I have to update the table if only the three values gets matched. I get a syntax error on trying this. What could be the reason?
$sql1="update target set updvalue='".$val3."' where Id ='".$b."'" AND MId ='".$c."'" AND DID ='".$f."'";
$res1=$this->db->query($sql1);
$sql1="update target set updvalue='".$val3."' where Id ='".$b."' AND MId ='".$c."' AND DID ='".$f."'";
$res1=$this->db->query($sql1);
use this
You can use Codeigniter query builder.
$this->db->where('Id',$b);
$this->db->where('MId',$c);
$this->db->where('DID',$f);
$upd_data['updvalue'] = $val3;
$res1=$this->db->update('target',$upd_data);
Let me know if it not works.
I think there are to many " between where Id and AND, that is, you have made a typo.
Hi I have two tables that I need to insert into.
the issue is that the first table has an ID field that is automatically generated and I need this field in the second query
members (table1):
|id|name|eyeColour|
assignedMembers (table 2):
|id|memberID|groupID|
I am currently using the below:
$addMember = $dbHandle->prepare("INSERT INTO members(name,date) VALUES(?,?)");
$addMember->bind_param("ss",$name,$eyeColour);
$addMember->execute();
$getID = $dbHandle->("SELECT id from members where name = ? LIMIT 1");
$getID->bind_param("s",$name);
$getID->execute();
$getID->bind_param($MID);
$assignMember= $dbHandle->prepare("INSERT INTO assignedMembers memberID,groupID) VALUES(?,4)");
$assignMember->bind_param("i",$MID);
$assignMember->execute();
This fails at the $assignMember->bind_param(); after troubleshooting I noticed that the $MID variable is empty.
it seems as though the row from the first INSERT is not added before the execution of the next statement is there a way to force this?
Thank you for taking the time to read this post, any help would be greatly appreciated
mysqli:$insert_id is what you are looking for.
$addMember = $dbHandle->prepare("INSERT INTO members(name,date) VALUES(?,?)");
$addMember->bind_param("ss",$name,$eyeColour);
$addMember->execute();
$id = $dbHandle->insert_id;
I think you should use
$getID->bind_result($MID);
$getID->fetch();
instead of
$getID->bind_param($MID);
Due to usage of '...->bind_param' I assume, you use MySQLi.
Check out: mysqli_insert_id — Get the ID generated in the last query
I'm working on a mailbox system for a game on Facebook. I have 2 inputs to a php script, with example input below:
$FriendIDs = "10000001,10002421,10132000,10074794,13523543"
$MailCode = "ReqGem"
and a table with the columns ID, Mailbox.
What I want to be able to do is concatenate whatever was originally in the Mailbox field, with MailCode, for each person in the FriendIDs.
I figured it was something like this, but I couldn't get it to work (my php/sql knowledge is pretty dire!):
mysqli_query($db, "UPDATE Save SET Mailbox = CONCAT(Mailbox,'$MailCode' . '_') WHERE 'id' IN $FriendIDs);
EDIT: I've just realized I need to add a new row if the FriendID isn't already in the table.
I'm guessing I need to start out with INSERT INTO and then use ON DUPLICATE KEY UPDATE, but I can't seem to get it to work. It's a bit trickier since the unique key is in an array, and I can't use WHERE id IN(ArrayOfValues) in an INSERT query.
Any help would be greatly appreciated!
You're close:
$FriendIDs = "10000001,10002421,10132000,10074794,13523543";
$MailCode = "ReqGem";
mysqli_query($db, "UPDATE Save SET Mailbox = CONCAT(Mailbox,'$MailCode' . '_') WHERE `id` IN($FriendIDs));
You just needed the parenthesis for IN() as it is a function.
Don't use single quotes for column names. Use ticks. Single quotes are for strings.
I'm using a SELECT query to obtain a variable using mysql_fetch_assoc. This then puts the variable into an UPDATE variable to put the returned value back into the database.
If I hard code the value, or use a traditional variable and it goes in just fine, but it doesn't work when using a value previously retrieved from the database. I've tried resetting the array variable to my own text and that works.
$arrgateRetrivalQuery = mysql_query(**Select Query**);
$arrGate = mysql_fetch_assoc($arrgateRetrivalQuery);
$arrivalGateTest = $arrGate['gatetype'];
$setGateAirportSQL = "UPDATE pilots SET currentgate = '".$arrivalGateTest."' WHERE pilotid = '".$pilotid."'";
$setGateAirportQuery = mysql_query($setGateAirportSQL);
// Close MySQL Connection
mysql_close($link);
This will just make the field to update have nothing in it, however whenever I remove the variable from the SELECT to one I define, array or not, it will work.
Hope this is clear enough. Thanks in advance.
Is arrivalGateTest a number or a string? How did you try to put another value in the query? If you are sure the previous query returns a value, try to write: $setGateAirportSQL = "UPDATE pilots SET currentgate = '$arrivalGateTest' WHERE pilotid = '$pilotid'";.
Just change your sql to inlcude a subquery.
You could use the following general syntax:
UPDATE pilots SET currentgate = (SELECT gate FROM airport WHERE flight='NZ1') WHERE pilotid='2';
which is demonstrated on this fiddle
This saves the extra query and more accurately describes what you are trying to achieve.
WARNING - test it carefully first!
I'm trying to run the following PHP script to do a simple database query:
$db_host = "localhost";
$db_name = "showfinder";
$username = "user";
$password = "password";
$dbconn = pg_connect("host=$db_host dbname=$db_name user=$username password=$password")
or die('Could not connect: ' . pg_last_error());
$query = 'SELECT * FROM sf_bands LIMIT 10';
$result = pg_query($query) or die('Query failed: ' . pg_last_error());
This produces the following error:
Query failed: ERROR: relation "sf_bands" does not exist
In all the examples I can find where someone gets an error stating the relation does not exist, it's because they use uppercase letters in their table name. My table name does not have uppercase letters. Is there a way to query my table without including the database name, i.e. showfinder.sf_bands?
From what I've read, this error means that you're not referencing the table name correctly. One common reason is that the table is defined with a mixed-case spelling, and you're trying to query it with all lower-case.
In other words, the following fails:
CREATE TABLE "SF_Bands" ( ... );
SELECT * FROM sf_bands; -- ERROR!
Use double-quotes to delimit identifiers so you can use the specific mixed-case spelling as the table is defined.
SELECT * FROM "SF_Bands";
Re your comment, you can add a schema to the "search_path" so that when you reference a table name without qualifying its schema, the query will match that table name by checked each schema in order. Just like PATH in the shell or include_path in PHP, etc. You can check your current schema search path:
SHOW search_path
"$user",public
You can change your schema search path:
SET search_path TO showfinder,public;
See also http://www.postgresql.org/docs/8.3/static/ddl-schemas.html
I had problems with this and this is the story (sad but true) :
If your table name is all lower case like : accounts
you can use: select * from AcCounTs and it will work fine
If your table name is all lower case like : accounts
The following will fail:
select * from "AcCounTs"
If your table name is mixed case like : Accounts
The following will fail:
select * from accounts
If your table name is mixed case like : Accounts
The following will work OK:
select * from "Accounts"
I dont like remembering useless stuff like this but you have to ;)
Postgres process query different from other RDMS. Put schema name in double quote before your table name like this, "SCHEMA_NAME"."SF_Bands"
Put the dbname parameter in your connection string. It works for me while everything else failed.
Also when doing the select, specify the your_schema.your_table like this:
select * from my_schema.your_table
If a table name contains underscores or upper case, you need to surround it in double-quotes.
SELECT * from "Table_Name";
I had a similar problem on OSX but tried to play around with double and single quotes. For your case, you could try something like this
$query = 'SELECT * FROM "sf_bands"'; // NOTE: double quotes on "sf_Bands"
This is realy helpfull
SET search_path TO schema,public;
I digged this issues more, and found out about how to set this "search_path" by defoult for a new user in current database.
Open DataBase Properties then open Sheet "Variables"
and simply add this variable for your user with actual value.
So now your user will get this schema_name by defoult and you could use tableName without schemaName.
You must write schema name and table name in qutotation mark. As below:
select * from "schemaName"."tableName";
I had the same issue as above and I am using PostgreSQL 10.5.
I tried everything as above but nothing seems to be working.
Then I closed the pgadmin and opened a session for the PSQL terminal.
Logged into the PSQL and connected to the database and schema respectively :
\c <DATABASE_NAME>;
set search_path to <SCHEMA_NAME>;
Then, restarted the pgadmin console and then I was able to work without issue in the query-tool of the pagadmin.
For me the problem was, that I had used a query to that particular table while Django was initialized. Of course it will then throw an error, because those tables did not exist. In my case, it was a get_or_create method within a admin.py file, that was executed whenever the software ran any kind of operation (in this case the migration). Hope that helps someone.
In addition to Bill Karwin's answer =>
Yes, you should surround the table name with double quotes. However, be aware that most probably php will not allow you to just write simply:
$query = "SELECT * FROM "SF_Bands"";
Instead, you should use single quotes while surrounding the query as sav said.
$query = 'SELECT * FROM "SF_Bands"';
You have to add the schema first e.g.
SELECT * FROM place.user_place;
If you don't want to add that in all queries then try this:
SET search_path TO place;
Now it will works:
SELECT * FROM user_place;
Easiest workaround is Just change the table name and all column names to lowercase and your issue will be resolved.
For example:
Change Table_Name to table_name and
Change ColumnName to columnname
It might be silly for a few, but in my case - once I created the table I could able to query the table on the same session, but if I relogin with new session table does not exits.
Then I used commit just after creating the table and now I could able to find and query the table in the new session as well. Like this:
select * from my_schema.my_tbl;
Hope this would help a few.
Make sure that Table name doesn't contain any trailing whitespaces
Try this: SCHEMA_NAME.TABLE_NAME
I'd suggest checking if you run the migrations or if the table exists in the database.
I tried every good answer ( upvote > 10) but not works.
I met this problem in pgAdmin4.
so my solution is quite simple:
find the target table / scheme.
mouse right click, and click: query-tool
in this new query tool window, you can run your SQL without specifying set search_path to <SCHEMA_NAME>;
you can see the result: