Let's take 3 tables that has all tons of rows:
TABLE Posts
PostPID
PostUID
PostText
TABLE Users
UserUID
UserName
TABLE Favorites
FavoriteUID
FavoritePID
Now, in order to get all the recent posts I perform a query such as:
SELECT p.PostPID, p.PostUID, p.PostText, u.UserUID, u.UserName
FROM Posts AS p
JOIN Users AS u
ON p.PostUID = u.UserUID
ORDER BY p.PostPID DESC
LIMIT 0, 30
Which works fine. Now I was wondering, how could I get only the posts a certain UserUID prefers? So only the one with FavoriteUID = UserUID = X?
You could use a subquery.
...
Where p.PostUID in (select f.FavoritePID from Favorite f where f.FavoriteUID = UserUID)
...
second join will do the same
SELECT
p.PostPID, p.PostUID, p.PostText, u.UserUID, u.UserName
FROM
Posts AS p
JOIN
Users AS u ON p.PostUID = u.UserUID
Join
Favorites as f on f.FavoriteUID = u.UserUID and f.FavoritePID=p.PostPID
ORDER
BY p.PostPID DESC
LIMIT 0, 30
Related
My tables
$sql="SELECT *
FROM addresses
LEFT JOIN users ON address_id = user_id
LEFT JOIN notes ON note_id = user_id
ORDER BY id DESC
LIMIT 1";
This is my SQL query, my task is to show the last records from 3 tables, but the table is blank, I don't know why,thanks in advance people :)
I guess the problem is coming from the ORDER BY id DESC .
Indeed, you have no column so called id.
You should probably remove this clause, in order to make your code work.
If you want to take the last records anyway, you can put an ORDER BY address_id DESC which will do the job !
The code directly edited :
$sql="SELECT *
FROM addresses
LEFT JOIN users ON address_id = user_id
LEFT JOIN notes ON note_id = user_id
ORDER BY adress_id DESC
LIMIT 1";
This may work:
SELECT a.address_id, u.user_id, n.note_id
FROM addresses a
LEFT JOIN users_addresses ua ON ua.ua_address_id = a.address_id
LEFT JOIN users u ON u.user_id = ua.ua_user_id
LEFT JOIN notes n ON n.note_user_id = u.user_id
ORDER BY a.address_id DESC
LIMIT 1
Here is the query to get all data from all the tables, not sure what do you mean last records from 3 tables, I can see four tables there:
SELECT *
FROM `addresses`
LEFT JOIN `users_addresses` ON `users_addresses`.`ua_address_id` = `addresses`.`address_id`
LEFT JOIN `users` ON `users`.`user_id` = `users_addresses`.`ua_user_id`
LEFT JOIN `notes` ON `notes`.`note_user_id` = `users`.`user_id`;
I have two tables posts and followings
posts (id,userid,post,timestamp) 30 000 rows
and
followings(id_me,userid) 90 000 rows
I want to get lattest 10 posts form posts table based on the people i follow and my posts
SELECT p.*
FROM posts as p INNER JOIN
followings as f
ON (f.id_me=(my user id) AND p.userid=f.userid )
OR
p.userid=(my user id)
ORDER BY id DESC LIMIT 10
But it takes about 10-15 seconds to return. Thanks in advance!
First, remove the filter from the join clause, let the join just correlate the joining tables.
(
SELECT p.*
FROM posts as p
INNER JOIN followings as f ON p.userid=f.userid
where f.id_me=(my user id)
UNION
SELECT p.*
FROM posts as p
where p.userid=(my user id)
)
ORDER BY id DESC LIMIT 10
second, verify your indexes if that ids got no indexes it ill perform a full table scan for each cartesian product of both tables (30k x 90k =~ 3700k pairs being compared)
third, if you don't follow yourself you need a union from post you are following and your posts
Using an OR in SQL is a performance killer, try this:
SELEC p.*
FROM posts as p INNER JOIN
followings as f
ON (f.id_me=(my user id) AND p.userid IN (f.userid,(my user id)))
ORDER BY id DESC LIMIT 10
Do this query using union:
(SELECT p.*
FROM posts p INNER JOIN
followings f
ON (f.id_me=(my user id) AND p.userid=f.userid
)
union
(select p.*
from posts p
where p.userid=(my user id)
)
ORDER BY id DESC
LIMIT 10
If the two conditions never overlap, then use union all instead.
An OR condition like that prevents the query optimizer from making use of indexes. Use a UNION instead:
SELECT *
FROM (SELECT p.*
FROM posts as p
INNER JOIN followings as f
ON f.id_me=(my user id) AND p.userid=f.userid
UNION
SELECT *
FROM posts
WHERE userid = (my user id)) u
ORDER BY id DESC
LIMIT 10
It might be just me but I think your WHERE clause is in an inefficient location:
SELECT
p.*
FROM
posts p
INNER JOIN
followings f
ON p.userid=f.userid
WHERE
MyUserID IN (p.userid, f.id_me)
ORDER BY
id DESC
LIMIT
10
I read in comments that you have the required indexes. The problem is the query. Combining OR with a JOIN confuses the poor and (often) dumb optimizer. The LIMIT 10 should be helpful but the optimizer is not (yet) smart enough to make the best plan.
Try this query:
( SELECT p.*
FROM posts AS p
JOIN followings AS f
ON f.id_me = (my_user_id)
AND p.userid = f.userid
ORDER BY p.id DESC
LIMIT 10
)
UNION ALL
( SELECT p.*
FROM posts AS p
WHERE p.userid = (my_user_id)
ORDER BY p.id DESC
LIMIT 10
) AS x
ORDER BY id DESC
LIMIT 10 ;
I have the table users with information about every user. Then the table posts with information about articles and finally the table user_posts, which contains following columns:
user_id
post_id
...
I am trying to get the chart of users with the highest count of posts. I made this query:
SELECT u.id as uid, u.name as uname,
count(up.id) as up_count
FROM users as u JOIN user_posts as up ON up.user_id = u.id ORDER BY vcount DESC LIMIT 25
This query returns me only one user and the total count of all rows in the table user_posts.
What am I doing wrong? I need to get the list of 25 users sorted by the count of articles that published each user.
Thank you in advance
Your query needs to have GROUP BY clause because you have used COUNT() function.
SELECT u.id as uid,
u.name as uname,
count(up.id) as up_count
FROM users as u
LEFT JOIN user_posts as up
ON up.user_id = u.id
GROUP BY u.id, u.name
ORDER BY up_count DESC LIMIT 25
You must have grouped them by ID otherwise you'll single total count result for all records. One more thing, use LEFT JOIN so even users with no post still will be visible in you result with the score of 0.
SELECT
u.id as uid, u.name as uname, count(up.id) as up_count
FROM users as u
JOIN user_posts as up ON up.user_id = u.id
GROUP BY
u.id, u.name
ORDER BY
vcount
DESC LIMIT 25
I'm not quite sure if this is the right approach, this is my situation:
I'm currently trying to select 15 galleries and then left join it with the user table through the id but I also want to select one random picture from each gallery however from what I know you can't limit the left join (picture) to only pick up one random picture without doing a subquery.
Here is what I got so far but its not working as it should:
SELECT galleries.id, galleries.name, users.username, pictures.url
FROM galleries
LEFT JOIN users ON users.id = galleries.user_id
LEFT JOIN pictures ON (
SELECT pictures.url
FROM pictures
WHERE pictures.gallery_id = galleries.id
ORDER BY RAND()
LIMIT 1)
WHERE active = 1
ORDER BY RAND()
LIMIT 15
I also tried to do this with Active Record but I got stuck after doing two left joins, is it possible to do get a subquery in here:
$this->db->select('galleries.id, galleries.name, users.id as user_id, users.username');
$this->db->from('galleries');
$this->db->join('users', 'users.id = galleries.user_id','left');
$this->db->join('pictures','pictures.gallery_id = galleries.id AND','left');
$this->db->where('active',1);
I hope its not to messy but I'm really starting to get confusing by all the sql queries..
Edit:
Active Record with CodeIgniter
You could fetch a random picture in a subquery:
select
g.name, u.username,
(select url from pictures p where p.gallery_id = g.gallery_id
order by rand() limit 1) as url
from galleries g
left join users u on g.user_id = u.id
where g.active = 1
Based on your comment, you could select a picture for each gallery in a subquery. This is assuming the picture table has an ID column.
select
g.name, u.username, p.url, p.name
from (
select id, user_id, name,
(select id from pictures p
where p.gallery_id = g.gallery_id
order by rand() limit 1) as samplepictureid
from galleries
where g.active = 1
) g
left join users u on g.user_id = u.id
left join pictures p on p.id = g.samplepictureid
SELECT
g.id,
g.name,
u.username,
p.url
FROM
galleries g
INNER JOIN (SELECT DISTINCT
gallery_id,
(SELECT url FROM pictures ss WHERE ss.gallery_id = s.gallery_id
ORDER BY RAND() LIMIT 1) AS url
FROM
pictures s) p ON
g.id = p.gallery_id
LEFT OUTER JOIN users u ON
g.user_id = u.id
WHERE
g.active = 1
This query will go out and select a gallery, then it will find any gallery with a picture (if you want to return galleries without a picture, change INNER JOIN to LEFT OUTER JOIN, and you'll be fine). After that, it joins it up with users. Now, of course, this puppy is going to return every frigging gallery for however many users you have (hoorah!). You may want to limit the user in the WHERE clause (e.g.-WHERE u.id = 123). Otherwise, you're going to get more results than you'd expect. That, or do an INNER JOIN on it.
I am making a cookie based favorite system and need to join data from two tables based on the unique user id stored in the cookie so I can tell what items that use has marked as favorites.
I know I need to do a JOIN but have not used them much and dont really have my head around them yet.
Existing query that selects the items from the db:
$query = mysql_query("SELECT *, UNIX_TIMESTAMP(`date`) AS `date` FROM songs WHERE date >= DATE_SUB( NOW( ) , INTERVAL 2 WEEK ) ORDER BY date DESC");
My favorites table is setup as: ID FAVORITE USERID where ID is the primary key, FAVORITE is the song ID from table songs and USERID is a hash stored in a cookie.
I need to join in all the rows from the favorites table where the USERID field matches the cookie hash variable.
I also need to gather the total number of rows in favorites that match the song id so I can display a count of the number of people who set the item as favorite so I can display how many people like it. But maybe need to do that as a separate query?
This should do it, I would imagine:
$user_id = intval($_COOKIE['user_id']);
$query = mysql_query(sprintf("
SELECT *
FROM songs s
INNER JOIN favorites f
ON f.favorite = s.id
WHERE f.userid = %s
", $user_id));
You should probably read up on the different types of joins.
And then to get the total amount of rows returned, you can just call mysql_num_rows on the result:
$favorite_song_count = mysql_num_rows($query);
EDIT: To select all songs but note which are favorited, you would do this:
$query = mysql_query(sprintf("
SELECT s.*, f.id as favorite_id
FROM songs s
LEFT JOIN favorites f
ON f.favorite = s.id AND f.userid = %s
", $user_id));
By switching it from an INNER JOIN to a LEFT JOIN we are selecting all songs even if they don't have a corresponding record in the favorites table. Any songs that are favorites of the user_id provided will have a non-NULL value for favorite_id.
You can have logical (and, or, ...) operators in join conditions:
select t1.*
from t1
join t2 on t1.id = t2.fid and t2.foo = 'blah'
If you are also querying the total number of times each song has been "favorited" then you need a group by construct also, like this way:
select *, count(f.id)
from songs as s
left join favorites as f on s.id = f.favorite and f.userid = <hash>
group by s.id