I need to compare a timestamp to a date. I would just like to compare the date portion without the time bit. I need to check whether a timestamp occurs on the day before yesterday i.e. today - 2.
Could you show me a snippet please? Thank you.
I've been reading through the PHP docs but couldn't find a very clean way of doing this. What I found was converting the timestamp to a date with a particular format and comparing it to a date which I get by doing a time delta to get the date before yesterday and converting it to a particular format. Messy.
You can arcieve this by using the function strtotime.
To round to a day I personaly like to edit the timestamp. This is a notations of seconds since epoch. One day is 86400 seconds, so if you do the following caculation:
$time = $time - ( $time % 86400 );
You can convert it back to a date again with the date function of PHP, for example:
$readableFormat = date( 'd-m-Y', $time );
There is also much on the internet about this topic.
you can use the strtotime function
<?php
$time = strtotime("5 june 2010");
$before = strtotime("-1 day",$time);
$after = strtotime("+1 day",$time);
Related
How can I check how many seconds past the current time to a time in my MySQL database?
Example: The current time right now is 2018-07-21 10:04:20, and the time in my database is 2018-07-20 21:58:40.
I want to get how many seconds past the datetime in my database to the current date time.
You can use the strtotime() to convert your Date-Time to Unixtime an time() to get actual Timestamp:
$timestamp = strtotime("2018-07-21 10:04:20"); //replace with your DB-date
$diff = time() - $timestamp ; //calculate the Difference
echo $diff; //negative number is in the future
Just turn the date into number using strtotime.
$seconds = abs(strtotime($currentDate) - strtotime($dbDate));
I put abs in case of the result is negative.
strtotime returns the difference in seconds between 01-01-1970 and the date in parameter.
How to find 1 day ago time in PHP microtime() format.
I am trying like this. But still showing the current time.
$date = date("Y-m-d H:i:s", strtotime('-1 day'));
$val = microtime($date);
http://us2.php.net/manual/en/function.microtime.php
microtime() returns the current Unix timestamp with microseconds
You can't use microtime() to get a time from the past, since the funtion only works with current date.
Wouldn't this work for you?
$date = strtotime('-1 day');
Edit: Code corrected according to u_mulder's comment.
I have wierd issues with time / date in PHP this year. Code have not changed at all and my dates are bugged.
Code is for example:
$date = strtotime($order['date']);
$dateNew = date('Y-m-d h:i A', $date);
print $dateNew;
Returns 1969-12-31 07:00 PM for some reasson, altough:
print $order['date'];
Returns 2013-01-12 18:25:43
I'm confused because I'm quite sure that my code is correct.
I dare you to solve this bugger!
The function strtotime() was made for transform English into date format.
The function expects to be given a string containing an English date format and will try to parse that format into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 UTC), relative to the timestamp given in now, or the current time if now is not supplied.
As i don't know what is really into your $order variable i will suggest 2 solutions :
Maybe you can avoid the strtotime function and replace it by date() directly like this :
$order = ['date' => '2013-01-12 18:25:43'];
$date = date($order['date']);
It works well here: http://codepad.viper-7.com/cbNA87
Or, if it's not working consider to use mktime(), it will convert the date into seconds since the epoch.
The Unix epoch is the reference point for all time stamps. PHP calculates the times from this date in seconds.
The $date should be null and your server in the east coast of the US so it's returns the epoch :)
PHP returns the date 1969-12-31 when there is not a proper date. So if you did
$date = 0;
$dateNew = date('Y-m-d', strtotime($date));
Your result would be 1969-12-31, since that is the default Unix epoch time. http://php.net/manual/en/function.time.php
Unexpected dates of "1969-12-31 07:00 PM" means something went wrong with date() .
your strototime($order['date']) is probably returning false (failing to parse it to a unix timestamp).
Try this and ensure its returning an int (not false)
var_dump($order['date'], strtotime($order['date']));
See the error state of date: http://php.net/date
See the return values of strtotime: http://php.net/strtotime
I'm displaying a due date for tasks in an m/d/y format. I'm displaying the day the task was posted in a "Posted X $name(s) ago" (eg. "Posted 6 day(s) ago").
I'm working on giving the timestamps (posted and due date) different CSS classes, depending on how many days there are from TODAY until the due date. (So the "Posted X" timestamp is less relevant, I just wanted to give a better picture.)
So far, I have the following down:
$cdate = $this->data['due'];
$today = time();
$dovi = date('m/d/Y', $today);
$difference = $cdate - $dovi;
$upcoming= floor($difference/60/60/24);
$cdate is pulling the due date from the DB, in m/d/y format. $today is telling us what today is (using the UNIX timestamp). $dovi is converting time() in to the m/d/y format. $difference is telling us the difference between today and the due date. $upcoming, in theory, should take that difference and dumb it down into a simple number.
I think that for the calculation to work, I would need to convert $cdate in to a UNIX timestamp or somehow convert both $today and $cdate into some other matching format other than m/d/y.
Does anyone have suggestions on the best way to make this work? I already have some code to run the CSS changes, the only thing I'm stuck on is this conversion/calculation issue to determine how many days from NOW (time()) the due date is. Thanks!!
Maybe something like this? Assuming $this->data['due'] is in m/d/Y format.
$this->data['due'] = '7/28/2012';
$diff = strtotime($this->data['due']) - strtotime(date('m/d/Y'));
var_dump(date('d',$diff)); // 3
You can pass any valid parameter to php's date function to have it formatted however you would like.
Its long one, but works...
$datetime = new DateTime("2012-07-22 02:03:50"); // your date in datetime type
$curr_stamp = time();
$act_stamp = mktime($datetime->format('H'), $datetime->format('i'), $datetime->format('s'), $datetime->format('n'), $datetime->format('j'), $datetime->format('Y'));
$diff=$curr_stamp-$act_stamp;
$day_diff = floor($diff / 86400);
if($day_diff < 7)
echo $day_diff." days ago";
Rather elegant and right solution (and also viable after the end of UNIX epoch).
$today = new DateTime(); // creating `today` DateTime object
$expiry = DateTime::createFromFormat('m/d/Y', $this->data['due']) // creating DateTime object from already formatted date
$difference = $today->diff($expiry); // 1st variant to calculate difference between dates
$difference = date_diff($today, $expiry); // and 2nd variant
echo $difference->format('Interval (difference) is %R% days');
Remember that UNIX epoch (timestamp) will "end" "soon" and code based on timestamps possibly will face some problems (maybe we will find the solution in future to avoid this, but ...), it is better to use DateTime class, bec. even to calculate number of years for those who are born before 1970 year can become kinda problem if you don't remember the date 1970.01.01 and trying to do it using timestamps (it is widespread database practice BTW :) ).
Never do it (timestamps) for very old dates and look to the future and DateTime will SaveOurSouls.
How can I easy convert a unix time to a weeks, days or months?
For example I got 604800 in unix time, which means thats 1 week, 3600 is 1 day etc.
I know this can be done using divisions, but I wonder if there is any ready-function for this.
From a timestamp, you can get much information using date(). For example:
$year = date('Y', $timestamp);
$dayOfYear = date('z', $timestamp);
$weekOfYear = date('W', $timestamp);
CakePHP have nice implementation of this, look at http://api13.cakephp.org/view_source/time-helper/#line-463
If you are trying to convert seconds to a week number and so on use date() function