i couldn't be able to execute ffmpeg command using php exec() function.
Actually all was fine and running before but by mistake we execute this command in SSH
-d safe_mode=off
after that we are facing this problem.
we have on it from the plesk pannel and also checked in php.ini it is safe_mod=on but still we couldn't be able to execute ffmpeg command through exec() function.
Can any one help me please.
Thanks,
Faraz
For exec() to work, you need to have save_mode=off in your php.ini
So the fix should just be: edit the save_mode=on line inside your php.ini to save_mode=off
And restart your webserver
The ssh command should not have anything to do with your webserver.
In the php.net documentation (http://nl3.php.net/manual/en/function.exec.php)
They say:
Note: When safe mode is enabled, you
can only execute files within the
safe_mode_exec_dir. For practical
reasons, it is currently not allowed
to have .. components in the path to
the executable.
Related
Ok, after having bashed my head on this for hours I decided to ask for help. I have a Windows Server 2008 running Apache 2.4 and PHP 7.1. My application must run a PHP script on the server when the user clicks a button on the browser.
This is working fine on my desktop with Windows 10. However, on the server, exec() returns "null" and an exit code of 255.
I read all I could find on exec() issues and tried the following:
exec("C:\\PHP7\\php.exe -v", $output);
I got the proper response containing PHP's version information.
Then I decided to check the configuration files:
exec("C:\\PHP7\\php.exe --ini", $output);
All files were in place.
Then I decided to perform a syntax check on my script:
exec("C:\\PHP7\\php.exe -d display_errors=1 -l C:\\Apache24\\htdocs\\script.php", $output);
No errors were found.
Finally I decided to check the user account:
exec("whoami", $output);
Got "NT Authority\SYSTEM" as expected. To make sure that the script was able to run under the SYSTEM account I used SysInternals psexec:
psexec -s C:\PHP7\php.exe C:\Apache24\htdocs\script.php
Everything ran smoothly.
In other words, the script shows no problems when executed from the command line, either under a user account or the system account. I have also proven that PHP is being properly invoked by exec().
So, then I decided to check for "hidden" errors in my code adding the following two lines to the very beginning of the script:
error_reporting(E_ALL);
ini_set('display_errors', 1);
But, no joy. And I'm out of ideas.
Can any good soul help me on this?
Thanks a bunch,
Miguel.
Finally! The key to the answer was here: PHP exec() git fetch failing with return value 255.
I was unable to see any errors, even adding the "2>&1" pipe redirection to my commands. After reading that article, I learned that proc_open() is way better than exec(). Quoting from PHP's documentation:
proc_open() is similar to popen() but provides a much greater degree of control over the program execution
So, I replaced my exec() for a few lines of code (refer to the example in the manual) and found that the problem was being caused by the Zend Opcache, which was enabled for CLI. The quickier solution for me was to disable it in the command line:
php.exe -d opcache.enable_cli=0 myscript.php
Voilà! Problem solved!
I have added this line PATH DEFAULT=${PATH}:~/bin/ to the ~/.pam_environment
This allows me to call ffmpeg from command line without path which is obviously in ~/bin/ dir so everything works fine as long as im ussing command line.
But if try to run the exact same command from php all i get is sh: ffmpeg: not found
And the code is
shell_exec("ffmpeg 2>&1");
So from my very little experiance with linux (in this case Ubuntu to be specific) i guess apache has no access to pam_environment or ~/bin
What can i do to make this work?
look at the output of phpinfo(), it has a section with all environment variables it sees. then look at your webserver configuration, maybe it's sanitizing the environment, or maybe the init script which starts your webserver does it.
and is the account the webserver is running under using PAM at all?
Like many others I have problem with shell_exec() function in PHP. I have safe mode disabled and disabled_functions deleted from php.ini.
If I run php script from terminal (php print.php) it's working perfectly but if I run it from web browser nothing happens.
Here is the scipt:
<?php
$output = shell_exec('lp print.php');
echo "<pre>$output</pre>";
?>
Please help me. I'm running PHP 5.3.10 on Apache2. My OS is Ubuntu Server 12.4. Here is the phpinfo page: http://testni-server.info/info.php
Progamming language PHP allows one to limit executing of external commands via configuration directive safe_mode_exec_dir. This directive should contain full path to a directory conatining programs which PHP script can run. If the script tries to execute a command not located in this directory, the command is not executed. This configuration directive is active only if safe mode is enabled, which means more and sometimes unwanted restrictions to users. PHP has no known possibility to limit executing of external commands with disabled safe mode. Teherefore, here is a patch adding special directive exec_dir straightly into PHP. This directive is very similar to safe_mode_exec_dir, but safe mode has not to be enabled.
This patch limits or corrects the behavior of these functions:
exec()
passthru()
proc_open()
shell_exec()
system()
popen()
is_executable()
The patch was created for purposes of limit execution of external commands of users on a multidomain apache server, first for PHP version 4.2.1. The patch was sent to PHP developers so it could be a part of PHP, but no one of PHP developers was interested in. On the other side, some PHP users wanted this patch, therefore this site was created.
Your command line (CLI) PHP might be using a different working directory and/or path than the CGI one. Try defining the working directory (containing the lp command) explicitly with chdir() before calling shell_exec().
<?php
exec("whoami");
?>
I can be more explicit with the code . Although When I'm trying to call the php file with my browser nothing happens (of course I'm using apache and the whole).
Note : The safe_mode is activated, I'm using php5, php interpreter seems to be nice when running other functions, I'm a ubuntu user.
Then what is wrong?
I think you're looking for the echo function. Executing whoami using the exec function will run the program but show you nothing… you want to spit out the result too.
echo exec("whoami");
You have to echo the output of the exec command somewhere.
PHP documentation for exec function contains the example with whoami, look at the echo.
Right in the docs for exec:
When safe mode is enabled, you can only execute files within the safe_mode_exec_dir. For practical reasons, it is currently not allowed to have .. components in the path to the executable.
If possible, turn off safe mode. Safes you lots of headaches.
Otherwise, is the php file owned by the same user that Apache runs as?
On Ubuntu, this will usually be www-data.
Try:
sudo chown www-data /path/to/you/script.php
Then run again.
I am working on Windows server and able to run command from command prompt
c:> %convertxls% {some args....}
But when I run same command from php script
*shell_exec(%convertxls% ..... 2>&1);*
it gives me error as
%convertxls% is not recognized as an internal or external command, operable program or batch file.
I think when I am running command from command prompt, it run for user which logged in. And when I run the php script it run for "www" user for which path is not set.
Can anybody tell me where I am doing mistake?
*Note: I haven't written complete command.
Supply the full path to the executable.
ignacio right,I wanted to add one more point that ignacio did not specify .
Check the parameter disable_functions in the php.ini .
maybe this function is not allowed.
This sounds like the environment variable %convertxls% is not set.
You can use putenv() to set it; alternatively, as Ignacio already says, specify the full path.