json stringify to php - php

Question

I want to pass the key values into php page.
At php page, I will start to read value by matching ajaxcallid.
But it not working.
It gotta do with syntax/way I am passing in causing error.
parse error
invalid json: ajax call id is missing
JavaScript/AJAX:
var person = {
"Address" : "123 Anywhere St.",
"City" : "Springfield",
"PostalCode" : 99999
};
alert(person);
person= JSON.stringify(person);
alert(person);
$.ajax({
url: 'ROOT_URL/admin/ajaxtest.php',
type: "POST",
dataType: 'json',
data: {ajaxcallid: '26', jsarr: person},
timeout: 5000,
success: function(output) {
alert(output.Address);
},
});
PHP:
<?php
if (isset($_REQUEST['ajaxcallid']))
{
if($_REQUEST['ajaxcallid']==26)
{
//example, I want to read value of person.Address, person.City,
//person.PostalCode
//what is the easiest way
$phparr= json_decode($_REQUEST['jsarr']);
//do all other operation
$output= json_encode($phparr);
}
}
else
{
$output= "ajax call id is missing";
}
echo $output;
?>

Answer 1

If you are not using dataType : 'json', you might need to do stripslashes
$.post(window.data.baseUrl, {posts : JSON.stringify(posts)});
And in php:
$posts = json_decode(stripslashes($_POST['posts']));

Answer 2

This helped me:
data = json_decode($this->request->data['jsarr'], true);
in your php code for accessing the record
Hope it will help someone!

Answer 3

I'm going to take a guess and say that you SHOULDN'T stringify anything. I believe JQuery will do that for you. Namely, no person = JSON.stringify(person). Give that a try.

Answer 4

This is what your $.ajax call and the PHP side should look like:
JQuery
$.ajax({
url: "/admin/ajaxtest.php",
method: "POST",
data: {
ajaxcallid: "26",
person: JSON.stringify({
"Address" : "123 Anywhere St.",
"City" : "Springfield",
"PostalCode" : "99999"
})
}
}).done(function(data) {
if (!data) {
// generic error message here
} else if (data == 'invalid') {
alert('no ajaxcallid received');
} else {
var result = $.parseJSON(data); // if you pass back the object
alert(result.Address);
}
});
PHP
if (isset($_REQUEST['ajaxcallid'])) {
if ((int) $_REQUEST['ajaxcallid'] == 26) {
$personData = json_decode($_REQUEST['person']);
$address = $personData->Address;
$postalCode = $personData->PostalCode;
$returnData = json_encode($personData);
echo $personData;
die();
}
} else {
echo 'invalid';
die();
}

Answer 5

$data_array = json_decode($json_string);
If you want objects to be converted into associative arrays, then add true into function:
$data_array = json_decode($json_string, true);

Answer 6

I have not worked with PHP but from my experience with ASP.net following may help you.
Add contentType key to ajax settigns:
type: "POST",
contentType:'application/json',
dataType: 'json',
also I think you need to stringify whole value you are assigning to data like this:
var person = {
"Address" : "123 Anywhere St.",
"City" : "Springfield",
"PostalCode" : 99999
};
var d= {ajaxcallid: '26', jsarr: person};
var dat=JSON.stringify(d);
......
data: dat,
......