I need a help with this script ($.ajax()) - php

Question

Ajax:
$.ajax({
url: 'process.php',
type: 'post',
data: 'loginName=' + $("#loginName").val() + 'loginPass=' + $("#loginPass").val(),
dataType: 'json',
success: function(data){
if(data.success)
{
location.href = data.redirect;
}
else
{
alert(data.message);
}
}
});
And here is process.php code:
<?
$data = array();
if($_SERVER['REQUEST_METHOD'] == 'POST'){
if($_POST['loginName'] == "test" && $_POST['loginPass'] == "test")
{
$data['redirect'] = "home.php";
$data['success'] = true;
echo json_encode($data);
}
else
{
$data['message'] = "<div id=Message>Your info is wrong...</div>";
$data['success'] = false;
echo json_encode($data);
}
}
?>
Sorry, but I'm from the Czech Republic and I don't speak english :D

Answer 1

Your data: misses a & right before loginPass=, which would lead to a garbled request. But maybe you should give jQuery an data object there anyway (it takes care of proper url encoding):
type: 'POST',
data: {loginName: $("#loginName").val(), loginPass: $("#loginPass").val()},
A second problem might be the lack of content-type in the php script. Add following on top (just to be sure this isn't why the result goes ignored):
<?php
header("Content-Type: application/json");
Another thing: You need more braces in the if statement, because && has higher precedence than the == comparison:
if(($_POST['loginName'] == "test") && ($_POST['loginPass'] == "test")) {
Since it is seemingly a PHP error, you must turn on error_reporting(E_ALL) and display_errors in the php.ini; If you still get no content returned from your URL, then add a print 'test123'; on top. And/or remove the test for REQUEST_METHOD (this adds no security anyway).