Display partial rows after the first row - php

Question

I am trying to take the following rows
username | id | role
SELECT u.username, u.id, r.role FROM ".TBL_USERS." u
INNER JOIN ".TBL_ADMIN_ROLES." r ON r.userid = u.id
WHERE u.userlevel > 3
At the moment, I use the following code to get the results.
<?php
$q = $database->getAllAdmins();
while($row=mysql_fetch_assoc($q))
{
?>
<a class="main" href="profile.php?id=<? echo $row['id']; ?>"><? echo $row['username']; ?></a>
<ul>
<li><? echo $row['role']; ?></li>
</ul>
<?
}
?>
Obviously, this is looping through and showing the username over and over.
What I want it to do is show the username once and then show every role below.
Any ideas? Thanks :)

Answer 1

$q = $database->getAllAdmins();
$user = "";
while($row=mysql_fetch_assoc($q)) {
if ($user != $row['username']) {
if ($user != "") { echo "</ul>"; }
echo "<a class='main' href='profile.php?id={$row['id']}'>{$row['username']}</a>";
echo "<ul>";
}
echo "<li>{$row['role']}</li>";
$user = $row['username'];
}
My answer is the same concept as the others, just cleaner.

Answer 2

If you add a ORDER BY i.id to your query, you can then use a variable to keep track of the last user.
<?php
$q = $database->getAllAdmins();
$lastUserID = 0;
while($row=mysql_fetch_assoc($q))
{
$newUser = $lastUserID != $row['id'];
if($newUser) {
?>
<a class="main" href="profile.php?id=<? echo $row['id']; ?>"><? echo $row['username']; ?></a>
<ul>
<? }
?>
<li><? echo $row['role']; ?></li>
<? if($newUser) {
?>
</ul>
<? $lastUserID = $row['id'];
}
}
?>