mysql_fetch_assoc returns duplicated rows... - php

Question

My fetch_assoc returns duplicated rows. It seems that it multiplies itself. I have 4 inputs in my table and it returns 16.
Here is my code.... Please help me. I think I got the looping wrong.
<?php
$tryshow =" SELECT c.customer_date, c.lastname, c.firstname,
s.room_number, s.date_in, s.date_out
FROM customers c
INNER JOIN services s
ON c.customer_date = s.date_in
WHERE c.customer_date = '$customer_date' ";
$result = #mysql_query($tryshow,$conn)
or die(mysql_error());
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print...";
}
?>
<form>
<table width="700" border="0">
<tr>
<td width="100">Customer Date:</td>
<td width="100">Last Name</td>
<td width="100">First Name</td>
<td width="100">Room Number</td>
<td width="100">Date In</td>
<td width="100">Date Out</td>
</tr>
<?php while($row=mysql_fetch_assoc($result)){ ?>
<tr>
<td><?php echo $row['customer_date']; ?></td>
<td><?php echo $row['lastname']; ?></td>
<td><?php echo $row['firstname']; ?></td>
<td><?php echo $row['room_number']; ?></td>
<td><?php echo $row['date_in']; ?></td>
<td><?php echo $row['date_out']; ?></td>
</tr>
<?php }?>
</table>
Thanks in advance.
-renz

Answer 1

You have two choices, if the query runs the same in phpMyAdmin. First, you can clean your data. If this is possible, its the best direction to go. Better data makes better applications possible. If you can't do much for the data integrity then you need to account for it. The simplest way would be to add a distinct to your query....
SELECT distinct c.customer_date, c.lastname, c.firstname,
s.room_number, s.date_in, s.date_out
FROM customers c
INNER JOIN services s
ON c.customer_date = s.date_in
WHERE c.customer_date = '$customer_date'

Answer 2

your on clause
ON c.customer_date = s.date_in
should be on a unique key
ON c.room_number = s.room_number