php associative array key order (not sort) - php

My array:
$data = array('two' => 2, 'one' => 1, 'three' => 3);
Now, with when I iterate the array, the first value that will come up will probably be
$data['two'] // = 2 # index[0]
right?
What if I want to move the $data[1] to the position of $data[0] ?
To rephrase:
How do I make the array look like this (so that 'one' comes up at $data[0])
$data = array('one' => 1, 'two' => 2, 'three' => 3
Why do I need this?
I use code igniter, the table->generate built-in function takes an assoc array and creates a table but offers no method of arranging the columns. This is why I would like to move the columns in the source array.

Two possible solutions (without using array_splice):
1) Create a new array with the new order of the keys.
$new_keys = array('one', 'two', 'three');
$new_data = array();
foreach ($new_keys as $key) {
$new_data[$key] = $data[$key];
}
$data = $new_data;
2) Move the element one upfront, remove it from $data and copy the rest of the array.
function rearrangeData($data) {
$result['one'] = $data['one'];
unset($data['one']);
return array_merge($result, $data);
}
$data = rearrangeData($data);

Take a look at daniele centamore's comment on PHP's array_splice() function, where he provides a couple of functions for moving the elements in an non-associative array.
<?php
// $input (Array) - the array containing the element
// $index (int) - the index of the element you need to move
function moveUp($input,$index) {
$new_array = $input;
if((count($new_array)>$index) && ($index>0)){
array_splice($new_array, $index-1, 0, $input[$index]);
array_splice($new_array, $index+1, 1);
}
return $new_array;
}
function moveDown($input,$index) {
$new_array = $input;
if(count($new_array)>$index) {
array_splice($new_array, $index+2, 0, $input[$index]);
array_splice($new_array, $index, 1);
}
return $new_array;
}
$input = array("red", "green", "blue", "yellow");
$newinput = moveUp($input, 2);
// $newinput is array("red", "blue", "green", "yellow")
$input = moveDown($newinput, 1);
// $input is array("red", "green", "blue", "yellow")
?>

See ksort and uksort.
Here's a working example:
<?php
$data = array('two' => 2, 'one' => 1, 'three' => 3);
print_r($data);
ksort($data);
echo "ksort:\n";
print_r($data);
uksort($data,'cmp');
echo "uksort:\n";
print_r($data);
function cmp($a, $b)
{
$num=' one two three four five six seven eight nine ten';
$ai = stripos($num,$a);
$bi = stripos($num,$b);
if ($ai>0 && $bi>0) {
return ($ai > $bi) ? 1 : -1;
}
return strcasecmp($a, $b);
}
Output:
Array
(
[two] => 2
[one] => 1
[three] => 3
)
ksort:
Array
(
[one] => 1
[three] => 3
[two] => 2
)
uksort:
Array
(
[one] => 1
[two] => 2
[three] => 3
)
Run this:
http://codepad.org/yAK1b1IP

PHP has 13 functions for sorting arrays, by key, by value, by user-defined functions where you can specify that "one" comes before "two". There's also array_shift, array_unshift, array_push and array_pop for moving things onto or off the front or end of the array. You can build a whole new array from the existing one.

I think, you should use asort function:
$data = array('two' => 2, 'one' => 1, 'three' => 3);
$dataOrdered = $data;
asort($dataOrdered);
Run this code

Related

how to fix array_udiff while having strings inside array [duplicate]

I have an array containing rows of associative data.
$array1 = array(
array('ITEM' => 1),
array('ITEM' => 2),
array('ITEM' => 3),
);
I have a second array, also containing rows of associative data, that I would like to filter using the first array.
$array2 = array(
array('ITEM' => 2),
array('ITEM' => 3),
array('ITEM' => 1),
array('ITEM' => 4),
);
This feels like a job for array_diff(), but how can I compare the rows exclusively on the deeper ITEM values?
How can I filter the second array and get the following result?
array(3 => array('ITEM' => 4))
You can define a custom comparison function using array_udiff().
function udiffCompare($a, $b)
{
return $a['ITEM'] - $b['ITEM'];
}
$arrdiff = array_udiff($arr2, $arr1, 'udiffCompare');
print_r($arrdiff);
Output:
Array
(
[3] => Array
(
[ITEM] => 4
)
)
This uses and preserves the arrays' existing structure, which I assume you want.
I would probably iterate through the original arrays and make them 1-dimensional... something like
foreach($array1 as $aV){
$aTmp1[] = $aV['ITEM'];
}
foreach($array2 as $aV){
$aTmp2[] = $aV['ITEM'];
}
$new_array = array_diff($aTmp1,$aTmp2);
Another fun approach with a json_encode trick (can be usefull if you need to "raw" compare some complex values in the first level array) :
// Compare all values by a json_encode
$diff = array_diff(array_map('json_encode', $array1), array_map('json_encode', $array2));
// Json decode the result
$diff = array_map('json_decode', $diff);
A couple of solutions using array_filter that are less performant than the array_udiff solution for large arrays, but which are a little more straightforward and more flexible:
$array1 = [
['ITEM' => 1],
['ITEM' => 2],
['ITEM' => 3],
];
$array2 = [
['ITEM' => 2],
['ITEM' => 3],
['ITEM' => 1],
['ITEM' => 4],
];
$arrayDiff = array_filter($array2, function ($element) use ($array1) {
return !in_array($element, $array1);
});
// OR
$arrayDiff = array_filter($array2, function ($array2Element) use ($array1) {
foreach ($array1 as $array1Element) {
if ($array1Element['ITEM'] == $array2Element['ITEM']) {
return false;
}
}
return true;
});
As always with array_filter, note that array_filter preserves the keys of the original array, so if you want $arrayDiff to be zero-indexed, do $arrayDiff = array_values($arrayDiff); after the array_filter call.
you can use below code to get difference
$a1 = Array(
[0] => Array(
[ITEM] => 1
)
[1] => Array(
[ITEM] => 2
)
[2] => Array(
[ITEM] => 3
)
);
$a2 = Array(
[0] => Array(
[ITEM] => 2
)
[1] => Array(
[ITEM] => 3
)
[2] => Array(
[ITEM] => 1
)
[3] => Array(
[ITEM] => 4
));
array_diff(array_column($a1, 'ITEM'), array_column($a2, 'ITEM'));
Having the same problem but my multidimensional array has various keys unlike your "ITEM" consistently in every array.
Solved it with: $result = array_diff_assoc($array2, $array1);
Reference: PHP: array_diff_assoc
Another solution
if( json_encode($array1) == json_encode($array2) ){
...
}
Trust that the maintainers of PHP have optimized array_udiff() to outperform all other techniques which could do the same.
With respect to your scenario, you are seeking a filtering array_diff() that evaluates data within the first level's "value" (the row of data). Within the custom function, the specific column must be isolated for comparison. For a list of all native array_diff() function variations, see this answer.
To use the first array to filter the second array (and output the retained data from the second array), you must write $array2 as the first parameter and $array1 as the second parameter.
array_diff() and array_intersect() functions that leverage (contain u in their function name) expect an integer as their return value. That value is used to preliminary sort the data before actually performing the evaluations -- this is a performance optimization. There may be scenarios where if you only return 0 or 1 (not a three-way comparison), then the results may be unexpected. To ensure a stable result, always provide a comparison function that can return a negative, a positive, and a zero integer.
When comparing integer values, subtraction ($a - $b) will give reliable return values. For greater utility when comparing float values or non-numeric data, you can use the spaceship operator when your PHP version makes it available.
Codes: (Demo)
PHP7.4+ (arrow functions)
var_export(
array_udiff($array2, $array1, fn($a, $b) => $a['ITEM'] <=> $b['ITEM'])
);
PHP7+ (spaceship operator)
var_export(
array_udiff(
$array2,
$array1,
function($a, $b) {
return $a['ITEM'] <=> $b['ITEM'];
}
)
);
PHP5.3+ (anonymous functions)
var_export(
array_udiff(
$array2,
$array1,
function($a, $b) {
return $a['ITEM'] === $b['ITEM']
? 0
: ($a['ITEM'] > $b['ITEM'] ? 1 : -1);
}
)
);
Output for all version above:
array (
3 =>
array (
'ITEM' => 4,
),
)
When working with object arrays, the technique is the same; only the syntax to access a property is different from accessing an array element ($a['ITEM'] would be $a->ITEM).
For scenarios where the element being isolated from one array does not exist in the other array, you will need to coalesce both $a and $b data to the opposite fallback column because the data from the first array and the second arrays will be represented in both arguments of the callback.
Code: (Demo)
$array1 = array(
array('ITEM' => 1),
array('ITEM' => 2),
array('ITEM' => 3),
);
$array2 = array(
array('ITEMID' => 2),
array('ITEMID' => 3),
array('ITEMID' => 1),
array('ITEMID' => 4),
);
// PHP7.4+ (arrow functions)
var_export(
array_udiff(
$array2,
$array1,
fn($a, $b) => ($a['ITEM'] ?? $a['ITEMID']) <=> ($b['ITEM'] ?? $b['ITEMID'])
)
);
Compares array1 against one or more other arrays and returns the values in array1 that are not present in any of the other arrays.
//Enter your code here, enjoy!
$array1 = array("a" => "green", "red", "blue");
$array2 = array("b" => "green", "yellow", "red");
$result = array_diff($array1, $array2);
print_r($result);

PHP array_unique is not returning unique values [duplicate]

My array is :
$array= array(4,3,4,3,1,2,1);
And I'd like to output it like below:
Output = 2
(As 2 is present only once)
This is what I've tried:
$array = array(4, 3, 4, 3, 1, 2, 1);
$array1 = array(4, 3, 4, 3, 1, 2, 1);
$array_diff = array_diff($array, $array1);
*Read last section of this an for the most stable technique the avoids fringe case issues -- it is also the most verbose.
One-liner with no loops: (Demo)
var_export(array_keys(array_intersect(array_count_values($array),[1])));
The breakdown:
array_keys( // return the remaining keys from array_count_values
array_intersect( // filter the first array by second
array_count_values($array), // count number of occurrences of each value
[1] // identify the number of occurrences to keep
)
)
if you (or any future reader) wants to keep more values, replace the second parameter/array in array_intersect().
for instance:
you want to keep 1,2,and 3: array(1,2,3) or [1,2,3]
p.s. For the record, you can use array_filter() with a custom function to omit all non-1 count values, but I have used array_intersect() because the syntax is more brief and IMO easier to read.
p.s. thought I'd revisit and include a PHP7.4 technique and compare against other function-based techniques...
Code: (Demo)
$numbers = [4, 3, 4, 3, 1, 2, 1];
var_export(
array_keys(
array_intersect(
array_count_values($numbers),
[1]
)
)
);
echo "\n---\n";
var_export(
array_keys(
array_filter(
array_count_values($numbers),
function($count) {
return $count === 1;
}
)
)
);
echo "\n---\n";
// PHP7.4+
var_export(
array_keys(
array_filter(
array_count_values($numbers),
fn($count) => $count === 1
)
)
);
*For similar tasks which have values which are not guaranteed to be integers, array_count_values() will complain with "Warning: array_count_values(): Can only count string and integer values".
Even a classic loop that uses values as first level keys like #LF00's answer will suffer potential side effects due to floats and numeric values being cast as integers automatically.
This means that a more general-use solution would be: (Demo)
$result = [];
foreach ($array as $index => $value) {
foreach ($array as $i => $v) {
if ($value === $v && $index !== $i) {
continue 2; // duplicate found, stop checking this value; do not retain
}
}
$result[] = $value;
}
var_export($result);
You could use the array_count_values() php function.
For example:
$numbers = [4, 3, 4, 3, 1, 2, 1];
// build count array as key = number and value = count
$counter_numbers = array_count_values($numbers);
print_r($counter_numbers);
Output :
Array
(
[4] => 2
[3] => 2
[1] => 2
[2] => 1
)
Then loop through the new array to get non-repeated values :
$unique_numbers = [];
foreach ($counter_numbers as $number => $count) {
if ($count === 1) {
$unique_numbers[] = $number;
}
}
print_r($unique_numbers);
Output :
Array
(
[0] => 2
)
You can do it like this: Count the occurrences of each element, then filter out the occurrences bigger than 1.
$array = [4, 3, 4, 3, 1, 2, 1];
foreach ($array as $v)
{
$arr[$v][] = 1; // doesn't matter if 1 is set to a different value
}
foreach($arr as $k => $v)
{
if (count($v) == 1) {
$o[] = $k;
}
}
print_r($o);
result:
Array
(
[0] => 2
)
If in your scenario there will be only one unique value you could use:
$array= array(4,3,4,3,1,2,1);
$singleValue = array_search(1, array_count_values($array));
var_dump($singleValue) // Outputs: 2

Find all array keys that has same value

Is there a simpler way to get all array keys that has same value, when the value is unknown.
The problem with array_unique is that it returns the unique array and thus it doesn't find unique values.
That is, for example, from this array:
Array (
[a]=>1000
[b]=>1
[c]=>1000
)
I want to get this
Array (
[a]=>1000
[c]=>1000
)
Another way around this is, if I could find the lonely values, and then their keys, and then use array_diff
This is what I've got so far, looks awful:
$a = array( 'a' => 1000, 'b' => 1, 'c' => 1000 );
$b = array_flip( array_count_values( $a ) );
krsort( $b );
$final = array_keys( $a, array_shift( $b ) );
Update
Using Paulo Freites' answer as a code base, I could get it working pretty easily, maintainable and easy on eyes kind of way… by using the filtering as a static class method I can get the duplicate values from an array by just calling ClassName::get_duplicates($array_to_filter)
private static $counts = null;
private static function filter_duplicates ($value) {
return self::$counts[ $value ] > 1;
}
public static function get_duplicates ($array) {
self::$counts = array_count_values( $array );
return array_filter( $array, 'ClassName::filter_duplicates' );
}
Taking advantage of closures for a more straightforward solution:
$array = array('a' => 1000, 'b' => 1, 'c' => 1000);
$counts = array_count_values($array);
$filtered = array_filter($array, function ($value) use ($counts) {
return $counts[$value] > 1;
});
var_dump($filtered);
This gave me the following:
array(2) {
["a"]=>
int(1000)
["c"]=>
int(1000)
}
Demo: https://eval.in/67526
That's all! :)
Update: backward-compatible solution
$array = array('a' => 1000, 'b' => 1, 'c' => 1000);
$counts = array_count_values($array);
$filtered = array_filter($array, create_function('$value',
'global $counts; return $counts[$value] > 1;'));
var_dump($filtered);
Demo: https://eval.in/68255
Your implementation has a few issues.
1) If there are 2 of value 1000 and 2 of another value, the array_flip will lose one of the sets of values.
2) If there are more than two different values, the array_keys will only find the one value that occurs most.
3) If there are no duplicates, you will still bring back one of the values.
Something like this works always and will return all duplicate values:
<?php
//the array
$a = array( 'a' => 1000, 'b' => 1, 'c' => 1000 );
//count of values
$cnt = array_count_values($a);
//a new array
$newArray = array();
//loop over existing array
foreach($a as $k=>$v){
//if the count for this value is more than 1 (meaning value has a duplicate)
if($cnt[$v] > 1){
//add to the new array
$newArray[$k] = $v;
}
}
print_r($newArray);
http://codepad.viper-7.com/fal5Yz
If you want to get the duplicates in an array try this:
array_unique(array_diff_assoc($array1, array_unique($array1)))
I found this from:
http://www.php.net/manual/en/function.array-unique.php#95203
at the moment I cant figure out another solution...
// target array
$your_array = array('a'=>1000, 'b'=>1, 'c'=>1000);
// function to do all the job
function get_duplicate_elements($array) {
$res = array();
$counts = array_count_values($array);
foreach ($counts as $id=>$count) {
if ($count > 1) {
$r = array();
$keys = array_keys($array, $id);
foreach ($keys as $k) $r[$k] = $id;
$res[] = $r;
}
}
return sizeof($res) > 0 ? $res : false;
}
// test it
print_r(get_duplicate_elements($your_array));
output:
Array
(
[0] => Array
(
[a] => 1000
[c] => 1000
)
)
example #2: - when you have different values multiplied
// target array
$your_array = array('a'=>1000, 'b'=>1, 'c'=>1000, 'd'=>500, 'e'=>1);
// output
print_r(get_duplicate_elements($your_array));
output:
Array
(
[0] => Array
(
[a] => 1000
[c] => 1000
)
[1] => Array
(
[b] => 1
[e] => 1
)
)
if function result has been assigned to $res variable $res[0] gets an array of all elements from original array with first value found more than once, $res[1] gets array of elements with another duplicated-value, etc... function returns false if nothing duplicate has been found in argument-array.
Try this
$a = array( 'a' => 1, 'b' => 1000, 'c' => 1000,'d'=>'duplicate','e'=>'duplicate','f'=>'ok','g'=>'ok' );
$b = array_map("unserialize", array_unique(array_map("serialize", $a)));
$c = array_diff_key($a, $b);
$array = array("1"=>"A","2"=>"A","3"=>"A","4"=>"B","5"=>"B","6"=>"B");
$val = array_unique(array_values($array));
foreach ($val As $v){
$dat[$v] = array_keys($array,$v);
}
print_r($dat);

Two arrays to one

I have two arrays and I want one, can I add array 2 to array one?
$array1 = array("Germany" => 2, "Belgium"=> 3);
$array2 = array("France" => 4, "Italy"=> 5);
$final_array = {both arrays in one};
is this possible?
Yes, use the array_merge function, like this:
$final_array = array_merge($array1, $array2);
print_r($final_array);
When I run the above script it'll output:
Array (
[Germany] => 2
[Belgium] => 3
[France] => 4
[Italy] => 5
)
Take a quick read here: http://www.php.net/manual/de/function.array-merge.php
Use array_merge like
$final_arr = array_merge($array1 , $array2);
print_r($final_arr);
See this LINK for more
I would like to mention that on duplicated keys array_merge() returns the value from the second array. So, if you have different values with same keys - you should write your own function.
For example:
<?php
$a = array('rund' => '2', 'group' => '3', 'kupon' => 'utre', 'tralala' => 'shtur_kupon');
$b = array('grund' => '2', 'group' => 'ww', 'soup' => '1', 'tralala' => 'fd');
function two_arrays_merge_all_values(array $a, array $b) {
foreach ($b as $b_key => $b_value) {
$a_last_index = count($a);
$current_index = 1;
foreach ($a as $a_key => $a_value) {
if ($a_key === $b_key) {
$unique = uniqid();
$a[$b_key . '_' . $unique] = $b[$b_key];
unset($b[$b_key]);
break;
}
if ($current_index == $a_last_index) {
$a[$b_key] = $b[$b_key];
unset($b[$b_key]);
}
$current_index++;
}
}
return $a;
}

Merge two 2d arrays grouping on one column value and summing another column value within each group

Basically I need to take two arrays, merge them with unique values and sum one of columns. It makes more sense when written out below:
$a = [
['ID' => 1, 'Count' => 2],
];
$b = [
['ID' => 1, 'Count' => 4],
['ID' => 2, 'Count' => 3]
];
and I need the final product to be:
$a_plus_b = [
['ID' => 1, 'Count' => 6],
['ID' => 2, 'Count' => 3]
];
I have been playing with different variations of array_merge() and array_unique(), but I can't find an efficient way to do what I need. I know I can always do nested loops, but I was hoping for something easier. Any ideas?
This should do the trick
Note: This solution requires PHP >= 5.3. There is a PHP < 5.3 solution below.
$input = array($a, $b);
// add as many result arrays to $input as you want; e.g.,
// $input = array($a, $b, $c, $d);
$output = array_count_values(
call_user_func_array(
'array_merge',
array_map(
function($arr) {
return array_fill(0, $arr['Count'], $arr['ID']);
},
call_user_func_array(
'array_merge',
$input
)
)
)
);
print_r($output);
Output
Array
(
[1] => 6
[2] => 3
)
Note the array keys above are ID values. The array values are Count values.
If you're running PHP < 5.2 you won't be able to use the inline closure with array_fill. You have to define it as a separate function.
$input = array($a, $b);
function _fill($arr) {
return array_fill(0, $arr['Count'], $arr['ID']);
}
$output = array_count_values(
call_user_func_array(
'array_merge',
array_map(
'_fill',
call_user_func_array(
'array_merge',
$input
)
)
)
);
print_r($output);
From here, converting the output to your desired format is a trivial task.
Please don't over-engineer such a basic task. Iterate both array with a single loop and assign temporary keys using ID values. If encountering a respective ID key more than once, just add the new Count value to the stored value.
Code: (Demo)
$result = [];
foreach (array_merge($a, $b) as $row) {
if (!isset($result[$row['ID']])) {
$result[$row['ID']] = $row;
} else {
$result[$row['ID']]['Count'] += $row['Count'];
}
}
var_export(array_values($result));
Output:
array (
0 =>
array (
'ID' => 1,
'Count' => 6,
),
1 =>
array (
'ID' => 2,
'Count' => 3,
),
)
Functional programming can be used as well to achieve the same result -- array_reduce() is ideal since the number of elements in the output will be equal to or less than the number of elements in the input data.
Code: (Demo)
var_export(
array_values(
array_reduce(
array_merge($a, $b),
function ($result, $row) {
if (!isset($result[$row['ID']])) {
$result[$row['ID']] = $row;
} else {
$result[$row['ID']]['Count'] += $row['Count'];
}
return $result;
},
[]
)
)
);
If the ID values in the first array are guaranteed to be unique, you can avoid the array_merge() call by porting the $a array to the result array and assigning temporary keys using the ID values. (Demo)
$result = array_column($a, null, 'ID');
foreach ($b as $row) {
if (!isset($result[$row['ID']])) {
$result[$row['ID']] = $row;
} else {
$result[$row['ID']]['Count'] += $row['Count'];
}
}
var_export(array_values($result));

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