th>Site Name:</th>
<th>Category:</th>
<th>RSS:</th>";
$i=0;
while ($i < $num) {
$siteName =mysql_result($result,$i,"siteName");
$category =mysql_result($result,$i,"category");
$category =mysql_result($result,$i,"url");
$rss =mysql_result($result,$i,"rss");
echo "
<tr>
<td><a href='$url'>$siteName</a></td>
<td>$category</td>
<td>$rss</td>
</tr>";
$i++;
}
?>

Answer 1

echo "<table>";
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo "<tr>";
echo "<td>$line ["siteName"]</td>";
echo "<td>$line ["category"]</td>";
echo "<td>$line ["url"]</td>";
echo "<td>$line ["rss"]</td>";
echo "</tr>";
}
echo "</table>";
skip $num, mysql_resuls ( the way how you do it ) open row TR in headers ( I skipped it ) and close table

Answer 2

echo "
<table border='1'>
<th>Site Name:</th>
<th>Category:</th>
<th>RSS:</th>";
Should be:
echo "
<table border='1'>
<tr>
<th>Site Name:</th>
<th>Category:</th>
<th>RSS:</th>
</tr>";
To start with.

Answer 3

Or just use some tool like SDTable.com or jqGrid and let them do all job for you =)