i have a textarea in a php page and and i want to save it on click of save button. but i have the insert queries in another php page. how shall i save the content without page refresh.
my immediate thought was ajax. but is it safe to transfer content through javascript or should i use session variables to carry the whole text content
help me in it.
You can use AJAX. Make sure you use a POST request as the text may be too long to be sent by GET (that is, appended to the URL in a query string).
Sessions are not a valid option. Sessions are files that exist on the server. In order to put the contents of a textarea into a session, you first have to get it to the server, so it's not a solution to the problem of getting the text to the server.
i think the ajax is the best solution,
make in your server side (php) sanity before insert to db (like mysql_real_escape_string)
Session variables are only stored on the server, so they cannot be used to transfer data from the client to the server. I you want to submit data without having the user to reload the page, ajax is the way to go.
Related
I have a text file storing one string. I anticipate that the text file will be changing frequently, so in order to keep my page up to date, I would like to use PHP (preferably) to fetch data from the text file every 20 seconds so I can explode it into an array and use the contents accordingly. The variables would also need to update every 20s.
So: on page load, the contents are fetched and displayed. But the contents of the text file may be changed thus making the page outdated while a user may already have it open.
I tried META Refresh, but the whole page refreshes in the middle of browsing and interrupts the user.
Sorry for the confusing description, it's hard to explain. :)
I've searched the web for ages and not found an answer to my question. Please remember I am using a text file and not MySQL, since I'm only storing one string.
Thanks in advance.
If you want to stay with PHP, I'm afraid a refreshing HTML Meta is the solution :
<meta http-equiv="refresh" content="10; url=http://example.com/" />
Refresh the page every X seconds, so that the file gets reloaded.
Another way could be the use of frames, however I cannot seriously recommand it to you.
However, you can load a content without reloading the whole page, using Ajax. It allows you to perform a HTTP request to the server (using a Javascript code) and place its result on the current page, using Javascript as well. You could create a PHP script "my_string_parsed.php", which reads the file, and then parses/prints its content. Then, you could call this script through an Ajax request to http://yoursite.com/my_string_parsed.php, and place its result in a specified HTML tag on your page.
W3Schools.com provides an Ajax tutorial here : http://www.w3schools.com/ajax/
A warning concerning Ajax though : an Ajax content loading must never replace the typical HTTP behavior your browser and the server have. If the string in your file is the only content on your page, then the best solution would be the refreshing meta. Ajax should only be used to refresh parts of a page. Never the whole thing.
Why not using a database instead of a file. You could also use jQuery to update your page smoothly.
I want to create a page where people can insert some text, hit enter, and the text be stored in a MySQL database. I can do this, but I want to be able to load a page, enter a password, and see a list of all the info in said database, then whenever something is added to the database, it's added to the list on the page, without me needing to refresh the page or setup some javascript code to refresh the page every five seconds.
I believe Satya has it correct in suggesting that you use Ajax in order to refresh the data without refreshing the page. You can have it request updated information from a php script which queries your database for the data you wish to display, and then sets the elements on your page accordingly.
this is probably the best way for you to implement ajax calls using javascript
http://api.jquery.com/jQuery.ajax/
Or you an simly do it with the help of setInterval() function. You can call an html code in a div using
$('#id').html("<htmlcode></htmlcode>");
Example : http://jsfiddle.net/ipsjolly/995PJ/6/
My client wants to have a 3 page form. The first page allows the user to enter data including a uploaded file. the second page confirms this data. and the third page submits the data to the database and directories.
Via post, I can keep saving the data to a hidden input fields, thats no problem. My problem is the uploaded file. how do I hold that document from page to page ? I am using Cakephp but any advice would help, thanks
You can always just create the illustion that the form is utilising three different pages. Use AJAX to accept and validate/request the user confirm their submitted data. If in this view they accept it initiate a POST to submit all that data.
You really don't need three physically different files to achieve this but you can still let it appear in three stages to keep your client happy.
You just upload the file to temp directory and keep the value in hidden variables just like other form data . If form successfully submitted then the image copy to desired location other wise delete the image
You can easily fake these 3 pages using CSS. Or even 2, as "third page" is actually a server script which has nothing to do with pages in the browser.
Just make your form, then put an event on the submit button which changes divs to whatever "confirmation page" he wants. and then actually send the form using a button on this page.
that's all
An uploaded file is always held temporarily. The server env var should tell you where it is. In Ruby's rack it is stored in the params var. So I guess there is a similar params var in php which has a hash with all the necessary information.
Since the file would be uploaded on the first step, one option is to put the file's location in a hidden input field along with the rest of the data (either there, or put it in the session). With CakePHP, if your file field looks somewhat like that:
<input type="file" name="data[User][image]" id="UserImage" />
Then you will be able to capture the location through
$location = $this->data['User']['image']['tmp_name'];
Which will correspond to something like /var/tmp/xxxxxx
On the last page, if the user confirms all the data, you just use move_uploaded_file() to put the file wherever you want on the server.
move_uploaded_file($location, '/new/location');
I have a page. The user submits the page and sends it to a PHP results page. It works fine. Now, I want the results page to link to another page, and for the elements on that page to depend on what was on the results page. I know how to pass form variables to another page, but I don't know anything about passing non-form variables.
From my searching on the web, my best guess is that I should be passing by URL. Is this correct? If so, a possible problem: the page I want the results page to pass to will have a form, and the user will go to yet another results page by clicking submit (the form data will be sent by POST). Can I send the non-form data (the old results page variable) along with the form data, if the user is going to the other page using POST?
I strongly suggest using sessions. It's not that hard to learn, php makes it VERY easy using http://php.net/session_start and the $_SESSION variable.
Advantage is that you will not have to submit a form on every click, and no information will be displayed in plain text in the URL.
There are several options. However, the easiest may be to simply pass the data on using hidden input fields.
Other options would be using the session, storing to a database between forms, or some combination therein.
If you are going to use POST to go to the next page the most simple option is to include the data you want to send along using an input type="hidden" element in your form.
You might consider using a session to pass the data along.
You can embed the non-form data into the second form as hidden fields. To make sure that it is also passed in the link, you can just add it to the URL as a query string, like:
http://..../blah.php?var1=val1&var2=val2
as long as the data you're passing can fit into a URL. Be sure to urlencode() anything you're appending to the URL.
<?php
start_session();
$_SESSION['Foo'] = 'Bar' // Add stuff here.
?>
I have a php page that has a form that asks for an e-mail. When you press the send button, it gets to another php page, which gets the form data and does its stuff. I need to then be able to go back to the old page (the one that contained the form) and give it some data so that it will be able to change itself and say "You've sent your e-mail successfully, and will not display the form.
How do I do it?
Sessions probably
http://us2.php.net/manual/en/book.session.php
You can either use sessions or cookies, to not depend on the URL cookies have always to be enabled.
Check the PHP Manual (Sessions and Cookies).
Options:
1) Set a cookie (or use a session variable, which is kind of the same thing)
2) Use a separate thank-you page. After you've processed the form, redirect to http://www.mysite.com/thankyou
3) Process the form on the same page as itself. If your form is at http://www.mysite.com/myform, then at the top of that page have a little
if ($_POST)
// process form
// display thank you
else
// display form
Good luck!
If the user is just seeing data that they've entered anyway, you can just use hidden form fields:
<input type="hidden" id="lang" name="lang" value="en" />
That way you can continue to POST new forms and pass the data down the lane. That's the easiest thing to do without having to write a single extra line of PHP code.
You could also store each section in a database and save each section as-added. That would give you the added benefit of having partial data in the case of a browser crash or whatever, depending on how many parts your form is. You could then pass just an ID to the DB table row and retrieve the data for display.