I have one field displaying date and time in following format:
30/01/2011, 4:57 pm
I want to store this in mysql using data type datetime.
After getting value from post, I try to store it in database but its storing 0000-00-00 00:00:00 in table.
How can I store above specified values?
You can use date and strtotime like this:
$date = '30/01/2011, 4:57 pm';
$to_mysql_date = date('Y-m-d h:i:s', strtotime(str_replace('/', '-', $date)));
echo $to_mysql_date;
Result:
2011-01-30 04:57:00
Working Example
Now you can use the $to_mysql_date variable to insert the date in MySQL-friendly format :)
More Info:
http://php.net/manual/en/function.date.php
http://php.net/manual/en/function.strtotime.php
If you don't want to change the formatting of your date you can always go for a VARCHAR field, but you're going to miss the purpose of datetime. Or you can transform that to a timestamp and use the TIMESTAMP field.
Alternatively, you can use:
$sd = DateTime::createFromFormat('d/M/Y, H:i a', '30/01/2011, 4:57 pm');
$mysqldate = date('Y-m-d H:i:s', strtotime($sd->format('Y-m-d H:i:s')));
Related
I have a datetime column in MySQL.
How can I convert it to the display as mm/dd/yy H:M (AM/PM) using PHP?
If you're looking for a way to normalize a date into MySQL format, use the following
$phpdate = strtotime( $mysqldate );
$mysqldate = date( 'Y-m-d H:i:s', $phpdate );
The line $phpdate = strtotime( $mysqldate ) accepts a string and performs a series of heuristics to turn that string into a unix timestamp.
The line $mysqldate = date( 'Y-m-d H:i:s', $phpdate ) uses that timestamp and PHP's date function to turn that timestamp back into MySQL's standard date format.
(Editor Note: This answer is here because of an original question with confusing wording, and the general Google usefulness this answer provided even if it didnt' directly answer the question that now exists)
To convert a date retrieved from MySQL into the format requested (mm/dd/yy H:M (AM/PM)):
// $datetime is something like: 2014-01-31 13:05:59
$time = strtotime($datetimeFromMysql);
$myFormatForView = date("m/d/y g:i A", $time);
// $myFormatForView is something like: 01/31/14 1:05 PM
Refer to the PHP date formatting options to adjust the format.
If you are using PHP 5, you can also try
$oDate = new DateTime($row->createdate);
$sDate = $oDate->format("Y-m-d H:i:s");
$valid_date = date( 'm/d/y g:i A', strtotime($date));
Reference: http://php.net/manual/en/function.date.php
Finally the right solution for PHP 5.3 and above:
(added optional Timezone to the Example like mentioned in the comments)
without time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date);
echo $date->format('m/d/y h:i a');
with time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date, new \DateTimeZone('UTC'));
$date->setTimezone(new \DateTimeZone('Europe/Berlin'));
echo $date->format('m/d/y h:i a');
An easier way would be to format the date directly in the MySQL query, instead of PHP. See the MySQL manual entry for DATE_FORMAT.
If you'd rather do it in PHP, then you need the date function, but you'll have to convert your database value into a timestamp first.
Forget all. Just use:
$date = date("Y-m-d H:i:s",strtotime(str_replace('/','-',$date)))
To correctly format a DateTime object in PHP for storing in MySQL use the standardised format that MySQL uses, which is ISO 8601.
PHP has had this format stored as a constant since version 5.1.1, and I highly recommend using it rather than manually typing the string each time.
$dtNow = new DateTime();
$mysqlDateTime = $dtNow->format(DateTime::ISO8601);
This, and a list of other PHP DateTime constants are available at http://php.net/manual/en/class.datetime.php#datetime.constants.types
This should format a field in an SQL query:
SELECT DATE_FORMAT( `fieldname` , '%d-%m-%Y' ) FROM tablename
Use the date function:
<?php
echo date("m/d/y g:i (A)", $DB_Date_Field);
?>
Depending on your MySQL datetime configuration. Typically: 2011-12-31 07:55:13 format. This very simple function should do the magic:
function datetime()
{
return date( 'Y-m-d H:i:s', time());
}
echo datetime(); // display example: 2011-12-31 07:55:13
Or a bit more advance to match the question.
function datetime($date_string = false)
{
if (!$date_string)
{
$date_string = time();
}
return date("Y-m-d H:i:s", strtotime($date_string));
}
SELECT
DATE_FORMAT(demo.dateFrom, '%e.%M.%Y') as dateFrom,
DATE_FORMAT(demo.dateUntil, '%e.%M.%Y') as dateUntil
FROM demo
If you dont want to change every function in your PHP code, to show the expected date format, change it at the source - your database.
It is important to name the rows with the as operator as in the example above (as dateFrom, as dateUntil). The names you write there are the names, the rows will be called in your result.
The output of this example will be
[Day of the month, numeric (0..31)].[Month name (January..December)].[Year, numeric, four digits]
Example: 5.August.2015
Change the dots with the separator of choice and check the DATE_FORMAT(date,format) function for more date formats.
You can also have your query return the time as a Unix timestamp. That would get rid of the need to call strtotime() and make things a bit less intensive on the PHP side...
select UNIX_TIMESTAMP(timsstamp) as unixtime from the_table where id = 1234;
Then in PHP just use the date() function to format it whichever way you'd like.
<?php
echo date('l jS \of F Y h:i:s A', $row->unixtime);
?>
or
<?php
echo date('F j, Y, g:i a', $row->unixtime);
?>
I like this approach as opposed to using MySQL's DATE_FORMAT function, because it allows you to reuse the same query to grab the data and allows you to alter the formatting in PHP.
It's annoying to have two different queries just to change the way the date looks in the UI.
You can have trouble with dates not returned in Unix Timestamp, so this works for me...
return date("F j, Y g:i a", strtotime(substr($datestring, 0, 15)))
This will work...
echo date('m/d/y H:i (A)',strtotime($data_from_mysql));
Using PHP version 4.4.9 & MySQL 5.0, this worked for me:
$oDate = strtotime($row['PubDate']);
$sDate = date("m/d/y",$oDate);
echo $sDate
PubDate is the column in MySQL.
Direct output e.g. in German format:
echo(date('d.m.Y H:i:s', strtotime($row["date_added"])));
$date = "'".date('Y-m-d H:i:s', strtotime(str_replace('-', '/', $_POST['date'])))."'";
I want to store php date in sql but it store 1970-01-01 05:00: instead of input datetime
This is html form
<input type="datetime" id="eventstart" name="txtEventStart" class="form-control" value="<?php echo date('m/Y/d h:i:s');?>">
when data is sent using post
$date = $this->input->post('txtEventStart');
I convert string to date format using:
$date2 = date('Y-m-d H:i:s', strtotime($date));
It stores '1970-01-01 05:00:00'
I want to know what is the correct format for storing such type of date.
Your code is giving you the wrong results because your date is in a format (m/Y/d h:i:s) that is not recognised by strtotime. Instead, use date_create_from_format to convert it and output a date in the correct form for SQL. For example:
$date = '08/2019/19 10:23:41';
echo date('Y-m-d H:i:s', strtotime($date)) . PHP_EOL;
echo date_create_from_format('m/Y/d h:i:s', $date)->format('Y-m-d H:i:s');
Output:
1970-01-01 01:00:00
2019-08-19 10:23:41
Demo on 3v4l.org
'YYYY-MM-DD hh:mm:ss' is not an acceptable format for PHP date function. Use Y-m-d H:i:s instead. More info here: https://www.w3schools.com/php/func_date_date.asp
Update: For date input field use ISO date format Y-m-d or change input type to 'text'
I need to format and insert the date to mysql table which is type of datetime, I am doing this from php.
Here is the statement
$timestamp ="22-11-2015+00:00:00";
$mysqltime = date ("d-m-Y H:i:s", $timestamp);
But when I insert to table the date is wrong, it showing 31-12-1969 19:00:22
What could be the issue?
It should be
$timestamp ="22-11-2015+00:00:00";
$mysqltime = date ("d-m-Y H:i:s", strtotime($timestamp));
because date is expecting it's second parameter to be a number, specifically the number of seconds since midnight January 1st, 1970.
The date function expects an integer timestamp for the second argument.
This MSQL insert statement would work fine:
INSERT INTO mytable (birthday) ('2015-11-22 00:00:00')
If you're using a database class in PHP and the function you're calling is using a PHP date object, then you'd have to construct the PHP date object using the date() function.
Or if you want to use PHP code to reformat the date in PHP before sending the string to the database to be inserted, then I think you'd use strtodate to get a PHP date object, and then date()
$phpdate = strtodate('d-m-Y H:i:s', '22-11-2015 00:00:00')
$dateformysql = date('Y-m-d H:i:s', $phpdate)
databaseclass.dotheinsert($mysqldate)
This should be working, but did not work for me!
$timestamp ="22-11-2015+00:00:00";
$mysqltime = date ("d-m-Y H:i:s", strtotime($timestamp));
I believe it is because my national standard format (LC_TIME) is "Y-m-d" rather then "d-m-Y". However this works perfectly:
$timestamp ="22-11-2015+00:00:00";
// The '+' sign needs to be escaped!!
$time = date_create_from_format( "d-m-Y\+H:i:s", $timestamp);
$mysqltime = $time->format( 'd-m-Y H:i:s' );
On the other hand, MySQL use the date format "YYYY-MM-DD" as a standard. The correct format string should be:
$mysqltime = date ("Y-m-d H:i:s", strtotime($timestamp));
// or second option
$mysqltime = $time->format( 'Y-m-d H:i:s' );
I think the corret format would be:
$mysqltime = date_format ($timestamp,"d-m-Y H:i:s");
Let me know if this works
Maybe is a dumb question, but I can't find the proper function:
I have a string date like 04/05/2012
How I can pass to this format: 2012-04-05 20:18:11 to insert in mySQL?
Combination of date and strtotime ...
$my_date = date('Y-m-d H:i:s',strtotime('04/05/2012'));
$dateTime = new DateTime($your_time_string);
echo $dateTime->format("Y-m-d H:i:s");
Time can not be 'made' on its own. If you're however inserting the current date-time setting, then the following code will be used:
$dt = date( "Y-m-d H:i:s", time() );
You may use dleiftah's statement, but the time in that case will always be 00:00:00
I have a datetime column in MySQL.
How can I convert it to the display as mm/dd/yy H:M (AM/PM) using PHP?
If you're looking for a way to normalize a date into MySQL format, use the following
$phpdate = strtotime( $mysqldate );
$mysqldate = date( 'Y-m-d H:i:s', $phpdate );
The line $phpdate = strtotime( $mysqldate ) accepts a string and performs a series of heuristics to turn that string into a unix timestamp.
The line $mysqldate = date( 'Y-m-d H:i:s', $phpdate ) uses that timestamp and PHP's date function to turn that timestamp back into MySQL's standard date format.
(Editor Note: This answer is here because of an original question with confusing wording, and the general Google usefulness this answer provided even if it didnt' directly answer the question that now exists)
To convert a date retrieved from MySQL into the format requested (mm/dd/yy H:M (AM/PM)):
// $datetime is something like: 2014-01-31 13:05:59
$time = strtotime($datetimeFromMysql);
$myFormatForView = date("m/d/y g:i A", $time);
// $myFormatForView is something like: 01/31/14 1:05 PM
Refer to the PHP date formatting options to adjust the format.
If you are using PHP 5, you can also try
$oDate = new DateTime($row->createdate);
$sDate = $oDate->format("Y-m-d H:i:s");
$valid_date = date( 'm/d/y g:i A', strtotime($date));
Reference: http://php.net/manual/en/function.date.php
Finally the right solution for PHP 5.3 and above:
(added optional Timezone to the Example like mentioned in the comments)
without time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date);
echo $date->format('m/d/y h:i a');
with time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date, new \DateTimeZone('UTC'));
$date->setTimezone(new \DateTimeZone('Europe/Berlin'));
echo $date->format('m/d/y h:i a');
An easier way would be to format the date directly in the MySQL query, instead of PHP. See the MySQL manual entry for DATE_FORMAT.
If you'd rather do it in PHP, then you need the date function, but you'll have to convert your database value into a timestamp first.
Forget all. Just use:
$date = date("Y-m-d H:i:s",strtotime(str_replace('/','-',$date)))
To correctly format a DateTime object in PHP for storing in MySQL use the standardised format that MySQL uses, which is ISO 8601.
PHP has had this format stored as a constant since version 5.1.1, and I highly recommend using it rather than manually typing the string each time.
$dtNow = new DateTime();
$mysqlDateTime = $dtNow->format(DateTime::ISO8601);
This, and a list of other PHP DateTime constants are available at http://php.net/manual/en/class.datetime.php#datetime.constants.types
This should format a field in an SQL query:
SELECT DATE_FORMAT( `fieldname` , '%d-%m-%Y' ) FROM tablename
Use the date function:
<?php
echo date("m/d/y g:i (A)", $DB_Date_Field);
?>
Depending on your MySQL datetime configuration. Typically: 2011-12-31 07:55:13 format. This very simple function should do the magic:
function datetime()
{
return date( 'Y-m-d H:i:s', time());
}
echo datetime(); // display example: 2011-12-31 07:55:13
Or a bit more advance to match the question.
function datetime($date_string = false)
{
if (!$date_string)
{
$date_string = time();
}
return date("Y-m-d H:i:s", strtotime($date_string));
}
SELECT
DATE_FORMAT(demo.dateFrom, '%e.%M.%Y') as dateFrom,
DATE_FORMAT(demo.dateUntil, '%e.%M.%Y') as dateUntil
FROM demo
If you dont want to change every function in your PHP code, to show the expected date format, change it at the source - your database.
It is important to name the rows with the as operator as in the example above (as dateFrom, as dateUntil). The names you write there are the names, the rows will be called in your result.
The output of this example will be
[Day of the month, numeric (0..31)].[Month name (January..December)].[Year, numeric, four digits]
Example: 5.August.2015
Change the dots with the separator of choice and check the DATE_FORMAT(date,format) function for more date formats.
You can also have your query return the time as a Unix timestamp. That would get rid of the need to call strtotime() and make things a bit less intensive on the PHP side...
select UNIX_TIMESTAMP(timsstamp) as unixtime from the_table where id = 1234;
Then in PHP just use the date() function to format it whichever way you'd like.
<?php
echo date('l jS \of F Y h:i:s A', $row->unixtime);
?>
or
<?php
echo date('F j, Y, g:i a', $row->unixtime);
?>
I like this approach as opposed to using MySQL's DATE_FORMAT function, because it allows you to reuse the same query to grab the data and allows you to alter the formatting in PHP.
It's annoying to have two different queries just to change the way the date looks in the UI.
You can have trouble with dates not returned in Unix Timestamp, so this works for me...
return date("F j, Y g:i a", strtotime(substr($datestring, 0, 15)))
This will work...
echo date('m/d/y H:i (A)',strtotime($data_from_mysql));
Using PHP version 4.4.9 & MySQL 5.0, this worked for me:
$oDate = strtotime($row['PubDate']);
$sDate = date("m/d/y",$oDate);
echo $sDate
PubDate is the column in MySQL.
Direct output e.g. in German format:
echo(date('d.m.Y H:i:s', strtotime($row["date_added"])));
$date = "'".date('Y-m-d H:i:s', strtotime(str_replace('-', '/', $_POST['date'])))."'";