Lets say I have a view file that is built like this:
<html>
...
<title><?= Functions::Text('title'); ?></title>
....
<body>
....
<?= Functions::Text('sometext'); ?>
</body>
</html>
Functions::Text - would give me a db entry in table texts with search_string of title and sometext.
I want to pull out the data at once, and not per request (which mean - to collect an array of strings given to Texts (which is not that hard) - but I want the data, after the select query, to go to the exact places which requested the data.
which mean -
$query = select ... ;
... fetch ...
$results_of_fetch = array ('title'=>'Welcome!','sometext' => 'sometext!!');
And the view file -
<html>
...
<title>Welcome!</title>
....
<body>
....
sometext!!
</body>
</html>
I think your question is more related to Object rather than MVC.
So, i would like to make suggestion.
Don't use static method if you have to reuse object more that one time.
By using non static method efficiently, you don't have to query database over and over again.
//create an object that takes parameter
//from a constructor or some other public method
class Function{
public $title;
public $text;
public $footer;
function _construct($id)
{
$conn = mysql_connect("localhost", "mysql_user", "mysql_password");
if (!$conn) {
echo "Unable to connect to DB: " . mysql_error();
exit;
}
if (!mysql_select_db("mydbname", $con)) {
echo "Unable to select mydbname: " . mysql_error();
exit;
}
$sql = "SELECT * FROM table1 WHERE id=".$id." LIMIT 1";
//if you are using id, then don't forget to add limit 1
$result = mysql_query($sql);
if (!$result) {
echo "Could not successfully run query ($sql) from DB: " . mysql_error();
exit;
}
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print so am exiting";
exit;
}
$row = mysql_fetch_assoc($result);
//alternatively you can add loop check it at php manual
$this->title = $row['title'];
$this->text = $row['text'];
$this->footer = $row['footer'];
}
}
And in you layout(or view) file
//the first thing you need to do is instantiate an object
//don't use static method if you are reusing object again
<?php
$function = new Function($id);
//pass some id or other parameter
?>
<html>
...
<title>
<?= $function->title; ?>
<!-- alternatively you can do with some method also -->
</title>
....
<body>
....
<?= $function->text; ?>
</body>
</html>
And I might not be understanding your necessity, you can comment, and please review your question.
You can do this with AJAX and jQuery. jQuery, so that it'll be much easier.
jQuery
$.post("fetchstuff.php", function(data){
document.title = data.title;
$("#txt1").html(data.sometext);
});
fetchstuff.php
<?php
$sometext = "sometext";
$title = "sometitle"
?>
Totally untested but output should look like this.
<title>sometitle</title>
....
<div id="txt1">sometext</div>
Related
So I'm working on a website where I need to pull data from a MySQL server and show it on a webpage. I wrote a simple PHP script to read data from the database depending upon an argument passed in the URL and it works just fine.
Here is the script:
<?php
function updator($item)
{
$servername = "localhost";
$username = "yaddvirus";
$password = "password";
$dbname = "database";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";
$table = "inventory";
//$item = "Rose Almonds";
$sql = "SELECT * FROM $table WHERE item = '$item'";
$result = $conn->query($sql);
while($data=$result->fetch_assoc()){
echo "<h1>{$data['item']}</h1><br>";
echo "<h1>{$data['item_desc']}</h1><br>";
echo "<h1>{$data['price125']}</h1><br>";
echo "<h1>{$data['price250']}</h1><br>";
}
//echo "0 results";
$conn->close();
}
if (defined('STDIN')) {
$item = $argv[1];
} else {
$item = $_GET['item'];
}
//$item = "Cherry";
updator($item);
?>
This script works exactly as expected. I call it using http://nutsnboltz.com/tester.php?item=itemname and it pulls and shows the data just fine.
P.S You can test it out by using Cherry or Blueberry as items.
The problem is, when I'm trying to put this data in my productpage.php file, I can't get the data to show up. Here's how the file hierarchy goes:
<php
*Exact same php script as above*
?>
<html>
<head>
Header and navbar come here
</head>
<body>
<div class="container-fluid">
<div class="row">
<div class="col-4">
<h1> RANDOM TEXT BEFORE </h1>
<?php
while($data=$result->fetch_assoc()){
echo "<h1>{$data['item']}</h1><br>";
echo "<h1>{$data['item_desc']}</h1><br>";
echo "<h1>{$data['price125']}</h1><br>";
echo "<h1>{$data['price250']}</h1><br>";
}
?>
</div>
<div class="col-8">
<H!> MORE RANDOM TEXT</h1>
</div>
</div>
</div>
</body>
<footer>
footer here
scripts etc
</footer>
</html>
So the script above the footer prints everything just fine. However, down where the HTML is, nothing is printed after the PHP code. It only shows my Navbar and the H1 tag saying "RANDOM TEXT BEFORE" and that's about it. My footer is gone along with everything else.
What exactly is the issue here and how do I fix this?
The problem seems to be that you're declaring $result inside the updator function, so it's not available when you're attempting to call it later.
The best thing to do might be to return $result from the function and assign that to a variable - something like this:
function updator($item)
{
// ... some code ...
$sql = "SELECT * FROM $table WHERE item = '$item'";
$result = $conn->query($sql);
// ... some more code ...
return $result;
}
<-- HTML CODE HERE -->
<?php
$item = !empty($_GET['item']) ? $_GET['item'] : false;
// yes I know it's a bit hacky to assign the variable
// within the 'if' condition...
if($item && $result = updator($item)) {
while($data=$result->fetch_assoc()){
echo "<h1>{$data['item']}</h1><br>";
echo "<h1>{$data['item_desc']}</h1><br>";
echo "<h1>{$data['price125']}</h1><br>";
echo "<h1>{$data['price250']}</h1><br>";
}
}
?>
I'm struggling to retrieve data from a table holding basic information. I've tried to use odbc_fetch functions but I couldn't get them to work. Could someone show me how to retrieve the data from a certain row
<?php
session_start();
?>
<html>
<head>
<title>Profile</title>
</head>
<body>
<?php
$employeeNumber = $_SESSION["user"];
$connect=odbc_connect("CoveringSystem", "", "");
$getData="SELECT FirstName, LastName FROM Details WHERE EmployeeNumber ='$employeeNumber'";
$result = odbc_exec($connect, $getData);
## //I've tried to add the odbc_fetch functions here\\ ##
echo $employeeNumber;
echo $firstName;
echo $lastName;
?>
</body>
</html>
Check this with mysqli :
// First connect to database
$con = mysqli_connect("localhost","my_user","my_password","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// Than make your query
$getData=mysqli_query($con,"SELECT FirstName, LastName FROM Details WHERE EmployeeNumber ='$employeeNumber'");
//Count row returned
if(mysqli_num_rows($getData)>0){
while($row=mysqli_fetch_assoc($getData)){
$firstName=$row['FirstName'];
$lastName=$row['LastName'];
//then you can do whatever you like with your data
}
}else{
}
I'm just learning PHP and MySQL, so I'm guessing my error is really obvious.
I have a DB Table called inventory and I'm trying to pull up information on the car named Mustang. That is the name of the car under the Make column.
The problem I'm having is that my first echo statement is not ending with what should be the closing " and the following ;. It is echo'ing everything that follows it in the code, down to the ?> at the end of the file.
Here is the code itself. Note this is just a database I threw together in 10 minutes in phpmyadmin and not anything official.
<!DOCTYPE html>
<html>
<head>
<title>Realistic Autos Inventory</title>
<script>
<?php
function GetInventory($CarName)
{
$user="Uhrmacher";
$host="localhost";
$password="";
$dbname="realistic autos";
$cxn= mysqli_connect($host, $user, $password, $dbname) or die("Failure to Communicate!");
$query = "SELECT * FROM inventory WHERE Make='$CarName'";
$result = mysqli_query($cxn, $query) or die ("Failure to Query!");
$index=1;
while($row=mysqli_fetch_query($result))
{
foreach($row as $colname => $value)
{
$array_multi[$index][$colname]=$value;
}
$index++;
}
return $array_multi;
}
?>
</script>
</head>
<body>
<?php
$CarName = "Mustang";
$CarInfo = GetInventory($CarName);
echo "<h1>{$type}s</h1>\n";
echo "<table cellspacing='15'>\n";
echo "<tr><td colspan='4'><hr /></td></tr>\n";
for ($i=1; $i<=sizeof($CarInfo); $i++)
{
$f_price = number_format($CarInfo[$i]['Price'], 2);
echo "<tr>\n
<td>$i.</td>\n
<td>{$CarInfo[$i]['StockNumber']}</td>\n
<td>{$CarInfo[$i]['Year']}</td>\n
<td>{$CarInfo[$i]['Make']}</td>\n
<td>{$CarInfo[$i]['Model']}</td>\n
<td>{$CarInfo[$i]['Package']}</td>\n
<td style='text-align: right'>\$$f_price</td>\n
<td>{$CarInfo[$i]['CurrentMiles']}</td>\n
<td>{$CarInfo[$i]['Engine']}</td>\n
<td>{$CarInfo[$i]['Transmission']}</td>\n
<td>{$CarInfo[$i]['DriveType']}</td>\n
<td>{$CarInfo[$i]['VIN']}</td>\n
<td>{$CarInfo[$i]['BoughtFrom']}</td>\n
<td>{$CarInfo[$i]['BoughtHow']}</td>\n
<td>{$CarInfo[$i]['LicensingFee']}</td>\n
<td>{$CarInfo[$i]['GasMileage']}</td>\n
</tr>\n";
echo "<tr><td colspan='4'><hr /></td></tr>\n";
}
echo "</table>\n";
?>
</body>
</html>
The following is the output.
\n"; echo "
\n"; for ($i=1; $i<=sizeof($CarInfo); $i++) { $f_price = number_format($CarInfo[$i]['Price'], 2); echo "\n $i.\n {$CarInfo[$i]['StockNumber']}\n {$CarInfo[$i]['Year']}\n {$CarInfo[$i]['Make']}\n {$CarInfo[$i]['Model']}\n {$CarInfo[$i]['Package']}\n \$$f_price\n {$CarInfo[$i]['CurrentMiles']}\n {$CarInfo[$i]['Engine']}\n {$CarInfo[$i]['Transmission']}\n {$CarInfo[$i]['DriveType']}\n {$CarInfo[$i]['VIN']}\n {$CarInfo[$i]['BoughtFrom']}\n {$CarInfo[$i]['BoughtHow']}\n {$CarInfo[$i]['LicensingFee']}\n {$CarInfo[$i]['GasMileage']}\n \n"; echo "
\n"; } echo "\n"; ?>
I wasn't sure how to search this, so sorry if this is a common problem.
Get that php out of those script tags! Put it all into one nice php block. Ideally you'd do something like have a "connect.php" page just for setting up your db connection then do an but it'll work on your page you have now.
Get rid of all those "\n"s. Those arnt helping anything. You dont need to have lines in your html, your browser will understand. (i'm assuming thats why you put them in). You had a bunch of crazy stuff going on when you created your table. Maybe you need it so its formatted pretty. I took it out. Lets get basic functionality working first. Table structure goes as follows: Table-head-row definition-closingTableTag.
Edit: Also i dont know why you had characters before and but make sure those are gone. And make sure you're saving your file as .php and not .html.
Try this, get back to us.
<!DOCTYPE html>
<html>
<head>
<title>Realistic Autos Inventory</title>
</head>
<body>
<?php
$user="Uhrmacher";
$host="localhost";
$password="";
$dbname="realistic autos";
$cxn= mysqli_connect($host, $user, $password, $dbname) or die("Failure to Communicate!");
function GetInventory($CarName){
$query = "SELECT * FROM inventory WHERE Make='$CarName'";
$result = mysqli_query($cxn, $query) or die ("Failure to Query!");
$index=1;
while($row=mysqli_fetch_query($result))
{
foreach($row as $colname => $value)
{
$array_multi[$index][$colname]=$value;
}
$index++;
}
return $array_multi;
}
$CarName = "Mustang";
$CarInfo = GetInventory($CarName);
echo "<h1>{$type}s</h1>";
echo "<table>";
//table header for every column you have. You could write a for loop to simplify
echo "<tr><th></th><th></th><th></th><th></th><th></th><th></th><th></th><th></th><th></th><th></th><th></th><th></th><th></th><th></th><th></th><th></th></tr>";
for ($i=1; $i<=sizeof($CarInfo); $i++)
{
$f_price = number_format($CarInfo[$i]['Price'], 2);
echo "<tr>
<td>$i.</td>
<td>{$CarInfo[$i]['StockNumber']}</td>
<td>{$CarInfo[$i]['Year']}</td>
<td>{$CarInfo[$i]['Make']}</td>
<td>{$CarInfo[$i]['Model']}</td>
<td>{$CarInfo[$i]['Package']}</td>
<td>$f_price</td> //DONT GET FANCY YET, JUST MAKE SURE IT WORKS
<td>{$CarInfo[$i]['CurrentMiles']}</td>
<td>{$CarInfo[$i]['Engine']}</td>
<td>{$CarInfo[$i]['Transmission']}</td>
<td>{$CarInfo[$i]['DriveType']}</td>
<td>{$CarInfo[$i]['VIN']}</td>
<td>{$CarInfo[$i]['BoughtFrom']}</td>
<td>{$CarInfo[$i]['BoughtHow']}</td>
<td>{$CarInfo[$i]['LicensingFee']}</td>
<td>{$CarInfo[$i]['GasMileage']}</td>
</tr>";
}
echo "</table>";
?>
</body>
</html>
I'm trying to write a function that will allow a user to enter a name into a field, insert the field to a MySQL table and then update a dropdown menu to include those names (while allowing for further additions).
On first load of the page, the dropdown menu shows the correct names that I seeded into the table. When I input a name into the form, it inserts to the table correctly, but then none of the options show in the dropdown list and it removes my entry form. If I refresh the page, everything comes back fine, and the names previously entered show up in the list.
I know I'm missing something obvious in the code to refresh the page, but I'm not even sure what to search for. I thought that by setting my form action to .$_SERVER['PHP_SELF']. it would cause the page to process and reload. I have a hunch this is where my problem is, but I'm not sure what it is.
The dropdown code was something I found off the web, perhaps I have to rewrite it myself, though it's the one part of this mess that's actually working.
Also, the mysql login is hardcoded in db_tools.php b/c I can't get it to work otherwise.
Sorry for the following wall of text, but I'm just trying to provide the most information possible. Thank you for your replies and pointing me in the right direction.
I have 2 files, db_tools.php and dropdown.inc
db_tools.php:
<?php
require_once 'db_login.php';
require_once 'MDB2.php';
require_once("dropdown.inc");
//Define a function to perform the database insert and display the names
function insert_db($name){
//initialize db connection
//$dsn = 'mysql://$db_username:$db_password#$db_hostname/$db_database';
$dsn = "mysql://redacted";
$mdb2 =& MDB2::connect($dsn);
if (PEAR::isError($mdb2)) {
//die($mdb2->getMessage());
die($mdb2->getDebugInfo());
}
//Manipulation query
$sql = " INSERT INTO participants (id, name) VALUES (NULL, \"$name\");";
$affected =& $mdb2->exec($sql);
if (PEAR::isError($affected)){
//die($affected->getMessage());
die($affected->getDebugInfo());
}
//Display query
$query = "SELECT * FROM participants;";
$result =& $mdb2->query($query);
if (PEAR::isError($result)){
die ($result->getMessage());
}
while ($row = $result->fetchRow()){
echo $row[1] . "\n";
}
$mdb2->disconnect();
}
?>
<html>
<head>
<title>Event Bill Splitter</title>
<body>
<?php
$name = $_POST['name'];
if ($name != NULL){
insert_db($name);
}
else {
echo '
<h1>Enter a new participant</h1>
<form name="nameForm" action="'.$_SERVER['PHP_SELF'].'" method="POST">
Name:<input name="name" type="text" />
</form>';
}
?>
<p>Participants:<br />
<?php dropdown(id, name, participants, name, participant_name1); ?></p>
</body>
</head>
</html>
dropdown.inc
require_once ('db_login.php');
$connection = mysql_connect($db_host, $db_username, $db_password);
if (!$connection) {
die ("Could not connect to the database: <br />". mysql_error() );
}
$db_select = mysql_select_db($db_database);
if (!$db_select) {
die ("Could not select the database: <br />". mysql_error() );
}
function dropdown($intNameID, $strNameField, $strTableName, $strOrderField, $strNameOrdinal, $strMethod="asc") {
//
// PHP DYNAMIC DROP-DOWN BOX - HTML SELECT
//
// 2006-05, 2008-09, 2009-04 http://kimbriggs.com/computers/
echo "<select name=\"$strNameOrdinal\">\n";
echo "<option value=\"NULL\">Select Value</option>\n";
$strQuery = "select $intNameID, $strNameField
from $strTableName
order by $strOrderField $strMethod";
$rsrcResult = mysql_query($strQuery);
while($arrayRow = mysql_fetch_assoc($rsrcResult)) {
$strA = $arrayRow["$intNameID"];
$strB = $arrayRow["$strNameField"];
echo "<option value=\"$strA\">$strB</option>\n";
}
echo "</select>";
}
?>
The problem of the form disappearing is simple, just remove the else after the insert section:
<body>
<?php
$name = $_POST['name'];
if ($name != NULL){
insert_db($name);
}
// else { // gone
echo '
<h1>Enter a new participant</h1>
<form name="nameForm" action="'.$_SERVER['PHP_SELF'].'" method="POST">
Name:<input name="name" type="text" />
</form>';
// } // gone
?>
Apart from that I would definitely re-write the dropdown code and add some security, a whitelist for table names, etc.
By the way, you are calling your function in a strange way:
<?php dropdown(id, name, participants, name, participant_name1); ?>
I assume these are variables so it should be $id etc, but where do they come from? If you mean to send values directly, it should be:
<?php dropdown('id', 'name', 'participants', 'name', 'participant_name1'); ?>
Here's my function:
function get_fname($un){
$registerquery = $this->conn->query("SELECT f_name FROM tz_members WHERE
usr='".$un."'");
while ($row = $registerquery->fetch_assoc()) {
return $fname = $row[$un];
}
}
Edit:
I chose to answer my own question because it has an editor.
#Mark Baker:
<?php
require_once 'Mysql.php';
$mysql = new Mysql();
?>
<html>
<head>
</head>
<body>
<h4><?php echo $mysql->get_fname("joann"); ?></h4>
</body>
</html>
That's how I am doing it...
It seems that your query failed. Because in that case query returns false. So try this:
$registerquery = $this->conn->query("SELECT f_name FROM tz_members WHERE
usr='".$un."'");
if ($registerquery) {
while ($row = $registerquery->fetch_assoc()) {
return $fname = $row[$un];
}
}
The failure may be caused by a syntax error in your query when $un contains characters that break the string declaration (like ' or \). You should use MySQLi::real_escape_string to escape that characters to prevent that.
Additionally, a function can only return a value once. So the while will be aborted after the first row.
$fname = $row[$un]; is assigning the value in $row[$un] to the variable $fname, then returning the result.
It's pointless doing that assignment to $fname because $fname is simply a local variable within the function.... if it's defined as global, then it's not good programming practise.
If echo $mysql->get_fname("joann") is the line where you're calling the get_fname() function, then how are you setting $mysql?
And what do you think will happen if the database query doesn't find any valid result for the query?
while ($row = fetch_assoc($registerquery)) {
return $fname = $row[$un];
}
}
Is it possible you forgot to give a table name in the connection?
$conn = new mysqli('localhost', 'root', 'password', 'ANY VALUE HERE??');