PHP to randomise image - php

Question

I'm loading a folder full of images in, to create a jQuery Image Gallery.
There are currently 100 images being loaded in to create the gallery. I've got all that to load without issue.
All I want to do is make the image(s) that are loaded, load in randomly.
How do I achieve this?
My code is :
<?php
$folder = "images/";
$handle = opendir($folder);
while(($file = readdir($handle)) !== false) {
if($file != "." && $file != "..")
{
echo ("<img src=\"".$folder.$file."\">");
}
}
?>
Thanks in advance.

Answer 1

Just store all the image paths in an array and do a random shuffle of the array. And then echo the elements
<?php
$folder = "images/";
$handle = opendir($folder);
$imageArr = array();
while(($file = readdir($handle)) !== false) {
if($file != "." && $file != "..")
{
$imageArr[] = $file;
}
shuffle($imageArr); // this will randomly shuffle the image paths
foreach($imageArr as $img) // now echo the image tags
{
echo ("<img src=\"".$folder.$img."\">");
}
}
?>

Answer 2

Traverse the directory and store the image file names into an array and randomly select path names from the array.
A basic example:
$dir = new DirectoryIterator($path_to_images);
$files = array();
foreach($dir as $file) {
if (!$fileinfo->isDot()) {
$files[] = $file->getPathname();
}
}//$files now stores the paths to the images.

Answer 3

You can try something like this:
<?php
$folder = "images/";
$handle = opendir($folder);
$picturesPathArray;
while(($file = readdir($handle)) !== false) {
if($file != "." && $file != "..")
$picturesPathArray[] = $folder.$file;
}
shuffle($picturesPathArray);
foreach($picturesPathArray as $path) {
echo ("<img src=\"".$path."\">");
}
?>