PHP mysql query judge and not echo the repeart part - php

I want to make a php search query. First, I put a sentence and explode every word get $name,Then I put $name make a query to match all the name which is exist in my database. Then echo part $row['name'][$i] has some word repeat.
for example: the sentence is :Marc Gasol is the brother of Pau Gasol and Gasol in my database, so the match words Gasol apearl 2 times. how to echo $row['name'][$i]; and get only one Gasol? thanks,
$query = mysql_query("SELECT * FROM books WHERE name like '$name[0]' OR name like '$name[1]' OR name like '$name[2]' OR name like '$name[3]' ");
$i = 0;
while($row = mysql_fetch_array($query)) {
echo $row['name'][$i];
$i++;
}

$sentence = "Marc Gasol is the brother of Pau Gasol";
$words = preg_split("/\s+/", $sentence);
//this will uniqueify your value set
$uniqueWords = array_keys(array_flip($words));
foreach($uniqueWords as $word){
$parts[] = "name like '%".mysql_real_escape_string($word)."%'";
}
$where = implode(" OR ", $parts);
$query = mysql_query("SELECT * FROM books WHERE $where ");
$i = 0;
while($row = mysql_fetch_array($query)) {
echo $row['name'][$i];
$i++;
}

You could run another quick loop through your array and remove all duplicate words before you proceed to executing your sql query that way you don't search the name twice in the first place. That should work if I am understanding what you are wanting to do.

Related

search array of words in database

I have text :
$a = I wanna eat apple , and banana .
I wanna get every words and punctuation of that sentence :
$b = explode(' ', strtolower(trim($a)));
the result of explode is array.
I have a words table on db that has fields : id, word and typewords all in lowercase. but for punctuation there are no exist in db.
I wanna search every words in db to take the type of words, so the final result that i want to get is :
words/typeofwords = I/n wanna/v eat/v apple/n ,/, and/p banana/n ./.
here's the code :
function getWord ($word){
$i = 0 ;
$query = mysql_query("SELECT typewords FROM words WHERE word = '$word' ");
while ($row = mysql_fetch_array($query)) {
$word[$i] = $row['typewords'];
$i++;
}
return $word;
}
echo $b.'/'.getWord($b);
but it doesn't work, please help me, thanks !
Try with this:
function getWord($words){
$association = array();
foreach($words as $word)
{
$query = mysql_query("SELECT typewords FROM words WHERE word = '$word' ");
if($row = mysql_fetch_array($query))
$association[$word] = $row['typewords'];
elseif(preg_match('/[\.\,\:\;\?\!]/',$word)==1)
$association[$word] = $word;
}
return $association;
}
$typewords = getWord($b);
foreach($b as $w)
echo $w.'/'.$typewords[$w];
function getWord($word){
// concat the word your searching for with the result
// http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_concat
$query = mysql_query("SELECT CONCAT(word,'/',typewords) as this_result FROM words WHERE word = '$word' ");
$row = mysql_fetch_array($query);
return $row['this_result']." "; // added a space at the end.
}
// loop through the $b array and send each to the function
foreach($b as $searchword) {
echo getWord($searchword);
}
You assume the function parameter to be an array, but it is a string.
Edit: In your function you treat $word as an array as well as a string. Decide what you want and recode your function.

How to sort the results of this code?

im creating a search feature that will allow a user to type in a question, my code will then match as many words as possible with the questions already in my MySQL database and display the top 5 results depending on the amount of words that are matched in the question.
I use a count() function which counts the number of matching words, however at the moment the results shown are displayed as the first 5 results in the database that have a 50% word match or more. I want the results to be shown as the highest match first and work its way down for every result in the database but only show the top 5.
Here is the code I have
<?php
include("config.php");
$search_term = filter_var($_GET["s"], FILTER_SANITIZE_STRING); //User enetered data
$search_term = str_replace ("?", "", $search_term); //remove any question marks from string
$search_count = str_word_count($search_term); //count words of string entered by user
$array = explode(" ", $search_term); //Seperate user enterd data
foreach ($array as $key=>$word) {
$array[$key] = " title LIKE '%".$word."%' "; //creates condition for MySQL query
}
$q = "SELECT * FROM posts WHERE " . implode(' OR ', $array); //Query to select data with word matches
$r = mysql_query($q);
$count = 0; //counter to limit results shown
while($row = mysql_fetch_assoc($r)){
$thetitle = $row['title']; //result from query
$thetitle = str_replace ("?", "", $thetitle); //remove any question marks from string
$title_array[] = $thetitle; //creating array for query results
$newarray = explode(" ", $search_term); //Seperate user enterd data again
foreach($title_array as $key => $value) {
$thenewarray = explode(" ", $value); //Seperate each result from query
$wordmatch = array_diff_key($thenewarray, array_flip($newarray));
$result = array_intersect($newarray, $wordmatch);
$matchingwords = count($result); //Count the number of matching words from
//user entered data and the database query
}
if(mysql_num_rows($r)==0)//no result found
{
echo "<div id='search-status'>No result found!</div>";
}
else //result found
{
echo "<ul>";
$title = $row['title'];
$percentage = '.5'; //percentage to take of search word count
$percent = $search_count - ($search_count * $percentage); //take percentage off word count
if ($matchingwords >= $percent){
?>
<li><a href='<?php echo $row['url']; ?>'><?php echo $title ?><i> No. matching words: <?php echo $matchingwords; ?></i></a></li>
<?php
$count++;
if ($count == 5) {break;
}
}else{
}
}
echo "</ul>";
}
?>
The image below shows the what happens when I search "How to make my own website" in the search bar. I already have several questions in the database for testing which are all similar questions and one the last entry is an exact match to the question I asked, but as its currently showing them as the first 5 mathing results, it ignores the full match.
Here is the results from that search.
I have added a bit of code which shows how many word matches there are in each question just so you can see it working a bit better. Also its a coincidence that its in ascending order, it is showing the first 5 matching results in the database.
What code do I need to add to this to arrange it so that it shows the closest match from the entire database first then the second best match, third etc...?
Either you use a nested SQL query where you can order by count or load the values to array php array first and then sort the array. Using SQL is very efficient && faster.
Multi Dimension Array Sorting
select column1, column2,..., LENGTH(titlecolumn) - LENGTH(REPLACE(titlecolumn, '$search term', '')) AS nummatchwords from posts where " . implode(' OR ', $array) order by nummatchwords;

Picking numbers in an order

I had a task to slide images from a mysql database using jquery slide and not the animation scripts. The slide is supposed to show at least the most recent ten images that was uploaded. With that I first of all wrote a random query
mysql_query("select * from tblname order by rand() limit 1);
But as expected, it picks the images at random irrespective of when it was posted and of course it wasn't the most recent ten. After some thought I now had to first run a query to get the most recent ten
mysql_query("select * from tblname order by ID limit 10);
while($row=mysql_fetch_array($sql){
$slideid=$slideid.",".$row['recordid'];
}
this of course results to a variable of this order
$var="23,22,24,34,27,78,56,87,98,55";
I tried handling it like an array but it wasn't giving any positive result, hence I had an issue of how to pick this numbers and use it for the slide
$myArr=explode(',',$var);
sort($myArr);
for($i=0;$i<count($myArr);$i++)
{
echo $myArr[$i];
}
Edit: For better efficiency use:
$myArr=explode(',',$var);
sort($myArr);
foreach ($myArr as $val)
{
echo $val;
// Or do whatever else you want with each one.
}
Edit 2: See comments below on efficiency vs for loops vs unexpected results. :)
Based on your comments I will offer my 2p into the mix
this is what I did $slideid="23,22,24,34,27,78,56,87,98,55"; $arr =
explode(',',$slideid); foreach ($arr as $val) { //lets get the
variables from the form post $rs = mysql_query("SELECT * FROM tblname
WHERE id='$val'") or die(mysql_error());
while($row=mysql_fetch_array($rs)){ echo "<img src='image/$image'>"; }
} the images are displayed one by one using jquery slide
Now I think we are wasting time dealing with exploding this variable because mysql has the nifty IN() function (possibly in other db's I don't know)
$slideid = "23,22,24,34,27,78,56,87,98,55";
$rs = mysql_query("SELECT * FROM tblname WHERE id IN({$slideid})") or die(mysql_error());
while ($row = mysql_fetch_assoc($rs))
{
echo "<img src='image/{$row['image']}' />";
}
I hope this helps
$var="23,22,24,34,27,78,56,87,98,55";
$arr = explode(',',$var);
foreach ($arr as $val) {
// work with $val
}
explode splits the string to an array
1) Explode the string into an array, splitting on the comma.
2) You didn't say whether you wanted to re-order the numbers into numerical order, or process them in the order they're already in. If the former, sort the array with sort($arr);
3) Loop over the array in sequence and do something with each number
$str = '1,2,3,4,5,6';
$arr = explode(',', $str);
foreach($arr as $num) echo $num.'<br />';
Note if there is any change of spaces after commas, a better choice would be preg_split rather than explode, as this is more dynamic.
$arr = preg_split('/, ?/', $str);
You can achieve this using php explode function
$pieces = explode(",", $var);
echo $pieces[0]; // piece1
echo $pieces1; // piece2
.
.
.
echo $pieces[n]; // piece n
I think you need to get result of order with respect to order of variable here
$slideid = "23,22,24,34,27,78,56,87,98,55";
$rs = mysql_query("SELECT * FROM tblname WHERE id IN({$slideid}) ORDER BY FIELD(id, {$slideid}) ") or die(mysql_error());
while ($row = mysql_fetch_assoc($rs))
{
echo "<img src='image/{$row['image']}' />";
}

Remove last comma or prevent it from being printed at all MySQL/PHP

I am printing a set of words that is placed in a MySQL database and I am retrieving it with PHP. I want to present it as a comma separated list, but I need it not to print or remove the last comma. How could I do this?
I did try to use rtrim, but I did not probably do it right.
This is my code as it is today:
<?php
$query0 = "SELECT LCASE(ord) FROM `keywords` ORDER BY RAND()";
$result0 = mysql_query($query0);
while($row0 = mysql_fetch_array($result0, MYSQL_ASSOC))
{
$keyword = $row0['LCASE(ord)'];
echo "$keyword, ";
?>
I did try to use rtrim, my attempt was something like this (I might be honest enough to say that I am in above my head in this ;) )
$keyword = $row0['LCASE(ord)'];
$keywordc = "$keyword, ";
$keyword- = rtrim($keywordc, ', ');
echo "$keyword-, ";
As you might imagine, this did not print much (but at least it did not leave me with a blank page...)
I would do:
$keywords = array();
while($row0 = mysql_fetch_array($result0, MYSQL_ASSOC))
{
$keywords[] = $row0['LCASE(ord)'];
}
echo implode(',', $keywords);
I usually do this by placing the results in an array first
$some_array = array();
while($row0 = mysql_fetch_array($result0, MYSQL_ASSOC)) {
$some_array[] = $row0['LCASE(ord)'];
}
then simply:
echo "My List: " . implode(', ', $some_array);
// Output looks something like:
My List: ord1, ord2, ord3, ord4
substr($string, 0, -1);
That removes the last character.

PHP - Delete last 2 characters in a loop

I have the following which produces results for me.
foreach($authArray as $key=>$value){
$query = mysql_query("SELECT * FROM table WHERE id='$value' LIMIT 1");
$author = mysql_fetch_assoc($query);
echo $author['fullname'] .', ';
}
It prints it out perfect, except on the last run it still adds the comma and space, is there a way i can strip this from the last result, so its:
name, name, name, name
Instead of the following
name, name, name, name,
Cheers
A better way of doing this would be to separate out the handling of database results from the view/output logic, and then you can sidestep the issue all together, using implode to allow PHP to join each of your authors together into a single string, split by your delimiter of a comma and a space:
// your loop {
$authors[] = $author['fullname'];
}
// your output
echo implode(', ', $authors);
Just concate the data into a string and then remove the last 2 chars using
$author['fullname'] = substr($author['fullname'], 0, -2);
Refer the manual for substr http://php.net/manual/en/function.substr.php
Instead of echoing each author out you could put them in a string and then simply use trim() to take off the trailing comma and finally echo the whole string.
this will probably work
foreach($authArray as $key=>$value){
$query = mysql_query("SELECT * FROM table WHERE id='$value' LIMIT 1");
$author = mysql_fetch_assoc($query);
//echo $author['fullname'] .', ';
}
$name_count = count($author[]);
for($x=0;$x<$name_count ;$x++){
if($x == $name_count -1){
echo $author['fullname'];
}else{
echo $author['fullname'].", ";
}
}
the idea is to detect the last array index, so that we can apply all the commas after each name except to the last one.
don't ever echo inside foreach
$var = '';
foreach($authArray as $key=>$value){
$query = mysql_query("SELECT * FROM table WHERE id='$value' LIMIT 1");
$author = mysql_fetch_assoc($query);
$var .= $author['fullname'] .', ';
}
echo trim($var,', ');

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