Calling method from a non-object? - php

Question

$query = "INSERT INTO users (name, password) VALUES ('$myusername', '$mypassword')";
if (!($result = $mysqli->query($query)))
die("WHAT???? " . $mysqli->error . " EEEEEFFFFFFF.");
$count = $result->num_rows;
while ($row = $result->fetch_array()) {
if ($row[name] == $myusername) {
$mysqli->query("DELETE FROM users WHERE name='$myusername' AND password='$mypassword'");
$count = 5;
}
}
When I run this, it gives me an error:
Fatal error: Call to a member function fetch_array() on a non-object in /home/appstore/public_html/phpstoof/signedup.php on line 26
Where line 26 is where the while statement starts (while(x)). $mysqli ALREADY an instance of mysqli(). I don't see the how this is an error if the same code works on another file.

Answer 1

An INSERT statement has nothing to fetch.

Answer 2

As #mellamokb says, INSERT has nothing to fetch. Also you have used a mix of MySQL and MySQLi.
With MySQLi, the code should be like:
$mysqli = new mysqli($db_host, $db_username, $db_password, $db_database);
$str_sql = 'INSERT INTO users (name, password) VALUES (?, ?)';
// Create a prepared statement
$stmt = $mysqli->prepare($str_sql);
// Bind parameters for markers; same order and same count in prepared statement
$stmt->bind_param('ss', $myusername, $mypassword);
// Execute query
$stmt->execute();
// *************************************************************************
// If you're using a SELECT statement, each output field must be bound to
// a variable in the same order as in SELECT
// Bind result variables
$stmt->bind_result($_var1, $_var2, $_var3, ...);
// Fetch results and generate output as an associative array
while ($stmt->fetch())
{
// Handle $_var1, $_var2, $_var3, ...
}
// *************************************************************************
// Free stored result memory
$stmt->free_result();
// Close statement
$stmt->close();
// Close connection
$mysqli->close();