Is it possible to have PHP format currency values, for example: $200 will output as: $200 (without decimals) but with a number like $200.50 it will correctly output $200.50 instead of $200.5?
Thanks! :)
$num_decimals = (intval($amt) == $amt) ? 0 :2;
print ("$".number_format($amt,$num_decimals);
If you don't mind handling the currency on your own, you can simply use the following on the number, to get the correct output.
This solution will always output trailing zeros (xx.x0 or xx.00 depending on the provided number)
$number = 1234
sprintf("%0.2f",$number);
// 1234.00
How about a custom function to handle the situation accordingly:
function my_number_format($number) {
if(strpos($number, '.')) {
return number_format($number, 2);
} else {
return $number;
}
}
you can use number_format to do this.
Example:
$Amount = 200.00;
echo "$" . number_format($Amount); //$200
There are a couple of ways. Probably the most universally supported and recommended method is sprintf.
sprintf("%01.2f", "200.5"); //200.50
sprintf("%01.2f", "10"); //10.00
number_format is good as well, and has all sorts of options, and it will add thousands separators and such if requested to do so.
There's also a money_format function, but it is unsupported on Windows servers.
Related
I'm trying to format numbers with not decimal points or commas, I've tried number_format() and money_format() and can't seem to get the result I need.
number_format($item->amount,2)
Result: 14,995.00
money_format("%i", $item->amount)
Result: 14,995.00
I'm want to get the following numbers formatted correct.
14995 needs to be £149.95
6795 needs to be £67.95
What is the best way to get the result above?
Using brick/money (disclaimer: I'm the author):
use Brick\Money\Money;
// Instantiating from a decimal amount
$money = Money::of('67.95', 'GBP');
echo $money->formatTo('en_GB'); // £67.95
// Instantiating from a minor amount (cents)
$money = Money::ofMinor(6795, 'GBP');
echo $money->formatTo('en_GB'); // £67.95
setlocale(LC_MONETARY, 'en_GB.UTF-8'); // change if needed
echo money_format('%n', 6795 / 100);
returns
£67.95
for me, so that should work. As i mentioned in my comment, you probably can't get the code to both display 14995 as 1,499.50 (divide by 10) and 6795 as 67.95 (divide by 100), so I'd recommend refactoring the code accordingly.
I have a code where I got some numbers like this:
92.682926829268
I'd like to cut them like this:
92.68
This is my code:
<td><?php if (($row['TotalMatch']) > 10){ echo ($row['OK_05'] / $row['TotalMatch']) * 100; } ?></td>
I tried with floor and round but I get that example I showed at the beginning of post ( 92.682926829268 instead of 92.68 )
Thanks for your attention
Regards!
EDIT Could you give me an example with my code? Thanks
Use sprintf() to format the number.
echo sprintf("%.2f", 92.682926829268);
Example:
https://3v4l.org/U87T9
The expression you're trying to format is this:
($row['OK_05'] / $row['TotalMatch']) * 100
So whichever function you decide to use needs to go around that expression.
As to which function to use, you need to select one that returns a string, not a float.
If you use round, and your expression returns a float that rounds to a number with two zeros after the decimal point, the trailing zeros will not be displayed in the result. For example, echo round(92.0006829268, 2) will display 92, not 92.00. So don't use round if you need to be sure that two decimal places are always displayed. round is a math function, not a formatting function.
floor is really not useful at all here, as it returns a number with no decimal places.
A simple way is to use sprintf as shown in some of the other answers.
echo sprintf("%.2f", ($row['OK_05'] / $row['TotalMatch']) * 100);
The first argument to sprintf is "%.2f", which is a format string indicating that the second argument should be displayed as a float with two decimal places. The second argument is your expression.
Using bcdiv as suggested in the other answer will also work, but it works a little differently that sprintf and will produce a slightly different result in some cases.
sprintf will round to the number of decimal places specified, so for example
echo sprintf("%.2f", 926.89 / 10); // outputs 92.69
and bcdiv will truncate instead, so
echo bcdiv(926.89, 10, 2); // outputs 92.68
Whichever one of those works for you, do that.
You can use the round function
$var = 92.682926829268;
$var = round($var, 2)
Or use sprintf (%.2f cuts the number)
$var = sprintf("%.2f", $var);
Try using sprintf like below:
<?php
$mynumber = 98.343434;
echo sprintf('%.2f', $mynumber); // this will output 98.34
You could use bcdiv()
bcdiv($row['OK_05'], ($row['TotalMatch'] * 100), 2);
If I have, say, 8.1 saved as a string/plaintext, how can I change that into the integer (that I can do addition with) 81? (I've got to remove the period and change it into an integer. I can't seem to figure it out even though I know it should be simple. Everything I try simply outputs 1.)
You can also try this
$str = '8.1';
$int = filter_var($str, FILTER_SANITIZE_NUMBER_INT);
echo $int; // 81
echo $int+1; // 82
DEMO.
If you're dealing with whole numbers (as you said), you could use the intval function that is built into PHP.
http://php.net/manual/en/function.intval.php
So basically, once you have your string parsed and setup as a whole number you can do something like:
intval("81");
And get back the integer 81.
Example:
$strNum = "81";
$intNum = intval($strNum);
echo $intNum;
// "81"
echo getType($intNum);
// "integer"
Since php does auto-casting, this should work:
<?php
$str="8432.145522";
$val = str_replace('.','', $str);
print $str." : ".$val;
?>
Output:
8432.145522 : 8432145522
Not sure if this will work. But if you always have something.something,(like 1.1 or 4.2), you can multiply by 10 and do intval('string here'). But if you have something.somethingsomething or with more somethings(like 1.42 and 5.234267, etc.), I don't know what to say. Maybe a function to keep multiplying by ten until it's an integer with is_int()?
Sources:
http://php.net/manual/en/function.intval.php
http://php.net/manual/en/function.is-int.php
Convert a string to a double - is this possible?
I have a e-commerce shop and on the shopping cart page it gives me a separate price for every product, but I need total price.
in order to do that, I need to calculate all these values together and that's fine.
But, what bugs me is that I should calculate the sum of variables that are given in this format:
$455.00
What is the best way to extract the value "455" so I could add it to another value afterwards?
I hope I made myself clear...
Don't use float, but instead use an integer in cent. Floats are not precise (see Floating Point Precision), so the calculation tend to fail if you use floats. That's especially a burden if it is related to payments.
$str = '$455.00';
$r = sscanf($str, '$%d.%d', $dollar, $cent);
if ($r <> 2 or $cent > 99 or $cent < 0 or $dollar > 9999 or $dollar < 0) throw new Exception(sprintf('Invalid string "%s"', $str));
$amountInDollarCents = $dollar * 100 + $cent;
echo $str, ' -> ', $amountInDollarCents;
Demo
If you need only the dollar sign removed, use str_replace. To convert that to int or float, typecast it. However, using float results in non-exact calculations so be careful with it!
$newval = (int)str_replace('$', '', '$455.00');
I think that your ECommerce site only has $ (USD)
$price= substr($string_price,1);
This will convert your string to a float:
$price = (float)substr("$455.00", 1);
echo($price);
For more information, you can see this answer, which has a couple of good links for you in it.
What about the following:
$amount = array();
$amount[0] = '$455.15';
$amount[2] = '$85.75';
$total = 0;
foreach ($amount AS $value) {
$value = str_replace('$', '', $value);
$total += $value;
}
echo $total . "\n";
The cleaning operation is:
$value = str_replace('$', '', $value);
You might want to extract it in a function, especially if you need to use it in more than one place.
Another thing to think about is, why do you have the value in such way? It's a display format and such conversion should be the last to be done, ideally by the template. Maybe, if possible, you should consider to fix the code before, instead of applying a patch like this one.
It really looks like your program is doing it wrong. You should really represent all prices as (double) instead of a string. Then only when you need to show the price to the user you would prepend the $ sign to it, converting it to a string. But your program should really treat prices as numbers and not strings.
If you storing your price in the database as a string "$5.99" then you are really doing it wrong.
It's been a long time since I worked with PHP, so I don't know what the best practice would be for working with currency. One quick method would be to remove "$" and ".", and just add together the resulting as integers.
use str_replace() for instance, and replace "$" and "." with an empty string: http://se2.php.net/manual/en/function.str-replace.php
This will give you the whole sum in cents (thus avoiding some potential rounding problems). You can then divide it by 100 and format it however you like to display the sum as dollars.
How do I output a value as a number in php? I suspect I have a php value but it is outputting as text and not as a number.
Thanks
Here is the code - Updated for David from question below
<?php
if (preg_match('/\-(\d+)\.asp$/', $pagename1, $a))
{
$pageNumber = $a[1];}
else
{ // failed to match number from URL}
}
?>
If I call it in: This code it does not seem to work.
$maxRows_rs_datareviews = 10;
$pageNum_rs_datareviews = $pagename1; <<<<<------ This is where I want to use it.
if (isset($_GET['pageNum_rs_datareviews'])) {
$pageNum_rs_datareviews = $_GET['pageNum_rs_datareviews'];
}
If I make page name a static number like 3 the code works, if I use $pagename1 it does not, this gives me the idea $pagename1 is not seen as a number?
My stupidity!!!! - I used $pagename1 instead of pageNumber
What kind of number? An integer, decimal, float, something else?
Probably the easiest method is to use printf(), eg
printf('The number %d is an integer', $number);
printf('The number %0.2f has two decimal places', $number);
This might be blindingly obvious but it looks like you want to use
$pageNum_rs_datareviews = $pageNumber;
and not
$pageNum_rs_datareviews = $pagename1;
echo (int)$number; // integer 123
echo (float)$number; // float 123.45
would be the easiest
I prefer to use number_format:
echo number_format(56.30124355436,2).'%'; // 56.30%
echo number_format(56.30124355436,0).'%'; // 56%
$num = 5;
echo $num;
Any output is text, since it's output. It doesn't matter what the type of what you're outputting is, since the human eye will see it as text. It's how you actually treat is in the code is what matters.
Converting (casting) a string to a number is different. You can do stuff like:
$num = (int) $string;
$num = intval($string);
Googling php string to number should give you a beautiful array of choices.
Edit: To scrape a number from something, you can use preg_match('/\d+/', $string, $number). $number will now contain all numbers in $string.