I have a date in this format: 20101101120000
I need to convert it to a timestamp with PHP.
I've been searching the PHP docs online, but can't find anything that can convert directly. Does one exist? If not, what's the most efficient way to do the conversion? Thank you for your help.
You can do this with DateTime::createFromFormat:
$d = DateTime::createFromFormat('YmdGis', '20101101120000');
$d is now a DateTime instance. You can either convert it to a timestamp with $d->getTimestamp() or use the DateTime methods on it.
Note that this requires PHP 5.3.
strtotime('20101101120000')
....
You need the function strptime.
The formats are described at strftime.
I only add to this resolved question because this may be helpful for users who stumble upon here (like I did) and are looking to get an actual datetime timestamp.
My assumption for most folks when they mention timestamp is that they're looking for a normal "YYYY-MM-DD HH:MM:SS" timestamp not a unix timestamp which you get when you use the getTimestamp() method (see accepted answer if you are indeed looking for the UNIX Timestamp).
So I will further elaborate on lonesomeday's answer (which is fully correct) for those looking to actually get a valid formated date that they can display to users or insert into their database:
$d = DateTime::createFromFormat('YmdGis', '20101101120000');
$formatedDate = $d->format('Y-m-d H:i:s'); // will return 2010-11-01 12:00:00
$formatedDate = $d->format('m-d-Y h:i A'); // will return 11-01-2010 12:00 PM
Related
I need to convert a specific date format into local time (Europe/Sarajevo), I have the time in this format 2013-02-17T15:00:00Z which I don't really understand and this is why I don't know how to convert it to the Europe/Sarajevo time, who knows maybe it is already Sarajevo time, I don't know...
OK I can parse it and remove the T and Z and get a time but these letters mean something, probably they affect the result time...
The result time is for example 2013-02-17 18:00:00, probably there will be a difference due to the letters T and Z which are probably time offset.
Use DateTime. It's much better for working with timezones:
$datetime = new DateTime('2013-02-17T15:00:00Z');
$datetime->setTimeZone(new DateTimeZone('Europe/Sarajevo'));
echo $datetime->format('c');
Reference
DateTime
DateTimeZone
See it in action
You can use php date function like this
$date = '2013-02-17T15:00:00Z';
echo date('Y-m-d H:i:s',strtotime($date));
See the Manual
i am trying to format a datetime which comes fromt he database in the format of
2012-06-11 21:39:54
However i want it to display in the format of June 11
How can do this?
Thanks
echo date('M d', strtotime('2012-06-11 21:39:54'));
Output
You can also use DateTime object.
$date = new DateTime($yourString);
$date->format($yourFOrmat);
I think that it would be the best way because DateTime is really more powerful than timestamp and date/strtotime functions.
From the code I gave above you can add functionalities like modifying dates, iterate over the time, compare 2 dates without functions like str_to_time...
$date->modify('+1 day');//the day after for example
foreach(new DatePeriod($date,new DateInterval('PT1M'),10){
$date->format($yourFormat);//iterate each minute
}
and so on
PHP manual gives an excellent documentation about using Date/Time functions. Basically you will need a combination of two functions: strtotime() and date().
strtotime() will convert your date into Unix timestamp which can be supplied to date() as second argument.
The format of date you will need is: M d.
Alternative: In addition you could also try the MYSQL counterpart which won't require conversion to UNIX timestamp. It is documented here. Assuming you are using date as your Datetime field, you will need something like this,
SELECT id,..,DATE_FORMAT(`date`, '%M %d') as f_date FROM table
For formatting date using php, you need to pass timestamp of date
and format specifiers as arguments into date function .
Eg echo date('M d',strtotime('2012-06-11 21:39:54'));
I want to input a timestamp in below format to the database.
yyyy-mm-dd hh:mm:ss
How can I get in above format?
When I use
$date = new Zend_Date();
it returns month dd, yyyy hh:mm:ss PM
I also use a JavaScript calender to insert a selected date and it returns in dd-mm-yyyy format
Now, I want to convert these both format into yyyy-mm-dd hh:mm:ss so can be inserted in database. Because date format not matching the database field format the date is not inserted and only filled with *00-00-00 00:00:00*
Thanks for answer
Not sure if this will help you, but try using:
// to show both date and time,
$date->get('YYYY-MM-dd HH:mm:ss');
// or, to show date only
$date->get('YYYY-MM-dd')
Technically, #stefgosselin gave the correct answer for Zend_Date, but Zend_Date is completely overkill for just getting the current time in a common format. Zend_Date is incredibly slow and cumbersome to use compared to PHP's native date related extensions. If you don't need translation or localisation in your Zend_Date output (and you apparently dont), stay away from it.
Use PHP's native date function for that, e.g.
echo date('Y-m-d H:i:s');
or DateTime procedural API
echo date_format(date_create(), 'Y-m-d H:i:s');
or DateTime Object API
$dateTime = new DateTime;
echo $dateTime->format('Y-m-d H:i:s');
Don't do the common mistake of using each and every component Zend Frameworks offers just because it offers it. There is absolutely no need to do that and in fact, if you can use a native PHP extension to achieve the same result with less or comparable effort, you are better off with the native solution.
Also, if you are going to save a date in your database, did you use any of the DateTime related columns in your database? Assuming you are using MySql, you could use a Timestamp column or an ISO8601 Date column.
This is how i did it:
abstract class App_Model_ModelAbstract extends Zend_Db_Table_Abstract
{
const DATE_FORMAT = 'yyyy-MM-dd';
public static function formatDate($date, $format = App_Model_ModelAbstract::DATE_FORMAT)
{
if (!$date instanceof Zend_Date && Zend_Date::isDate($date)) {
$date = new Zend_Date($date);
}
if ($date instanceof Zend_Date) {
return $date->get($format);
}
return $date;
}
}
this way you don't need to be concerned with whether or not its actually an instance of zend date, you can pass in a string or anything else that is a date.
a simple way to use Zend Date is to make specific function in its business objects that allows to parameter this function the date format. You can find a good example to this address http://www.pylejeune.fr/framework/utiliser-les-date-avec-zend_date/
this is i did it :
Zend_Date::now->toString('dd-MM-yyyy HH:mm:ss')
output from this format is "24-03-2012 13:02:01"
and you can modified your date format
I've always use $date->__toString('YYYY-MM-dd HH-mm-ss'); method in the past but today didn't work. I was getting the default output of 'Nov 1, 2013 12:19:23 PM'
So today I used $date->get('YYYY-MM-dd HH-mm-ss'); as mentioned above. Seems to have solved my problem.
You can find more information on this on output formats here: http://framework.zend.com/manual/1.12/en/zend.date.constants.html
I display the date or the time on my website a lot and I'm thinking about writing a function to parse a PostgreSQL timestamp.
The timestamp is in the format: Y-m-d H:i:s.u. E.g. 2011-04-08 23:00:56.544.
I'm thinking about something like this:
function parse_timestamp($timestamp, $format = 'd-m-Y')
{
// parse the timestamp
return $formatted_timestamp;
}
However I am wondering whether this can also be achieved without writing a parser for it myself (with the use of some PHP function).
function parse_timestamp($timestamp, $format = 'd-m-Y')
{
return date($format, strtotime($timestamp));
}
Don't forget to set timezone before, e.g.
date_default_timezone_set('UTC');
Or in your case, I guess 'Europe/Amsterdam'.
You can always get PHP timestamp of this format Y-m-d H:i:s.u using strtotime(). Then, using date() you can export time in your own format. Both functions depend of time zone set.
strtotime is perfectly capable of parsing that time string, then just reformat it with date:
echo date('d-m-Y', strtotime('2011-04-08 23:00:56.544')); // 08-04-2011
For those using DateTime class:
DateTime::createFromFormat('Y-m-d H:i:s.u', $yourTime);
If the database isn't giving you what you want, change it. PostgreSQL can also format dates and times.
select to_char(timestamp '2011-03-04 07:04:00', 'DD-MM-YYYY');
04-03-2011
But that's risky in international contexts, like the web. Different locales expect different ordering of elements. (Does "04-03" mean 03-April or 04-March?) This expression is easier to understand, and it uses locale-specific abbreviations for the months.
select to_char(timestamp '2011-03-04 07:04:00', 'DD-Mon-YYYY');
04-Mar-2011
Take a look at the strptime function - it can parse many time formats.
To change 2009-12-09 13:32:15 to 09/12/2009
here:
echo date("d/m/Y", strtotime('2009-12-09 13:32:15'))
You can use strtotime to get the timestamp of the first date, and date to convert it to a string using the format you want.
$timestamp = strtotime('2009-12-09 13:32:15');
echo date('d/m/Y', $timestamp);
And you'll get :
09/12/2009
[edit 2012-05-19] Note that strtotime() suffers a couple of possibly important limitations:
The format of the date must be YYYY-MM-DD; it might work in some other cases, but not always !
Also, working with UNIX Timestamps, as done with date() and strtotime() means you'll only be able to work with dates between 1970 and 2038 (possibly a wider range, depending on your system -- but not and illimited one anyway)
Working with the DateTime class is often a far better alternative:
You can use either DateTime::__construct() or DateTime::createFromFormat() to create a DateTime object -- the second one is only available with PHP >= 5.3, but allows you to specify the date's format, which can prove useful,
And you can use the DateTime::format() method to convert that object to any date format you might want to work with.
Using the date() method.
print date("d/m/Y", strtotime("2009-12-09 13:32:15"));
$long_date = '2009-12-09 13:32:15';
$epoch_date = strtotime($long_date);
$short_date = date('m/d/Y', $epoch_date);
The above is not the shortest way of doing it, but having the long date as an epoch timestamp ensures that you can reuse the original long date to get other date format outputs, like if you wanted to go back and have just the time somewhere else.