Any idea how to copy: name, content from rows where language_id = 1 to rows where language_id = 2?
How should SQL command look like?
I want to achive:
http://dev.mysql.com/doc/refman/5.0/en/insert-select.html is what you need to do
assuming it is the productid that you want to update from lang1 to lang 2
update a set
a.name = b.name,
a.content = b.content
from tablea a
join tablea b on a.productid = b.productid
where a.language_id = 2
and b.language_id = 1
ofcourse this will do it for every row in the table so if you want to restrict it then make sure to restrict it by the productids
Did you mean copying all language_id=1 rows to language_id=2 ones?
My knowledge of MySQL syntax is very poor, so I dare not give you all the codez, but at least you may find the following approach useful:
Create a temp table with the structure like this:
product_id int,
name (varchar?)
content (varchar?)
That is, include product_id and all the columns you need to copy.
Populate the temp table with the language_id=1 data. Probably like this:
INSERT INTO temp_table
SELECT product_id, name, content
FROM orig_table
WHERE language_id = 1
Update those rows in the original table where language_id=2 with the corresponding data in the temp table. It may look like this:
UPDATE orig_table
SET
name = temp_table.name,
content = temp_table.content
FROM temp_table
WHERE orig_table.product_id = temp_table.product_id
AND orig_table.language_id = 2
Insert the rows from the temp table into the original table, where the products don't have language_id=2. Something like this:
INSERT INTO orig_table (product_id, language_id, name, content)
SELECT product_id, 2, name, content
FROM temp_table
WHERE NOT EXISTS (
SELECT 1 FROM orig_table
WHERE product_id = temp_table.product.id
AND language_id = 2
)
If you didn't mean to change the already existing language_id=2 data, then step #3 should be omitted and you might further want to modify step #2 in such a way that it selected language_id=1 data only for the products lacking language_id=2.
Related
I have two tables.
first datatable structure has nine columns but the important three are:
code | name | value
2D3 | name test | 0.12
the second table has the same three columns.
Now I want to update all rows of the first table with the values of table two where code AND name are the same as in table two.
So my current idea is to do a select of all rows of table 1 with the code and name columns, than check if a row with the same code and name exists in table 2, if yes get that value and do a UPDATE query in table 1 with value of table 2.
The problem is that the two tables are hugh and I am sure that I am not using the fastest method.
anyone an idea for the fastest method to do this? Thank you very much!
EDIT: the query:
$getall = "SELECT code, name, value FROM table2";
$query = mysqli_query($conn, $getall );
while($result = mysqli_fetch_array($query))
{
$UpdateAll = "UPDATE table1 SET value = '".mysqli_real_escape_string($conn,$result["value"])."' WHERE name = '".mysqli_real_escape_string($conn,$result["name"])."' AND code = '".mysqli_real_escape_string($conn,$result["code"])."'";
$result2 = mysqli_query($conn, $UpdateAll); }
You speak of two databases but really mean two tables, don't you? In this case, you can do it with one update using a join, like this:
update table1 t1
inner join table2 t2 on t2.code = t1.code and t2.name = t1.name
set t1.value = t2.value;
I have the database structure as shown in the below image:
I want to retrieve variant_id that belongs to particular product_id
Example :
lets say 1 and Size = L , Color = Green.
I expect mysql query to return variant_id = 7.
What is the expected query to be used in this scenario?
You can use following query.
I'm assuming your table name is table1
select variant_id from (select * from table1 where
product_id=1 and ((attribute_name='Size' and value='L')
or (attribute_name='Color' and value='Green'))) as temp
group by variant_id having count(*)>1
just wondering how to insert dynamic column to existing MySQL table? For example: I already have "sampletable" and I want to make input fields that can add dynamic column to the existing table, example: column1, column2, column3. How to do that with dynamic numbering?
I would agree with #Barmar that your SQL table structure is wrong if you are trying to do this. What you are trying to do in this case is what's called a "one to many" relationship. This is usually achieved by doing something like the following.
Table 1: Contains columns for all the usual data (non-"dynamic" columns in your terms), and a unique ID column which all good database tables should have
Table 2: An ID column, and column that refers to the ID column on table one and a column for the data that goes in the dynamic column.
Now you can store your values that you would normally store in "dynamic columns" in individual rows on the second table.
Example
// sample:
//
// | id | name |
//
// dynamic_values:
//
// | id | sample_id | value |
// Selecting data
SELECT * FROM sample WHERE id = 1;
SELECT * FROM dynamic_values WHERE sample_id = 1;
// Querying on "dynamic columns"
SELECT * FROM sample s LEFT JOIN dynamic_values d ON d.sample_id = s.id WHERE d.value = 'something';
Try This set of code for Dynamic Column Creation for Existing Table.
SET SQL_SAFE_UPDATES = 0;
Drop TEMPORARY table if exists Temp_Report;
CREATE TEMPORARY TABLE Temp_Report (Report_Date Date);
Drop TEMPORARY table if exists Temp_Product_Tax;
CREATE TEMPORARY TABLE Temp_Product_Tax as SELECT concat(REPLACE(Tax_category,' ','_'),'|',Taxvalue) as 'Tax_category',Taxvalue FROM tax_category c left join taxmaster t on c.id=t.catid ; -- where c.is_Product =1
select * from Temp_Product_Tax;
set Count_1=(SELECT COUNT(*) FROM Temp_Product_Tax);
set Var_1=0;
While(Count_1>Var_1) do
set #Col_Name=Concat( Var_1+1,'_',REPLACE((select Tax_category from Temp_Product_Tax limit Var_1,1),'.','_'),' Double(15,2)');
set #Col_Name=Concat('ALTER TABLE Temp_Report ADD COLUMN ', #Col_Name) ;
PREPARE stmt FROM #Col_Name;
EXECUTE stmt;
set Var_1=Var_1+1;
END While;
select * from Temp_Report;
SET SQL_SAFE_UPDATES = 1;
In fact, what you intend to do, ie, adding dynamic columns is not at all a good practice I think. Anyway
You can do that using ALTER TABLE
for($i=1;$i<4;$i++){
mysqli_query("ALTER TABLE mytable ADD COLUMN `input.$i` VARCHAR(40)",$db_con);
}
But I would suggest the same way, which is BARMER mentioned in the above comments.
How do I select a column value as a column name and group the results as a row.
I have a table as such:
id articleId label value
1 1 title Example title
2 1 description This is the description
3 1 author Me
4 2 title Example of another type of article
5 2 description Short description
6 2 author Someone else
Is it possible to select all of the rows and use the label as the column name and the value as the value of that column name and then group them by the article name.
So how I would like to have it returned:
articleId title description author
1 Example title This is the.. Me
2 Example of an.. Short descr.. Someone else
I'm using this for a CMS where the user can define the fields for an article so we don't have to customize the table's. This is why i'm not making the tables as the I would like to have it returned. I am also aware that I can just as easily convert the result to this in php.
-- edit --
Can this be done without knowing what labels are added? In this example im using title, description and author. But it could very well be something totally different like title, shortDescription, availableTo, techInformation, etc.. The idea is that the article's are customizable for the user without needing to change the database and query's
I figured I'd better post as an answer, even if not what OP would like to hear. What you are asking to do is to populate a query with a variable number of columns based on the distinct values within column label, all associated with articleID. Taking your specific example, the following would be the resultant query that I would most likely go to in this instance (though the example from #Devart is equally valid)
SELECT
t.id,
t.articleId,
t1.value AS title,
t2.value AS description,
t3.value AS author
FROM `tableName` t
LEFT JOIN `tablename` t1
ON t1.article_id = t.article_id AND t1.label = 'title'
LEFT JOIN `tablename` t2
ON t2.article_id = t.article_id AND t2.label = 'description'
LEFT JOIN `tablename` t3
ON t3.article_id = t.article_id AND t3.label = 'author'
Now expanding this to account for up to n labels, we get the following query (metacode included, this query will NOT execute verbatim)
SELECT DISTINCT label FROM `tableName`;
SELECT
t.id,
t.articleId
// for (i=1;i<= number of distinct labels) {
,t[i].value AS [value[i]]
// }
FROM `tableName` t
// for (i=1;i<= number of distinct labels) {
LEFT JOIN `tablename` t[i]
ON t[i].article_id = t.article_id AND t[i].label = [value[i]]
// }
;
So what you can do is one of the following.
SELECT t.* FROM tablename t and then have PHP process it as required
SELECT DISTINCT label FROM tablename and have PHP build the second query with the many LEFT JOINs (or MAX / GROUP BY logic if preferred)
Create a Stored Procedure to do the same as #2. This would most likely be more efficient than #2 however may be less efficient overall than #1.
You can use pivote table trick -
SELECT
articleId,
MAX(IF(label = 'title', value, NULL)) AS title,
MAX(IF(label = 'description', value, NULL)) AS description,
MAX(IF(label = 'author', value, NULL)) AS author
FROM
table
GROUP BY
articleId
Try below :
select t1.articleId,t1.title,t1.description,t1.author
from tablename as t1
left join (select max(articleId) as articleId
from tablename
group by articleId ) as t2
on t1.articleId=tsm.articleId where [.....]
I'm trying to join two tables. The first table has a list of 11 items which are 'site_names' with an auto id field of 'id'. The second table that I want to connect has an auto id field of 'desc_id' and another field of 'descriptions'. This second table currently has 3 rows of data that I want displayed only for id 1 in table 1.
So, I want to accomplish is to connect the first site in table one with an id of '1' to the entire second table.
I can't seem to figure out how connect only the first entry(id=1) in table 1 to all the rows in table 2 (tb.1->id->1 to tbl.2->desc_id->1,2,3).
I hope that made sense. Any help would be great. Thanks
Try:
select site_name, descriptions
from table_1
inner join table_2
on 1 = 1
where table_1.site_id = 1
This should join give you what you want.
OK - based on the comment, I'm guessing what you want is:
site1 | desc1 | desc2 | desc3
all on one row. This is a bit trickier - particularly if you want it to remain open to an arbitrary number of descriptions. For just 3 (or, really, any limited subset, but as the number goes up, it gets ugly), you could do:
select site_name, t2.desc, t3.desc, t4.desc
from table_1
inner join table_2 t2
on t2.desc_id = 1
inner join table_2 t3
on t3.desc_id = 2
inner join table_2 t4
on t4.desc_id = 3
where site_id = 1
This kind of stuff is highly irregular though. It seems to me like something about your schema is probably not quite right to generate this sort of requirement.
Here is the query:
<?php
$mysql = new mysqli('localhost', 'root', 'root') or die('counld not connect');
$result = $mysql->query("SELECT ajax_demo.explore.site_name, anthony1.property.descriptions FROM ajax_demo.explore INNER JOIN anthony1.property ON ajax_demo.explore.id = anthony1.property.desc_id") or die($mysql->error);
if($result)
{
while($row = $result->fetch_object())
{
$id = $row->id;
$siteName = $row->site_name;
$siteDescription = $row->site_description;
echo "$siteName";
echo "$siteDescription";
}
}
?>
I may be missing something here, but it sounds to me like you need to add a foreign key to the Site table. If I understand your question correctly, your tables should look something like this:
Site
- SiteID
- DescriptionID
- SiteName
Description
- DescriptionID
- Description
Then your query to get Sites and their associated Descriptions would look like this:
SELECT
s.SiteName,
d.Description
FROM
Site s INNER JOIN Description d
ON s.DescriptionID = d.DescriptionID
This table structure assumes that multiple Sites share single Descriptions (as per your posted question).