We are showing results in a table from a MySQL database with checkboxes inside it. How can we delete many rows simultaneously if the user ticks 5 rows and clicks the delete button?
HTML:
<form method="post">
<input type="checkbox" name="id[]" value="123" /> Element 1 <br/>
<input type="checkbox" name="id[]" value="5434" /> Element 2 <br/>
<input type="checkbox" name="id[]" value="24" /> Element 3 <br/>
<input type="checkbox" name="id[]" value="76" /> Element 4 <br/>
<input type="submit" value="delete" />
</form>
PHP:
if ( $_SERVER['REQUEST_METHOD'] == 'POST' ) {
$ids = array_walk($_POST['id'], 'intval');
mysql_query('DELETE FROM table WHERE id IN (' . implode(',', $ids) . ')');
}
P.S. I want points !
I won't give you the PHP code, but building an SQL query like this will solve your problem:
DELETE FROM foo WHERE id IN ( … );
See the manual for details.
With PDOStatement like this
$statement = "DELETE FROM table WHERE id = ?";
$conn = new PDO($dns,$user,$pass);
$conn->beginTransaction();
$query = $conn->prepare($statement);
foreach($params as $p){ //$params are your checked id's
$query->bindParam(1,$p);
if($query->execute()){
echo "ok";
}else{
$conn->rollBack();
exit("Error");
}
}
$conn->commit();
Related
I have searched everywhere and still cannot find the answer. Can anybody help?
I have a PHP form that consists of a textbox (with data that will go into column name_id) and a checkbox, that has the option to go to 5 different MySQL tables:
'table A'
'table B'
'table C'
'table D'
'table E'
People can choose which table they want, and the name_id will go to the tables selected.
How can I do this?
my Answere in different from #RandD-SexyBoy- . my sql query is different from #RandD-SexyBoy- he has used $sql = "INSERT INTO $tables[$i](nameID_column); with out VALUES (:nameID_column)
were is have used $sql->prepare("INSERT INTO ".$v." (name_id) VALUES (?)"
Here are 3 cases the user responds
case first : user may select a single table
case second : user may select multiple tables. here we must use foreach() loop and dynamic sql queries.
case third : user may not select any table in this case we must give user a message table not selected
html form :
`
<html>
<head>
</head>
<body>
<form action="" method="post">
<input type="text" name="name_id" required>
<p>select your table to add data</p>
<input type="checkbox" name="tables[]" value="tblA">Table A<br>
<input type="checkbox" name="tables[]" value="tblB">Table B<br>
<input type="checkbox" name="tables[]" value="tblC">Table C<br>
<input type="checkbox" name="tables[]" value="tblD">Table D<br>
<input type="checkbox" name="tables[]" value="tblE">Table E<br>
<input type="submit" name="submit">
</form>
</body>
</html>
`
php file :
<?php
$con = new mysqli('localhost','root','admin','demo');
if(!$con){
die("Connection ".$con->connect_error);
}
if(isset($_POST['submit'])){
$name_id = $_POST['name_id'];
$tables = $_POST['tables'];
if(!empty($tables)){
foreach($tables as $key=>$v){
$sql = $con->stmt_init();
if($sql->prepare("INSERT INTO ".$v." (name_id) VALUES (?)")){
$sql->bind_param($name_id);
$sql->execute();
echo "DATA INSERTED";
}
else
{
echo "Error".$con->error;
}
}
}
else
{
echo "You have not selected tables";
}
}
?>
So one naive approach could be, when the user submits the form, on your php side, you check which checkboxes are ticked and your condition could be something like this
if(checkbox_for_table_A) {// insert query}
if(checkbox_for_table_B) {// insert query}
if(checkbox_for_table_C) {// insert query}
if(checkbox_for_table_D) {// insert query}
if(checkbox_for_table_E) {// insert query}
This way if one checkbox is selected it will save into that table, if more than one tables are selected, it will go in that table.
Hope this helps! Ask any doubt you get in the comment section.
Adapting from sources : post checkbox value and tutorial http://www.mustbebuilt.co.uk/php/insert-update-and-delete-with-pdo/, you can use this approach :
HTML Form :
<form action="checkbox-form.php" method="post">
<input type="text" name="name_id" /><br />
Select your database: <br/>
<input type="checkbox" name="formTables[]" value="A" />Table A<br />
<input type="checkbox" name="formTables[]" value="B" />Table B<br />
<input type="checkbox" name="formTables[]" value="C" />Table C<br />
<input type="checkbox" name="formTables[]" value="D" />Table D<br />
<input type="checkbox" name="formTables[]" value="E" />Table E<br />
<input type="submit" name="formSubmit" value="Submit" />
</form>
Now the PHP script :
<?php
$pdo_connection = new PDO('mysql:host=localhost;dbname=test', 'demouser', 'demopass');
$tables = $_POST['formTables'];
if(empty($tables))
{
echo("You didn't select any tables.");
}
else
{
$N = count($tables);
echo("You selected $N table(s): ");
for($i=0; $i < $N; $i++)
{
$sql = "INSERT INTO $tables[$i](nameID_column);
$stmt = $pdo_connection->prepare($sql);
$stmt->bindParam(':nameID_column', $_POST['name_id'], PDO::PARAM_STR);
$stmt->execute();
echo("Your ID Name was inserted into table $tables[$i] ! <br /> ");
}
}
?>
how to save multiple radio button in database using php without save button value.
my code :
$user_id = $_POST['user_id'];
foreach ( $_POST as $key => $val ) {
if ($key <> 'user_id') {
$bidder_interst_insert="INSERT INTO bidder_interest_list(id, bidder_id, bidder_interest_name) VALUES ('','$user_id','$val')";
$bidder_interst_insert_result = mysql_query($bidder_interst_insert);
if (mysql_affected_rows() > 0) {
$interest_list_success = "Thank you Successfull insert your interst list.";
$_SESSION['interest_list_success_msg'] = $interest_list_success;
} else {
$insert_error = "interst list Insert Error.";
$_SESSION['insert_error_msg'] = $insert_error;
header("location:interest_list.php");
}
}
}
This code work but database extra save in save button value how to solved this problem??
foreach ( $_POST as $key => $val ){
You are directly looping the $_POST, so the SAVE button value is also saving in the database. Take the values individually instead of looping the whole $_POST, then the SAVE button value won't be saved in the database.
And moreover you are using mysql functions which are deprecated, use mysqli or PDO.
EDIT::
Just take it the same way as u took user_id ==> $variablename = $_POST['fieldname'];
EDIT:::
Let me suppose i have a form like this
<form name="form1" id="form1" method="post" action="">
<input type="checkbox" name="products[]" value="A" checked="checked" />A <br />
<input type="checkbox" name="products[]" value="B" checked="checked" />B <br />
<input type="checkbox" name="products[]" value="C" checked="checked" />C <br />
<input type="checkbox" name="products[]" value="D" checked="checked" />D <br />
<input type="checkbox" name="products[]" value="E" checked="checked" />E <br />
<input type="checkbox" name="products[]" value="F" checked="checked" />F <br />
<input type="submit" name="save" id="save" value="Save" />
</form>
then i can do it like:
<?php
if(isset($_POST['save']))
{
$products = $_POST['products'];
foreach($products as $key => $value)
{
$qry = mysql_query("INSERT INTO tbl(product) VALUES('$value')");
}
}
?>
Try this
unset($_POST['name-of-save-button']);
$data = $_POST;
foreach ( $data as $key => $val ){//your code here}
on page 1 i have a form, then on page 2 which is the processor file, i want to select records based on the checked checkboxes that were checked on page 1.
<form action="output.php" method="post">
<input type="checkbox" id="" class="" name="check_list[]" value="something" />
<input type="checkbox" id="" class="" name="check_list[]" value="something else" />
<input type="checkbox" id="" class="" name="check_list[]" value="yet another thing" />
<input type="checkbox" id="" class="" name="check_list[]" value="one more thing" />
<input type="checkbox" id="" class="" name="check_list[]" value="some name" />
<input type="checkbox" id="" class="" name="check_list[]" value="some other name" />
<input type="submit" value="Submit" name="submit">
</form>
the following foreach can display all the values of everything that was checked, but i don't know how to take it further into my sql select statement to select all the records that have a column field by that name.
foreach($_POST['check_list'] as $check) {
echo $check . '<br>';
}
lets say in a table called stuff there are these fields
id, first_title, second_title
so i want to do the following, but obviously this isn't the way to write it. this is the part i need help with.
SELECT * FROM stuff WHERE first_title = $check or second_title = $check
lets us further say that these records exist in the table...
id first_title second_title
-----------------------------------------
1 something something else
2 yet another thing one more thing
3 some name some other name
then lets say these checkboxes were checked:
<input type="checkbox" id="" class="" name="check_list[]" value="something" />
<input type="checkbox" id="" class="" name="check_list[]" value="one more thing" />
so what i want to happen is for my select statement to select record 1 and record 2 and not record 3, because "something" is in the first_title column of the first record, and "one more thing" is in the second_title of the second record, and nothing was checked that is in third record.
i hope i gave as much detail as is needed. let me know if you need further explanation.
Use the SQL IN operator to test if a column is in a list of values. Here's how to write it with MySQLI:
$in_str = implode(', ', array_map(function($title) use ($con) {
return "'" . $con->real_escape_string($title) . "'";
}, $_POST['check_list']));
$sql = "SELECT * FROM stuff WHERE first_title IN ($in_str) OR second_title IN ($in_str)";
$result = $con->query($sql);
try this dynamic where condition in your code
<?php
$arr_where = array();
foreach($_POST['check_list'] as $check) {
$arr_where[] = " first_name='$check' OR last_name='$check' ";
}
$where_text = implode("OR", $arr_where);
$sql = "SELECT * FROM stuff WHERE ".$where_text;
?>
I am trying to do eCommerce filtering on the category page. So far I can get it to work for one colour, but if the user checks more than one colour, I want it to search for the other colour too.
URL
//current
category.php?colourChoice=White
//more than one
category.php?colourChoice=White&colourChoice=Ruby+Red
I realise I need some sort of form array or an explode?
MYSQL
products
---
id sku price
1 p22 45.00
2 p33 65.00
3 p44 70.00
colours
---
id sku name
1 p22 White
2 p33 Ruby Red
3 p44 Black
HTML
<form action="form.php" method="get">
<input type="checkbox" name="colourChoice" value="White"/>
<input type="checkbox" name="colourChoice" value="Black"/>
<input type="checkbox" name="colourChoice" value="Ruby Red"/>
<input type="checkbox" name="colourChoice" value="Orange"/>
<input type="submit" value="go">
</form>
PHP
// VARS
$colourName=mysql_real_escape_string($_GET["colourChoice"]);
// MYSQL
$checkSQL=mysql_query("
SELECT * FROM `products`
INNER JOIN `colours`
ON `products`.`sku` = `colours`.`sku`
WHERE (
name = '".$colourName."'
OR name LIKE '".$colourName.";%'
OR name LIKE '%;".$colourName.";%'
OR name LIKE '%;".$colourName."'
)
");
// SHOW RESULTS
while($r = mysql_fetch_array($checkSQL)) {
echo '
<div class="product">
Cost £'.$r['price'].'<br />
</div>
';
}
You have to make checkbox array as below
<form action="form.php" method="get">
<input type="checkbox" name="colourChoice[]" value="White"/>
<input type="checkbox" name="colourChoice[]" value="Black"/>
<input type="checkbox" name="colourChoice[]" value="Ruby Red"/>
<input type="checkbox" name="colourChoice[]" value="Orange"/>
<input type="submit" value="go">
</form>
Then, you will get multiple value checked into array in php.
foreach($_GET["colourChoice"] as $value){
/// here you can make concat for where clause.
}
You can get HTML input values in PHP as array:
HTML
<form action="form.php" method="get">
<input type="checkbox" name="colourChoice[]" value="White"/>
<input type="checkbox" name="colourChoice[]" value="Black"/>
<input type="checkbox" name="colourChoice[]" value="Ruby Red"/>
<input type="checkbox" name="colourChoice[]" value="Orange"/>
<input type="submit" value="go">
</form>
Then you query the database using prepare/execute statements to prevent SQL injection.
PHP
$placeholders = substr(str_repeat('?, ', count($_GET['colourChoice']), 0, -1);
$query = "
SELECT * FROM `products`
INNER JOIN `colours`
ON `products`.`sku` = `colours`.`sku`
WHERE name in ($placeholders);
");
$db = new PDO(...);
$stmt = $db->prepare($query);
$stmt->execute($_GET['colourChoice']);
print_r($stmt->fetchAll());
I have a form with a variable number of inputs. The inputs are inside the table and I need to get three values from them: the row, the column and the actual value inside the input.
Some may be populated some may not and I need all their values to update a mysql db (row and column to know what to update, value to know the new value to insert in the database).
This is my form (an example version of it):
<form method="post" action="">
<input name="data[111][222]" value="2" />
<input name="data[112][221]" value="0" />
<input name="data[113][223]" value="4" />
//goes on
<input name="data[324][435]" value="11" />
<input name="data[325][436]" value="" />
</form>
And that's as far as I go. How can I get the data from this form so I can do a simple update in my database that goes like this (for all the affected inputs):
update table set res="value_from_input" where row="row_value" and col="col_value"
<form method="post" action="">
<input name="data[111][222]" value="2" />
<input name="data[112][221]" value="0" />
<input name="data[113][223]" value="4" />
<input name="data[324][435]" value="11" />
<input name="data[325][436]" value="" />
<input type="submit" />
</form>
<?php
foreach ($_POST['data'] as $k1 => $v1)
{
foreach ($v1 as $k2 => $v2)
{
echo "<p>k1:".$k1."; k2: ".$k2."; value: ".$v2."</p>";
$query = "update table set res='$v2' where row='$k1' and col='$k2'";
mysql_query($query);
}
}
?>
foreach($_POST['data'] as $row => $row_array)
{
foreach($row_array as $col => $value)
{
// Sanitize all input data before entry
$mysql = "UPDATE table SET res='$value' WHERE row='$row' AND col='$col'";
}
}