MySQL Query: Trying to get property of non-object - php

Question

I'm getting following error message.
Notice: Trying to get property of non-object in
C:\xampp\htdocs\my\include\user_functions.php on line 34
Here is my Code
$conn = db_connection();
if($conn == false) {
user_error('Unable to connect to database');
return false;
}
$query = "UPDATE user SET passwd = '".$new_passwd."'
WHERE username = '".$username."' ";
$result=$conn->query($query);
if($result == false) {
user_error('Query Error'.$conn->error);
return false;
}
if($result->num_rows == 1) {
echo 'Password changed';
} else {
echo 'Failed ';
}
here is my db_connection
function db_connection() {
$db = new mysqli('localhost','root','','php_login');
if(!$db) {
echo 'Could not connect to database server';
} else {
return $db;
}
}

Answer 1

The UPDATE statement doesn't return a result set. What are you trying to get from fetch_array?

Answer 2

UPDATE
class mysqli{
public $aff_num_rows;
//some properties
//some properties
//some methods
//some methods
public function query($sql)
{
$resultset = mysql_query($sql); //after query instantiate the $aff_numrows
//property with function
$this->aff_num_rows = mysql_affected_rows(); //guess you are using sqlite
//so you might have different function
//and you can use this property
}
}
And in you code you have
if($conn->aff_num_rows == 1) {
echo 'password changed';
} else {
echo 'error changing pasword';
}