Using WEBrick to serve PHP web applications - php

Question

I am a PHP developer who has started learning Ruby on Rails. I love how easy it is to get up and running developing Rails applications. One of the things I love most is WEBrick. It makes it so you don't have to configure Apache and Virtual Hosts for every little project you are working on. WEBrick allows you to easily start up and shut down a server so you can click around your web application.
I don't always have the luxury of working on a Ruby on Rails app, so I was wondering how I might configure (or modify) WEBrick to be able to use it to serve up my PHP projects and Zend Framework applications.
Have you attempted this? What would be the necessary steps in order to achieve this?

Answer 1

To get php support in webrick you can use a handler for php files. To do this you have to extend HttpServlet::AbstractServlet and implement the do_GET and do_POST methods. These methods are called for GET and POST requests from a browser. There you just have to feed the incoming request to php-cgi.
To get the PHPHandler to handle php files you have to add it to the HandlerTable of a specific mount. You can do it like this:
s = HTTPServer.new(
:Port => port,
:DocumentRoot => dir,
:PHPPath => phppath
)
s.mount("/", HTTPServlet::FileHandler, dir,
{:FancyIndexing => true, :HandlerTable => {"php" => HTTPServlet::PHPHandler}})
The first statement initializes the server. The second adds options to the DocumentRoot mount. Here it enables directory listings and handling php files with PHPHandler. After that the server can be started with s.start().
I have written a PHPHandler myself as I haven't found one somewhere else. It is based on webricks CGIHandler, but reworked to get it working with php-cgi. You can have a look at the PHPHandler on GitHub:
https://github.com/questmaster/WEBrickPHPHandler

Answer 2

You can use nginx or lighttpd
Here's a minimal lighttpd config.
Install PHP with FastCGI support and adjust the "bin-path" option below for your system. You can install it with MacPorts using sudo port install php5 +fastcgi
Name this file lighttpd.conf
then simply run lighttpd -f lighttpd.conf from any directory you'd like to serve.
Open your webbrowser to localhost:8000
lighttpd.conf:
server.bind = "0.0.0.0"
server.port = 8000
server.document-root = CWD
server.errorlog = CWD + "/lighttpd.error.log"
accesslog.filename = CWD + "/lighttpd.access.log"
index-file.names = ( "index.php", "index.html",
"index.htm", "default.htm" )
server.modules = ("mod_fastcgi", "mod_accesslog")
fastcgi.server = ( ".php" => ((
"bin-path" => "/opt/local/bin/php-cgi",
"socket" => CWD + "/php5.socket",
)))
mimetype.assign = (
".css" => "text/css",
".gif" => "image/gif",
".htm" => "text/html",
".html" => "text/html",
".jpeg" => "image/jpeg",
".jpg" => "image/jpeg",
".js" => "text/javascript",
".png" => "image/png",
".swf" => "application/x-shockwave-flash",
".txt" => "text/plain"
)
# Making sure file uploads above 64k always work when using IE or Safari
# For more information, see http://trac.lighttpd.net/trac/ticket/360
$HTTP["useragent"] =~ "^(.*MSIE.*)|(.*AppleWebKit.*)$" {
server.max-keep-alive-requests = 0
}
If you'd like to use a custom php.ini file, change bin-path to this:
"bin-path" => "/opt/local/bin/php-fcgi -c" + CWD + "/php.ini",
If you'd like to configure nginx to do the same, here's a pointer.

Answer 3

I found this, but I really think it isn't worth the hassle. Is making a virtual host (which isn't even necessary) that difficult? In the time it would take you to set this up to work with PHP, if you can even get it working, you could have written a script that creates virtual host entries for you, making it as easy as webrick.

Answer 4

It looks like WEBrick has CGI support, which implies that you can get PHP running by invoking it as a CGI script. The #! line at the top of each executable file would just need to point towards the absolute path to php-cgi.exe.
It's worth noting that you'd need to remove the #! line when moving the file to any other server that doesn't think of PHP as a CGI script, which would be ... uh ... all of'em.