I want to add .00 to my value.
For example:
100 will be 100.00
100.26 will be 100.26 only.
$YOUR_VALUE = 1000.25;
echo number_format($YOUR_VALUE, 2);
number_format() can be your friend
Like #Gaurav said, use the number_format() function. Simply pass it the value and the number of digits you want there to be after the decimal point:
$value = 100;
echo number_format($value, 2); //prints "100.00"
Note that by default, it will also insert commas as the thousands separator:
$value = 2013;
echo number_format($value, 2); //prints "2,013.00"
You can change the characters that are used as the decimal point and thousands separator by passing them in as the third and fourth parameters to the function:
$value = 2013;
echo number_format($value, 2, ',', ' '); //prints "2 013,00"
number_format(100, 2, '.', ' ')
you can use
round()
or
number_format()
Related
$price = 10.00;
list($dollars, $cents) = explode('.', $price);
echo $dollars . '.' . $cents;
... almost works except that the zeros are omitted. 10.00 becomes 10 and 10.10 becomes 10.1
I see there's a padding function for strings, but anything for numbers or floats?
How do I fix this?
You can use number_format:
echo number_format($price, 2); // Would print 10.00
You can specify a separator for the decimal point and another one for the thousands:
echo number_format(1234.56, 2, ',', ' '); // Would print 1 234,56
Use Sprintf
$digit = sprintf("%02d", $digit);
For more information, refer to the documentation of sprintf.
number_format is what you want: http://php.net/manual/en/function.number-format.php
Though i would recommend number_format, you could use
sprintf('%02.2f', $price)
if you want to rely on string functions.
Is there an easy way to echo a float number with a specific amount of digits after the decimal point?
For example: $sum = 3.1234566768; I would like to echo $sum and get: 3.12.
use number_format()
number_format($sum,2);
Try with:
$sum = 3.1234566768;
$rounded = round($sum, 2);
echo number_format($sum, 2); // 3.12
echo number_format((float)$ans, 4, '.', '');
I think this will work out
I have a basic index.php page with some variables that I want to print in several places - here are the variables:
<?php
$firstprice = 1.50;
$secondprice = 3.50;
$thirdprice = 20;
?>
My challenge is that later in the document, when I print, I get the prices without the second '0' in the price - this is what happens:
<?php print "$firstprice";?> // returns 1.5 - not 1.50!
SO - I know how to do this with JS, but how is this done in PHP 5+? Basically I want to print the second '0' if there is already a decimal, so if the variable is equal to '3', it stays as '3', but if it's equal to '3.5' it converts to display '3.50' with a second '0', etc.
Here's a JS example - what's the PHP equivalent?
JS:
.toFixed(2).replace(/[.,]00$/, ""))
Many thanks!!
This is simple and it will also let you tweak the format to taste:
$var = sprintf($var == intval($var) ? "%d" : "%.2f", $var);
It will format the variable as an integer (%d) if it has no decimals, and with exactly two decimal digits (%.2f) if it has a decimal part.
See it in action.
Update: As Archimedix points out, this will result in displaying 3.00 if the input value is in the range (2.995, 3.005). Here's an improved check that fixes this:
$var = sprintf(round($var, 2) == intval($var) ? "%d" : "%.2f", $var);
<?php
$number = 1234.56;
// english notation (default)
$english_format_number = number_format($number);
// 1,235
// French notation
$nombre_format_francais = number_format($number, 2, ',', ' ');
// 1 234,56
$number = 1234.5678;
// english notation without thousands seperator
$english_format_number = number_format($number, 2, '.', '');
// 1234.57
?>
more info here
http://php.net/manual/en/function.number-format.php
You could use
if (is_float($var))
{
echo number_format($var,2,'.','');
}
else
{
echo $var;
}
What about something like this :
$value = 15.2; // The value you want to print
$has_decimal = $value != intval($value);
if ($has_decimal) {
echo number_format($value, 2);
}
else {
echo $value;
}
Notes :
You can use number_format() to format value to two decimals
And if the value is an integer, just display it.
you can use number_format():
echo number_format($firstprice, 2, ',', '.');
Alternatively way to print
$number = sprintf('%0.2f', $numbers);
// 520.89898989 -> 520.89
I have some double fields in my database and when echoing the fields out in my php I get .00 at the end of the values.
How do I get the .00 not to display, but display if there is a value?
You can use str_replace to remove the ".00" from the values.
$value = 10.00;
echo str_replace('.00', '', $value); // 10
$value = 10.52;
echo str_replace('.00', '', $value); // 10.52
echo (int)$double;
will simply strip off the decimal places. if you merely want to hide 'zero' decimals (10.00 -> 10), but leave non-zero decimals (10.1 -> 10.1), then you'd need to do some processing:
echo preg_replace('/\.0+$/', '', $double);
which would handle any number of zeroes after the decimal place, but leave non-zeroes in place.
if (fmod($number, 1) == 0)
{
$number = intval($number);
}
else
{
$number = round($number, 2);
}
Or just use round() [# ideone.com]:
var_dump(round($number = 5.00, 2)); // 5
var_dump(round($number = 5.01, 2)); // 5.01
For an arbitrary number of 0s at the end of the number:
$number = rtrim($number,".0");
Examples:
Input : 1.00
Result: 1
Input : 1.25
Result: 1.25
Input : 1.40
Result: 1.4
Input : 1.234910120000
Result: 1.23491012
select number,if(number % 1 = 0,cast(number as unsigned),number)
from table
I want that real numbers would be for example 12.92, but not 12.9241. Is it possible to do like that?
In PHP, try number_format:
$n = 1234.5678;
// Two decimal places, using '.' for the decimal separator
// and ',' for the thousands separator.
$formatted = number_format($n, 2, '.', ',');
// 1,234.57
For PHP you can use number_format(), for MySQL use the FORMAT() function.
MySQL: http://dev.mysql.com/doc/refman/5.1/en/string-functions.html#function_format
FORMAT(number, 2)
Example:
mysql> SELECT FORMAT(12332.123456, 4);
-> '12,332.1235
PHP: http://php.net/manual/en/function.number-format.php
$number = 1234.5678;
$formatted_number = number_format($number, 2, '.', '');
// 1234.56
$number = 1234.5678;
$teX = explode('.', $number);
if(isset($teX[1])){
$de = substr($teX[1], 0, 2);
$final = $teX[0].'.'.$de;
$final = (float) $final;
}else{
$final = $number;
}
final will be 1234.56
You can multiply your number by 100, do a rounding of the result and then divide back by 100.
Or in php use the round function round function
$result=round(12.9241, 2);