divide php mysql result left and right - php

Question

$flag=0;
if($q->num_rows > 0) :
echo '<div id="testimonial">';
while($r = $q->fetch_array(MYSQLI_ASSOC)) :
if($flag=0) :
$class=test1; $flag=1;
else :
$class=test2; $flag=0;
endif;
echo '<div class="'.$class.'">';
echo '<span class="left">';
echo '<p>'.$r['compname'].'</p>';
echo '<p>'.$r['position'].'</p>';
echo '</span>';
echo '<span class="right">';
echo '<p>'.$r['testimonial'].'</p>';
echo '</span>';
echo '</div>';
endwhile;
echo '</div>';
else :
echo '<h1>Coming Soon</h1>';
endif;
i want the result look like the picture! seems my php code doesnt work out the css class. its only showing 1 class test1 when i echoing the result. so all the result left align.

Answer 1

if($flag=0)
^ should be ==
This is easier though with:
$i = 0;
while (…) {
$class = $i++ % 2 ? 'test1' : 'test2';
}

Answer 2

You have an assignment in your if statement instead of a comparison: if($flag=0).

Answer 3

$class=test1; $flag=1;
^----^---
you're missing some quotes there too. As it stands now, you're trying to assign a constant named "test1" and "test2", which are most likely not defined, so they'll evaluate to an empty string.

Answer 4

$flag=0;
if($q->num_rows > 0) :
echo '<div id="testimonial">';
while($r = $q->fetch_array(MYSQLI_ASSOC)) :
if($flag==0) :
$class='test1'; $flag=1;
else :
$class='test2'; $flag=0;
endif;
echo '<div class="'.$class.'">';
echo '<span class="left">';
echo '<p>'.$r['compname'].'</p>';
echo '<p>'.$r['position'].'</p>';
echo '</span>';
echo '<span class="right">';
echo '<p>'.$r['testimonial'].'</p>';
echo '</span>';
echo '</div>';
endwhile;
echo '</div>';
else :
echo '<h1>Coming Soon</h1>';
endif;
This should work!