I have a class that build my main navigation. Everything works fine except for the html output i get in the source code. In my class i got something like this:
public function getNav(){
$output = "";
foreach($nav as $key=>$value){
$output .= "<li><a href='$value'>$key</a></li>\n";
}
return $output;
}
Then i show navigation in my template...
<ul class="nav">
<?php echo $site->getNav(); ?>
</ul>
... and the html source look like this:
<ul id="nav">
<li><a href='index.php'><span>HOME</span></a></li>
<li><a href='page2.php'><span>PAGE 2</span></a></li>
<li><a href='page3.php'><span>PAGE 3</span></a></li>
</ul>
This is probably irrelevant, i'm just trying to understand if i get this due to the double quoted or what...
This output has nothing to do with the doublequotes(except the linebreak, which you wouldn't have without them).
Are you sure that your template is
<ul class="nav">
<?php echo $site->getNav(); ?>
</ul>
...and not
<ul class="nav">
<?php echo $site->getNav(); ?>
</ul>
?
That's the only mysterious thing I see.
Related
I am trying to display something from my database on a bootstrap bar and I have no idea how to combine or implement the two. Ive made my bootstrap html's file a .php, was that the correct thing to do? Here's my code (ignore the filler words)
<ul class="nav nav-list well">
<li class="nav-header"></li>
<li class="active">HIT INFO</li>
<li>Linky link</li>
<li class="divider"></li>
<li>ANOTHER HIT INFO</li>
<li>ANOTHER LINKY LINK</li>
<li class="divider"></li>
<li>YET ANOTHER HIT</li>
<li>AAAAAnd another link</li>
</ul>
and this is the php i want to include (the code to making what i want to display is in the file)
<?php include 'one.php'; ?>
where "linky link" is, i want to display this but it didnt seem to work when i put that php right there. Another thing i want to do is when a link from the database gets displayed, it displays as a bootstrap button. i tried and am just not sure how to implement php code in my bootstrap code.
Print " <td>".$row['link'] . "</td></tr> ";
How would i add this bootstrap code to that so when a link from my database gets displayed, it gets displayed as this button
<i class="icon-heart icon-white"></i>Do this HIT!
Your code seems right to me except to your "<td> and <tr>" tag. You're not using it right.
Try this approach
In one.php
<?php
$links = array( 0 => array("url"=>"http://google.com","text"=>"Google") );
?>
In Menu
<?php include('one.php')?>
<ul>
<li>Menu one</li>
<?php foreach( $links as $link){ ?>
<li><a href="<?php print $link['url']?>"><?php print $link['text']?></li>
<?php } ?>
</ul>
Hi I have a menu on my site on each page, I want to put it in it's own menu.php file but i'm not sure how to set the class="active" for whatever page i'm on.
Here is my code: please help me
menu.php:
<li class=" has-sub">
<a class="" href="javascript:;"><i class=" icon-time"></i> Zeiten<span class="arrow"></span></a>
<ul class="sub">
<li><a class="" href="offnungszeiten.php">Öffnungszeiten</a></li>
<li><a class="" href="sauna.php">Sauna</a></li>
<li><a class="" href="frauensauna.php">Frauensauna</a></li>
<li class=""><a class="" href="custom.php">Beauty Lounge</a></li>
<li><a class="" href="feiertage.php">Feiertage</a></li>
</ul>
</li>
this method gets the current page using php which will pass a word in this case active and places it inside the class parameter to set the page active.
<?php
function active($currect_page){
$url_array = explode('/', $_SERVER['REQUEST_URI']) ;
$url = end($url_array);
if($currect_page == $url){
echo 'active'; //class name in css
}
}
?>
<ul>
<li><a class="<?php active('page1.php');?>" href="http://localhost/page1.php">page1</a></li>
<li><a class="<?php active('page2.php');?>" href="http://localhost/page2.php">page2</a></li>
<li><a class="<?php active('page3.php');?>" href="http://localhost/page3.php">page3</a></li>
<li><a class="<?php active('page4.php');?>" href="http://localhost/page4.php">page4</a></li>
</ul>
It would be easier if you would build an array of pages in your script and passed it to the view file along with the currently active page:
//index.php or controller
$pages = array();
$pages["offnungszeiten.php"] = "Öffnungszeiten";
$pages["sauna.php"] = "Sauna";
$pages["frauensauna.php"] = "Frauensauna";
$pages["custom.php"] = "Beauty Lounge";
$pages["feiertage.php"] = "Feiertage";
$activePage = "offnungszeiten.php";
//menu.php
<?php foreach($pages as $url=>$title):?>
<li>
<a <?php if($url === $activePage):?>class="active"<?php endif;?> href="<?php echo $url;?>">
<?php echo $title;?>
</a>
</li>
<?php endforeach;?>
With a templating engine like Smarty your menu.php would look even nicer:
//menu.php
{foreach $pages as $url=>$title}
<li>
<a {if $url === $activePage}class="active"{/if} href="{$url}">
{$title}
</a>
</li>
{/foreach}
Create a variable in each of your php file like :
$activePage = "sauna"; (different for each page)
then check that variable in your html page like this
<?php if ($activePage =="sauna") {?>
class="active" <?php } ?>
Put all the below code in menu.php and everything will be taken care of.
// function to get the current page name
function PageName() {
return substr($_SERVER["SCRIPT_NAME"],strrpos($_SERVER["SCRIPT_NAME"],"/")+1);
}
$current_page = PageName();
Use the above to get the current page name then put this in your menu
<li><a class="<?php echo $current_page == 'offnungszeiten.php' ? 'active':NULL ?>" href="offnungszeiten.php">Öffnungszeiten</a></li>
<li><a class="<?php echo $current_page == 'sauna.php' ? 'active':NULL ?>" href="sauna.php">Sauna</a></li>
<li><a class="<?php echo $current_page == 'frauensauna.php' ? 'active':NULL ?>" href="frauensauna.php">Frauensauna</a></li>
<li><a class="<?php echo $current_page == 'custom.php' ? 'active':NULL ?>" href="custom.php">Beauty Lounge</a></li>
<li><a class="<?php echo $current_page == 'feiertage.php' ? 'active':NULL ?>" href="feiertage.php">Feiertage</a></li>
where active is the name of the class which will highlight your menu item
there is two things you can do.
first you can read the current filename of the php file you request by using $_SERVER['PHP_SELF'] or $_SERVER['REQUEST_URI'] or any other $_SERVER global variables that you can use to read your current page and compare it with the link's url, something like this
<a href="offnungszeiten.php" <?php if($_SERVER['PHP_SELF']=='offnungszeiten.php'){ ?>class="activatepage" <?php } ?> >
Öffnungszeiten
</a>
the second one is to create a variable that you can read globally that would store the current name of the current page, like this
<?php
$cur_page ="offnungszeiten"
?>
<a href="offnungszeiten.php" <?php if($cur_page=='offnungszeiten'){ ?>class="activatepage" <?php } ?> >
Öffnungszeiten
</a>
I have done it with php in this way,
function createTopNav($active)
{
$pages = array(
array(
'name'=>'Home',
'link'=>'index'
),
array(
'name'=>'Smartphone',
'link'=>'smartphone'
),
array(
'name'=>'Tablet',
'link'=>'tablet'
),
array(
'name'=>'About Us',
'link'=>'about'
),
array(
'name'=>'Contact Us',
'link'=>'contact'
)
);
$res = "<ul>";
$activePage = "";
foreach($pages as $key=>$val)
{
if($val['link']==$active)
{
$res.= "<li><a href='".$val['link']."' class='active' >".$val['name']."</a></li>";
}
else
{
$res.= "<li><a href='".$val['link']."'>".$val['name']."</a></li>";
}
}
$res.="</ul>";
return $res;
}
And then to call this function
echo createTopNav("about");
and the output will be like this
<ul>
<li>Home</li>
<li>Smartphone</li>
<li>Tablet</li>
<li>About Us</li>
<li>Contact Us</li>
</ul>
I solved this using jQuery/javascript by running the code below each time my any page is loaded:
$(document).ready(function () {
//Get CurrentUrl variable by combining origin with pathname, this ensures that any url appendings (e.g. ?RecordId=100) are removed from the URL
var CurrentUrl = window.location.origin+window.location.pathname;
//Check which menu item is 'active' and adjust apply 'active' class so the item gets highlighted in the menu
//Loop over each <a> element of the NavMenu container
$('#NavMenu a').each(function(Key,Value)
{
//Check if the current url
if(Value['href'] === CurrentUrl)
{
//We have a match, add the 'active' class to the parent item (li element).
$(Value).parent().addClass('active');
}
});
});
This implementation assumes your menu has the 'NavMenu' ID, and uses http://hostname/scriptname.php href attributes like so:
<ul id="NavMenu">
<li>Home</li>
<li>Smartphone</li>
<li>Tablet</li>
<li>About Us</li>
<li>Contact Us</li>
</ul>
Read the javascript comments to see what's going on. If you prefer to use a different href layout (like in your original example), you have to play with the CurrentUrl variable a bit to get it to use the same layout as your href attributes.
For me this was the easiest solution since I had an existing sites with a big menu and many pages, and wanted to avoid having to modify all pages. This allows me to throw in a piece javascript code in the header file (which was a central file already) which solves the problem for all existing pages.
A bit late on the ball, but I just had to solve this myself and ended up using this Javascript method, with a small modification. This has the advantage on not requiring many changes to the current code, just run the script and voila.
window.onload = activateCurrentLink;
function activateCurrentLink(){
var a = document.getElementsByTagName("A");
for(var i=0;i<a.length;i++)
if(a[i].href == window.location.href.split("#")[0])
a[i].className = 'activelink';
}
Send page name in query string and check it on every page by getting the variable.
Simplere solution:
Borrowing the code from asprin above;
Create a new file menu.php where you will store the one and only copy of the menu. In this file, you will create a function addMenu($pageName) that take a parameter as the page name and returns a string consisting of the menu after having added the current tag.
In your HTML code, you would include(menu.php) and then call the function addMenu with the current page name. So your code will look like this:
menu.php
<?php
function addMenu($pageName){
$menu =
'<ul>
<li><a href="Öffnungszeiten.php"' . ($pageName == "Öffnungszeiten" ? "class=\"current\"" : "") . '><span>Öffnungszeiten</span></a></li>
<li><a href="sauna.php"' . ($pageName == "Öffnungszeiten" ? "class=\"current\"" : "") . '><span>Sauna</span></a></li>
<li><a href="frauensauna.php"' . ($pageName == "Frauensauna" ? "class=\"current\"" : "") . '><span>Frauensauna</span></a></li>
<li><a href="custom.php" ' . ($pageName == "lounge" ? "class=\"current\"" : "") . '><span>Beauty Lounge</span></a></li>
<li><a href="Feiertage.php"' . ($pageName == "feiertage" ? "class=\"current\"" : "") . '><span>Feiertage</span></a></li>
</ul>';
return $menu;
}
?>
And in your HTML, say this:
<div id="menu">
<?php
include('menu.php');
echo addMenu("index");
echo $hello;
?>
</div>
This worked for me:
function active_page($script){
$actual = basename($_SERVER['PHP_SELF']);
if($script == $actual){
return 'active-page'; //class name in css
}
}
I have some simple example, see below:
<?php
function active($currect_page) {
$url = $_SERVER['REQUEST_URI'];
if($currect_page == $url){
echo 'active';
}
}
?>
<ul class="navbar-nav mr-auto">
<li class="nav-item <?php active('/');?>">
<a class="nav-link" href="/">Home</a>
</li>
<li class="nav-item <?php active('/other');?>">
<a class="nav-link" href="/other">Other page</a>
</li>
</ul>
Better late than never - I like to keep it simple, to be honest, especially if there's a ton of scripting and PHP going on.
I place this code on the top of each page to identify the page:
<?php
$current_page = 'home';
include 'header.php';
?>
Then your menu/navigation (mine is bootstrap 4) looks like this:
<ul class="navbar-nav mx-auto">
<li class="nav-item <?php if ($current_page=="home") {echo "active"; }?>">
<a class="nav-link" href="<?php echo SITEURL;?>/">Home</a>
</li>
<li class="nav-item <?php if ($current_page=="about") {echo "active"; }?>">
About
</li>
<li class="nav-item <?php if ($current_page=="store") {echo "active"; }?>">
Store
</li>
<li class="nav-item <?php if ($current_page=="news") {echo "active"; }?>">
News
</li>
<li class="nav-item <?php if ($current_page=="contact") {echo "active"; }?>">
Contact
</li>
</ul>
I'm not saying this is the optimal method, but it works for me and it's simple to implement.
adding this:<?= ($activePage == 'home') ? 'active':''; ?> to my link it works perfectly, I only can't make the child of a submenu working to make the parent active.
Assume you have a navbar with the following items:
<ul>
<li id="menu-item-home">HOME</li>
<li id="menu-item-services">SERVICES</li>
<li id="menu-item-about-us">ABOUT US</li>
<li id="menu-item-contact">CONTACT</li>
</ul>
Then, declare a javascript variable in each page as below:
<script>
<?php echo("var active = 'menu-item-home';"); ?>
</script>
The variable "active" is assigned with the corresponding item of each page.
Now, you can use this variable to highlight the active menu item as below.
$(window).ready(function(){$("#" + active).addClass("active");});
I have a similar issue with my web app menu.
I also have sub menus which do not appear as top level menu buttons.
My solution is as follows:
a) Partial php file with menu html and a little php function at the top that checks GET variables against the menu buttons.
I have two GET variables to check: the page and (if necessary) the menu_button.
b) Adding any new php page with a href links to either menu pages or sub menu pages.
The variable "menu_button" is optional and can be used to link to submenu php files.
Of course the security concerning GET variables should be considered.
From my point of view, this solution has less effort than having to maintain an array of pages or links somewhere.
You just use a get variable "menu_button" where you pass the top level menu button that should be marked visually in any link which targets your php file.
Code examples:
Partial menu.php (has to be included in every php file):
<?php
function active($page_link){
$menu_button = $_GET("menu_button") ?: $_GET("page"); // sets the menu button either to the given top level menu or it defaults to the page itself
if($menu_button === $page_link) return "active";
}
?>
<div>
<a href="?page=one" class="<?= active('one') ?>"Link one</a>
Link two
</div>
Any php file with links to sub menu file:
<div>
Link one
Link to sub menu page "three" of menu "two"
</div>
Works for me. Hope someone else can use this.
For making a dynamic active menu link I follow this method.
first, In the menu link, I always use the full address:
//HTML CODE
<ul class="menu">
<li>
Home
</li>
<li>
About us
</li>
<li>
Contact
</li>
</ul>
//Javacript Code
const menus = document.querySelectorAll('.menu li a');
menus.forEach((menu) => {
const currentLocation = window.location.href;
if (currentLocation === window.origin) {
menus[0].classList.add('active');
} else if (menu.href === currentLocation) {
menu.classList.add('active');
} else {
return;
}
});
and then I will use vanilla javascript code to do the rest
You can use
<?php
function active($current_page){
$page = $_GET['p'];
if(isset($page) && $page == $current_page){
echo 'active'; //this is class name in css
}
}
?>
<ul>
<li><a class="<?php active('page1');?>" href="?p=page1">page1</a></li>
<li><a class="<?php active('page2');?>" href="?p=page2">page2</a></li>
<li><a class="<?php active('page3');?>" href="?p=page3">page3</a></li>
<li><a class="<?php active('page4');?>" href="?p=page4">page4</a></li>
</ul>
This is my first post so forgive as I am just new in the world of web development.
Normally, when I try to make a website, I create a file called header.html and footer.html so that I only change data once in all of the pages rather than having multiple same headers on many html files. And include them all in a php file together with the content and the php codes that comes per page.
Now my problem is because I only have 1 header, the css is designed in a way that whatever the current menu/tab is, it will be marked as "selected" so that its obvious to the user what page they are currently in.
My question is how do I solve this problem:
1.) To have the class="selected" depending on what the current page/url is.
<!--Menu Starts-->
<div class="menu">
<div id="smoothmenu" class="ddsmoothmenu">
<ul>
<li>Home</li>
<li>About </li>
<li>Services </li>
<li>Features</li>
<li>Support
<ul>
<li>Support 1</li>
<li>Support 2</li>
</ul>
</li>
</ul>
</div>
</div>
<!-- Menu Ends--!>
Thank You :)
If you're looking for a non-javascript / php approach...
First you need to determine which nav-link should be set as active and then add the selected class. The code would look something like this
HTML within php file
Call a php function inline within the hyperlink <a> markup passing in the links destination request uri
<ul>
<li><a href="index.php" <?=echoSelectedClassIfRequestMatches("index")?>>Home</a></li>
<li><a href="about.php" <?=echoSelectedClassIfRequestMatches("about")?>>About</a> </li>
<li><a href="services.php" <?=echoSelectedClassIfRequestMatches("services")?>>Services</a> </li>
<li><a href="features.php" <?=echoSelectedClassIfRequestMatches("features")?>>Features</a></li>
<li>Support
<ul>
<li><a href="support1.php" <?=echoSelectedClassIfRequestMatches("support1")?>>Support 1</a></li>
<li><a href="support2.php" <?=echoSelectedClassIfRequestMatches("support2")?>>Support 2</a></li>
</ul>
</li>
</ul>
PHP function
The php function simply needs to compare the passed in request uri and if it matches the current page being rendered output the selected class
<?php
function echoSelectedClassIfRequestMatches($requestUri)
{
$current_file_name = basename($_SERVER['REQUEST_URI'], ".php");
if ($current_file_name == $requestUri)
echo 'class="selected"';
}
?>
You could ID each link and use JavaScript/Jquery to add the selected class to the appropriate link.
<!--Menu Starts-->
<div class="menu">
<div id="smoothmenu" class="ddsmoothmenu">
<ul>
<li id="home-page">Home</li>
<li id="about-page">About </li>
<li id="services-page">Services </li>
<li id="features-page">Features</li>
<li id="support-page">Support
<ul>
<li id="support1-page">Support 1</li>
<li id="support2-page">Support 2</li>
</ul>
</li>
</ul>
</div>
</div>
<!-- Menu Ends--!>
On your content page use jQuery to do something like:
$(document).ready(function(){
$("#features-page").addClass("selected");
});
Another method you could use is:
Add class element based on the name of the page
Give each link a separate id then use jQuery on the individual pages.
<li>Home</li>
<li>About </li>
<li>Services </li>
<li>Features</li>
<li>Support
<ul>
<li>Support 1</li>
<li>Support 2</li>
</ul>
</li>
On the services page:
$(document).ready(function(){
$("#services").addClass("selected");
});
Or even better as robertc pointed out in the comments, there is no need to even bother with the id's just make the jquery this:
$(document).ready(function(){
$("[href='services.php']").addClass("selected");
});
One variant on Chris's approach is to output a particular class to identify the page, for example on the body element, and then use fixed classes on the menu items, and a CSS rule that targets them matching. For example, this page:
<DOCTYPE HTML>
<head>
<title>I'm the about page</title>
<style type="text/css">
.about .about,
.index .index,
.services .services,
.features .features {
font-weight: bold;
}
</style>
</head>
<body class="<?php echo basename(__FILE__, ".php"); ?>">
This is a menu:
<ul>
<li>Home</li>
<li>About </li>
<li>Services </li>
<li>Features</li>
</ul>
</body>
...is pretty light on dynamic code, but should achieve the objective; if you save it as "about.php", then the About link will be bold, but if you save it as "services.php", then the Services link will be bold, etc.
If your code structure suits it, you might be able to simply hardcode the page's body class in the page's template file, rather than using any dynamic code for it. This approach effectively gives you a way of moving the "logic" for the menu system out of the menu code, which will always remain the same for every page, and up to a higher level.
As an added bonus, you can now use pure CSS to target other things based on the page you're on. For example, you could turn all the h1 elements on the index.php page red just using more CSS:
.index h1 { color: red; }
You can do it from simple if and PHP page / basename() function..
<!--Menu Starts-->
<div class="menu">
<div id="smoothmenu" class="ddsmoothmenu">
<ul>
<li><a href="index.php" <?php if (basename($_SERVER['PHP_SELF']) == "index.php") { ?> class="selected" <?php } ?>>Home</a></li>
<li><a href="about.php" <?php if (basename($_SERVER['PHP_SELF']) == "about.php") { ?> class="selected" <?php } ?>>About</a> </li>
<li><a href="services.php" <?php if (basename($_SERVER['PHP_SELF']) == "services.php") { ?> class="selected" <?php } ?>>Services</a> </li>
<li><a href="features.php" <?php if (basename($_SERVER['PHP_SELF']) == "features.php") { ?> class="selected" <?php } ?>>Features</a></li>
</ul>
</div>
</div>
Sorry for my bad English, however may be it could help. You can use jQuery for this task. For this you need to match the page url to the anchor of menu and then add class selected to it. for example the jQuery code would be
jQuery('[href='+currentURL+']').addClass('selected');
echo $nav gives code like this:
<ul>
<li class="someclass">sometext
<ul>
<li class="someclass">sometext</li>
<li class="spacer"></li>
<li class="someclass">sometext</li>
<li class="spacer"></li>
<li class="someclass">sometext</li>
<li class="spacer"></li>
<li class="someclass">sometext</li>
<li class="spacer"></li>
</ul>
</li>
<li class="spacer"></li>
<li class="someclass">sometext</li>
<li class="spacer"></li>
</ul>
There are list items with class spacer inside each child ul, after each normal list item.
How do I remove the spacer list items which are grandchildren of the main list, using PHP?
Example: <ul> <li> <ul> <li class="spacer">
I'm searching for a regular expression, which should erase <li class="spacer"></li> only in a child <ul> element.
If you don't have access to the $nav variable to remove it (which you likely do) then I'd just use CSS to hide it, something like this should work:
li ul li.spacer {
display:none;
}
If however you have access to $nav - delete that spacer li from the code. Simples.
Also, on a side note. having empty elements like that on the page as "spacers" is semantically bad. This should be handled via CSS, add margins/padding on other elements on the page, don't use a class of spacer, if you do then you may as well go back to using stray <br /> tags everywhere to create spaces.
$xml = new SimpleXMLElement($nav);
$spacers = $xml->xpath('li//li[#class="spacer"]');
foreach($spacers as $i => $n) {
unset($spacers[$i][0]);
}
echo $xml->asXML();
This is converting to XML (use a recent PHP 5.3 version and DOMDocument to export to HTML). Output:
<?xml version="1.0"?>
<ul>
<li class="someclass">sometext
<ul>
<li class="someclass">sometext</li>
<li class="someclass">sometext</li>
<li class="someclass">sometext</li>
<li class="someclass">sometext</li>
</ul>
</li>
<li class="spacer"/>
<li class="someclass">sometext</li>
<li class="spacer"/>
</ul>
How about str_replace?
$nav = str_replace('<li class="spacer"></li>','',$nav);
edited code below
Based on the new requirement this code works. I know its hacky and sloppy but it works:
$temp = explode("\n",$nav);
for ($i=0;$i<count($temp);$i++) {
if (strstr($temp[$i],"<ul>")) {
$nested_ul = 1;
}
if (strstr($temp[$i],"</ul>")) {
$nested_ul = 0;
}
if ($nested_ul==0) {
if (!strstr($temp[$i],"spacer")) {
$new_nav .= $temp[$i]."\n";
}
} else {
$new_nav .= $temp[$i]."\n";
}
}
echo $new_nav;
"Easily" is relative. It depends on a few things. If you want, modify where the $nav is getting generated from.
use preg_replace to replace the li tags:
$new_nav = preg_replace('/<li class="spacer"></li>/', '', $nav);
echo $nav;
There are multiple ways:
Do not create it. It will be easier if you do not create something you do not want. It will be easier to maintain. So if you have any control over what is generated into $var string, just change it.
Simply replace it like that: str_replace('<li class="spacer"></li>', $var).
Use some HTML parser and remove the nodes.
Use JavaScript to remove <li class="spacer"></li> on client side.
Use substr_replace and strpos instead of str_replace, and specify an offset just after the first spacer.
http://www.php.net/manual/en/function.substr-replace.php
http://www.php.net/manual/en/function.strpos.php
Add the following CSS
ul ul li.spacer { display: none; }
Try this:
$nav = str_replace('<li class="spacer"></li>', '', $nav);
Hi I am trying to have the navigation highlights determined by what category or page you are looking at using wordpress. Can someone tell me what is wrong with a statement like this:
<?php if (in_category('b')){ ?>
<ul>
<li>A</li>
<li><a class="current" href="#">B</li>
</ul>
<?php } else { ?>
<ul>
<li><a class="current" href="#">A</a></li>
<li><a href="#">B</li>
</ul>
<?php } ?>
I am trying to use something like this but my else statement is ignored and the 'b' is always current regardless of category.
You are either not inside a post or everything is in category 'b'.
See http://codex.wordpress.org/Function_Reference/in_category for in_category() information.
read here.
You've got to write something like:
<?php if (in_category('b')): ?>
<ul>
<li>A</li>
<li><a class="current" href="#">B</li>
</ul>
...