php preg_match image address which is bagin as letter - php

I want to get all the image address which is a letter.
I use this...
<?php
$str = <<<EOT
image/20110331_121.jpg
../image/20110330_132.jpg
http://www.site.com/image/20110330_098.jpg
EOT;
$image = preg_match('#^[a-zA-Z](.*)\/.(jpg)$#i',$str);
print_r($image);// I want get a echo image/20110331_121.jpg
?>

Your problem was the \/ right before the .jpg without any placeholder. You could try this:
$image = preg_match('#^[a-z]\w+/\w+[.](jpg)$#im',$str);
And you also forgot the #m modifier to apply ^ and $ against multiple lines.

Related

how to do echo from a string, only from values that are between a specific stretch[href tag] of the string?

[PHP]I have a variable for storing strings (a BIIGGG page source code as string), I want to echo only interesting strings (that I need to extract to use in a project, dozens of them), and they are inside the quotation marks of the tag
but I just want to capture the values that start with the letter: N (news)
[<a href="/news7044449/exclusive_news_sunday_"]
<a href="/n[ews7044449/exclusive_news_sunday_]"
that is, I think you will have to work with match using: [a href="/n]
how to do that to define that the echo will delete all the texts of the variable, showing only:
note that there are other hrefs tags with values that start with other letters, such as the letter 'P' : href="/profiles... (This does not interest me.)
$string = '</div><span class="news-hd-mark">HD</span></div><p>exclusive_news_sunday_</p><p class="metadata"><span class="bg">Czech AV<span class="mobile-hide"> - 5.4M Views</span>
- <span class="duration">7 min</span></span></p></div><script>xv.thumbs.preparenews(7044449);</script>
<div id="news_31720715" class="thumb-block "><div class="thumb-inside"><div class="thumb"><a href="/news31720715/my_sister_running_every_single_morning"><img src="https://static-hw.xnewss.com/img/lightbox/lightbox-blank.gif"';
I imagine something like this:
$removes_everything_except_values_from_the_href_tag_starting_with_the_letter_n = ('/something regex expresion I think /' or preg_match, substring?);
echo $string = str_replace($removes_everything_except_values_from_the_href_tag_starting_with_the_letter_n,'',$string);
expected output: /news7044449/exclusive_news_sunday_
NOTE: it is not essential to be through a variable, it can be from a .txt file the place where the extracts will be extracted, and not necessarily a variable.
thanks.
I believe this will help her.
<?php
$source = file_get_contents("code.html");
preg_match_all("/<a href=\"(\/n(?:.+?))\"[^>]*>/", $source, $results);
var_export( end($results) );
Step by Step Regex:
Regex Demo
Regex Debugger
To get just the links out of the $results array from Valdeir's answer:
foreach ($results as $r) {
echo $r;
// alt: to display them with an HTML break tag after each one
echo $r."<br>\n";
}

Regex to select url except when = is directly infront of it

I'm trying to use a regex to find and replace all URLs in a forum system. This works but it also selects anything that is within bbcode. This shouldn't be happening.
My code is as follows:
<?php
function make_links_clickable($text){
return preg_replace('!(([^=](f|ht)tp(s)?://)[-a-zA-Zа-яА-Я()0-9#:%_+.~#?&;//=]+)!i', '$1', $text);
}
//$text = "https://www.mcgamerzone.com<br>http://www.mcgamerzone.com/help/support<br>Just text<br>http://www.google.com/<br><b>More text</b>";
$text = "#Theareak We know this and [b][url=https://www.mcgamerzone.com/news/67/False-positive-proxy-bans-and-bot-attacks]here[/url] [/b]is an explanation, we are trying to fix this asap! https://www.mcgamerzone.com/news/67/False-positive-proxy-bans-and-bot-attacks aaa";
echo "<b>Unparsed text:</b><br>";
echo $text;
echo "<br><br>";
echo "<b>Parsed text:</b><br>";
echo make_links_clickable($text);
?>
All urls that occur in bb-code are following up on a = character, meaning that I don't want anything that starts with = to be selected.
I basically have that working but this results in selecting 1 extra character in in front of the string that should be selected.
I'm not very familiar with regex. The final output of my code is this:
<b>Unparsed text:</b><br>
#Theareak We know this and [b][url=https://www.mcgamerzone.com/news/67/False-positive-proxy-bans-and-bot-attacks]here[/url] [/b]is an explanation, we are trying to fix this asap! https://www.mcgamerzone.com/news/67/False-positive-proxy-bans-and-bot-attacks aaa<br>
<br>
<b>Parsed text:</b><br>
#Theareak We know this and [b][url=https://www.mcgamerzone.com/news/67/False-positive-proxy-bans-and-bot-attacks]here[/url] [/b]is an explanation, we are trying to fix this asap! https://www.mcgamerzone.com/news/67/False-positive-proxy-bans-and-bot-attacks aaa
You can match and skip [url=...] like this:
\[url=[^\]]*](*SKIP)(?!)|(((f|ht)tps?://)[-a-zA-Zа-яёЁА-Я()0-9#:%_+.\~#?&;/=]+)
See regex demo
That way, you will only match the URLs outside the [url=...] tag.
IDEONE demo:
function make_links_clickable($text){
return preg_replace('~\[url=[^\]]*](*SKIP)(?!)|(((f|ht)tps?://)[-a-zA-Zа-яёЁА-Я()0-9#:%_+.\~#?&;/=]+)~iu', '$1', $text);
}
$text = "#Theareak We know this and [b][url=https://www.mcgamerzone.com/news/67/False-positive-proxy-bans-and-bot-attacks]here[/url] [/b]is an explanation, we are trying to fix this asap! https://www.mcgamerzone.com/news/67/False-positive-proxy-bans-and-bot-attacks aaa";
echo "<b>Parsed text:</b><br>";
echo make_links_clickable($text);
You can use a negative lookbehind (?<!=) instead of your negated class. It asserts that what is going to be matched isn't preceded by something.
Example

Text between less than and greater than not output PHP

i use (str_replace) function to replace ##ID## in youtube url with this regular expression : (?P<id>[a-z-A-Z_0-9]+)
so i use this code to do this :
<?php
$urlbase = 'https://www.youtube.com/watch?v=##ID##';
$lastchange = str_replace('##ID##', '(<id>[a-z-A-Z_0-9]+)', $urlbase);
echo $lastchange;
?>
i get the output in the browser like this : https://www.youtube.com/watch?v=(?P[a-z-A-Z_0-9]+), its looks like <id> not show up !
i try this simple code :
<?php
echo "This is my <id>";
?>
but i just get this is my in the browser !
What's the probleme ? and how i can fix it , thanks
is being interpreted as HTML so your browser is parsing it and since it is not a renderable element, it shows nothing. Try:
<?php
echo "This is my <id>
?>
As for the str_replace, it's doing exactly what the function is supposed to be doing. If you're looking to use regular expressions in string replacements, use preg_replace
The tag <id> is being removed by your browser. It is really there if you watch the source code. Maybe you should try:
$urlbase = 'https://www.youtube.com/watch?v=##ID##';
$lastchange = str_replace('##ID##', '(<id>[a-z-A-Z_0-9]+)', $urlbase);
echo urlencode( $lastchange );
Problem is with the line:
$lastchange = str_replace('##ID##', '(<id>[a-z-A-Z_0-9]+)', $urlbase);
str_replace does not use regex.
You will need preg_replace
$pattern = '(<id>[a-z-A-Z_0-9]+)'
$replacement = '##ID##'
$string = $urlbase
$lastchange = preg_replace($pattern, $replacement, $string);
Also < and > are html entities which means they are reserved chars for HTML they have some special meanings if you want to show them then you must use there entity name eg < and > in your case respectively.
<?php
echo " echo "This is my <id>";
?>

Replace url strings in PHP

I have a string for example : I am a boy
I want to show this on my url for example in this way : index.php?string=I-am-a-boy
My program :
$title = "I am a boy";
$number_wrds = str_word_count($title);
if($number_wrds > 1){
$url = str_replace(' ','-',$title);
}else{
$url = $title;
}
What if I have a string : Destination - Silicon Valley
If I implement the same logic my url will be : index.php?string=Destination---Silicon-Valley
But I want to show only 1 hyphen.
I want to show a hyphen instead of a plus sign..
url_encode() will eventually insert plus symbols.. So it's not helping here.
Now if I use minus symbol then if the actual string is Destination - Silicon Valley, then the url will look like
Destination-Silicon-Valley and not
Destination---Silicon-Valley
Check this stackoverflow question title and the url. You will know what I am saying.
Check this
Use urlencode() to send strings along with an url:
$url = 'http://your.server.com/?string=' . urlencode($string);
In comments you told, that you don't want urlencode, you'll just replace spaces by - characters.
First, you should "just do it", the if conditional and str_word_count() is just overhead. Basically your example should look like this:
$title = "I am a boy";
$url = str_replace(' ','-', $title);
That's it.
Further you told that this would make problems if the original string already contains a -. I would use preg_replace() instead of str_replace() to solve that problem. Like this:
$string = 'Destination - Silicon Valley';
// replace spaces by hyphen and
// group multiple hyphens into a single one
$string = preg_replace('/[ -]+/', '-', $string);
echo $string; // Destination-Silicon-Valley
Use preg_replace instead:
$url = preg_replace('/\s+/', '-', $title);
\s+ means "any whitespace character (\t\r\n\f (space, tab, line feed, newline)).
use urlencode:
<?php
$s = "i am a boy";
echo urlencode($s);
$s = "Destination - Silicon Valley";
echo urlencode($s);
?>
return:
i+am+a+boy
Destination+-+Silicon+Valley
and urldecode:
<?php
$s = "i+am+a+boy";
echo urldecode($s)."\n";
$s = "Destination+-+Silicon Valley";
echo urldecode($s);
?>
return:
i am a boy
Destination - Silicon Valley
just use urlencode() and urldecode(). It’s for sending Data with GET in the URL.

Stripping variable suffix off Wordpress title

I'm trying to strip a variable suffix off my Wordpress titles, basically a bunch of hastags from posts imported from Instagram that are preceeded by an hyphen and I've come up with something like this:
<?php
$titleoutput = get_the_title($ID);
$titleoutputstrip = preg_replace("/\-/", "", $titleoutput);
echo $titleoutputstrip;
?>
But it doesn't seem to be working.
Can anyone help me out?
Thanks in advance!
<?php
$titleoutput = get_the_title($ID);
$titleoutputstrip = ltrim($titleoutput , '-'); // ltrim for begining rtrim for end
echo $titleoutputstrip;
?>
I finally nailed it with:
<?php
$titleoutput = get_the_title($ID);
$titleoutputstrip = preg_replace('/\ #[^.]+$/','',$titleoutput);
echo $titleoutputstrip;
?>
The hyphen was giving me problems because it's actually a dash "–" or something like that so I just set it to look for the first hashtag and erase the contents to the end.

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