PHP: compare two arrays and sort by priority - php

Question

I would like to compare two arrays: one is containing the list of possible options and the other array contains priorities.
This is how the two arrays are organized :
foreach ($varsA as $varA) {
foreach ($varsB as $varB) {
$options[$varA][$varB] = $id;
$priority[$varA] = $priority + $priority[$varA];
}
}
this is what $options contains:
array (
1 =>
array (
33307 => 'w',
33313 => '7',
),
2 =>
array (
33307 => 'w',
33313 => '7',
),
3 =>
array (
33307 => 'w',
33313 => '7',
),
4 =>
array (
33307 => '4',
33313 => '7',
),
)
and this is what $priority contains:
array (
1 => 5,
2 => 9,
3 => 9,
4 => 5,
)
I would like to duplicate the duplicates values from $options and keep the one with the uniques with the lowest priority:
The output would be: Array (1, 4) Because 1, 2, 3 are not unique and 1 has the smallest priority.
I was using the following function to remove duplicates but I don't know how I can adapt it to deal with priorities:
super_magic($options) {
$result = array_map("unserialize", array_unique(array_map("serialize", $options)));
foreach ($result as $key => $value) {
if ( is_array($value) ) {
$result[$key] = super_magic($value);
}
}
return $result;
}

Answer 1

This sounds like a very specialized scenario without a foundation specific to PHP. With that being said, i would look into http://php.net/manual/en/ref.array.php that page for specifics on the PHP functions at your disposal for using PHP arrays. I would look into the functions like uksort() and uasort()

Answer 2

for ($x = 1; $x <= count($options); $x++) {
for ($i = 1; $i <= count($options); $i++) {
if (array_key_exists($x, $options) && array_key_exists($i, $options)) {
if ($x != $i) {
$diff = array_diff($options[$x], $options[$i]);
if(empty($diff)) {
if ($priority[$x] >= $priority[$i]){
unset($options[$x]);
}
}
}
}
}
}