<?php
header('Content-type: text/html; charset=gb2312');
include("parser.php");
$html = file_get_html('http://www.souyishop.com/shop_gkq5/1280/products.aspx?sku=1351249&shbid=20358');
$price = $html->find('span[id=Product_main1_Label5]');
$price = str_replace(" ", "", str_replace("￥", "", str_replace("元", "", $price[0])));
echo (int)$price . "<br>";
?>
Basically, I'm trying to fetch the price ￥ 32 元 and I remove the currency and white space. After that I try to convert the string to int so that I can do calculation later. Guess what, I get 0. :(
Somethign like this isnt going to work:
echo intval('￥ 32');
So try replacing all nondigits
echo (int)preg_replace( '~\D~', '', $str );
Use a regular expression in this case:
$re = preg_match('/(\d+)/', $str, $matches);
$price = $matches[1];
That str_replace chain is cumbersome
A more elegant solution is to pull out all numbers with preg_match
$price = preg_match('/[0-9]+/i', $price, $matches);
print_r($matches);
I think you should first echo $price without and int conversion to determine if you are actually replacing the string items you think you are, this is probably why it returns 0.
Chinese encoding requires special handling.
edit:
try using the html code for the char (yen = ¥) see: http://www.starr.net/is/type/htmlcodes.html
Related
I'm trying to get all numeric before space/alpha in PHP string.
Example:
<?php
//string
$firstStr = '12 Car';
$secondStr = '412 8all';
$thirdStr = '100Pen';
//result I need
firstStr = 12
SecondStr = 412
thirdStr = 100
How do I can get all the number of a string just like example above?
I've an idea to get the position of first Alpha, then get all numeric before that position.
I've successfully get the position using
preg_match('~[a-z]~i', $value, $match, PREG_OFFSET_CAPTURE);
But I'm not done yet to get the numeric before the posisition.
How do I can do that, or anybody know how to fix my idea?
Anyhelp will be appreciated.
You don't need to use regex for strings like the examples you've shown, or any functions at all for that matter. You can just cast them to ints.
$number = (int) $firstStr; // etc.
The PHP rules for string conversion to number will handle it for you.
However, because of those rules, there are some other types of strings that this won't work for. For example, '-12 Car' or '412e2 8all'.
If you do use a regex, be sure to anchor it to the beginning of the string with ^ or it will match digits anywhere in the string as the other regex answers here do.
preg_match('/^\d+/', $string, $match);
$number = $match[0] ?? '';
Here's an extremely hackish approach that will work in most situations:
$s = "1001BigHairyCamels";
$n = intval($s);
$my_number = str_replace($n, '', $s);
$input = '100Pen';
if (preg_match('~(\d+)[ a-zA-Z]~', $input, $m)) {
echo $m[1];
}
This function will do the job!
<?php
function getInt($str){
preg_match_all('!\d+!', $str, $matches);
return $matches[0][0];
}
$firstStr = '12 Car';
$secondStr = '412 8all';
$thirdStr = '100Pen';
echo 'firstStr = '.getInt($firstStr).'<br>';
echo 'secondStr = '.getInt($secondStr).'<br>';
echo 'thirdStr = '.getInt($thirdStr);
?>
I am looking for some code that allows you to add +44 onto the beginning of my $string variable.
So the ending product would be:
$string = 071111111111
+44071111111111
Your $string variable isn't actually a string in this scenario; it's an integer. Make it a string by putting quotes around it:
$string = "071111111111"
Then you can use the . operator to append one string to another, so you could do this:
$string = "+44" . $string
Now $string is +44071111111111. You can read more about how to use the . (string concatenation operator) on the PHP documentation here.
Other people's suggestions of just keeping $string as an integer wouldn't work: "+44" . 071111111111 is actually +447669584457. Due to the 0 at the start of the number, PHP converts it to an octal number rather than a decimal one.
You can combine strings by .
$string = '+44'.$string;
You can use universal code, which works with another parameters too.
<?php
$code = "+44";
$string = "071111111111";
function prepend(& $string, $code) {
$test = substr_replace($string, $code, 0, 0);
echo $test;
}
prepend($string, $code);
?>
I have few strings where i need to extract only the prices in php (which will obviously be numerals).
The use cases are follows:
1) Rs. 23,459.45 desired output = 23459.45
2)Our best price 23,459.45 desired output = 23459.45
etc.
I gave the above use cases to give an idea that the preceding characters could be anything.
Please help!
How about:
$arr = array(
'Rs. 23,459.45 ',
'Our best price 23,459.45 ',
);
foreach($arr as $string) {
$string = preg_replace('/^.*?(\d+),?(\d{3})(\.\d{2})?.*$/', "$1$2$3", $string);
echo $string,"\n";
}
output:
23459.45
23459.45
It's:
$result = preg_replace('/[^0-9.]/', '', $string);
-but note, this will not validate numbers or provide valid result in common case since string could contain something like 'foo . bar,baz . price 20.5 with .6 discount' - end result will be not a valid number. So code above answers the question about "how to replace", but does not fit validating a number (and you've not mentioned if that is your goal).
About validating a number - such question will be ambiguous because it's not obvious how to convert ..20.5.6 (which will be result for string above). But if you need only to check that, use is_numeric() on $result, like this:
$string = 'foo . bar,baz . price 20.5 with .6 discount';
$result = preg_replace('/[^0-9.]/', '', $string);
$result = is_numeric($result)?(float)$result:null;
You can use this to validate the above strings. When this function valiadates Rs. , it will return two dots, so I used ltrim to remove the first dot.
<?php
//$s = "Rs. 23,459.45";
$s= "Our best price 23,459.45";
echo $result = ltrim(preg_replace("/[^0-9.]+/", "", $s),'.');
?>
http://codepad.org/cyH5OWyE
I have a small problem. I am tryng to convert a string like "1 234" to a number:1234
I cant't get there. The string is scraped fro a website. It is possible not to be a space there? Because I've tried methods like str_replace and preg_split for space and nothing. Also (int)$abc takes only the first digit(1).
If anyone has an ideea, I'd be greatefull! Thank you!
This is how I would handle it...
<?php
$string = "Here! is some text, and numbers 12 345, and symbols !£$%^&";
$new_string = preg_replace("/[^0-9]/", "", $string);
echo $new_string // Returns 12345
?>
intval(preg_replace('/[^0-9]/', '', $input))
Scraping websites always requires specific code, you know how you receive the input - and you write code that is required to make it usable.
That is why first answer is still str_replace.
$iInt = (int)str_replace(array(" ", ".", ","), "", $iInt);
$str = "1 234";
$int = intval(str_replace(' ', '', $str)); //1234
I've just came into the same issue, however the answer that was provided wasn't covering all the different cases I had...
So I made this function (the idea popped in my mind thanks to Dan) :
function customCastStringToNumber($stringContainingNumbers, $decimalSeparator = ".", $thousandsSeparator = " "){
$numericValues = $matches = $result = array();
$regExp = null;
$decimalSeparator = preg_quote($decimalSeparator);
$regExp = "/[^0-9$decimalSeparator]/";
preg_match_all("/[0-9]([0-9$thousandsSeparator]*)[0-9]($decimalSeparator)?([0-9]*)/", $stringContainingNumbers, $matches);
if(!empty($matches))
$matches = $matches[0];
foreach($matches as $match):
$numericValues[] = (float)str_replace(",", ".", preg_replace($regExp, "", $match));
endforeach;
$result = $numericValues;
if(count($numericValues) === 1)
$result = $numericValues[0];
return $result;
}
So, basically, this function extracts all the numbers contained inside of a string, no matter how many text there is, identifies the decimal separator and returns every extracted number as a float.
One can specify what decimal separator is used in one's country with the $decimalSeparator parameter.
Use this code for removing any other characters like .,:"'\/, !##$%^&*(), a-z, A-Z :
$string = "This string involves numbers like 12 3435 and 12.356 and other symbols like !## then the output will be just an integer number!";
$output = intval(preg_replace('/[^0-9]/', '', $string));
var_dump($output);
I have a string, "Chicago-Illinos1" and I want to add one to the end of it, so it would be "Chicago-Illinos2".
Note: it could also be Chicago-Illinos10 and I want it to go to Chicago-Illinos11 so I can't do substr.
Any suggested solutions?
Complex solutions for a really simple problem...
$str = 'Chicago-Illinos1';
echo $str++; //Chicago-Illinos2
If the string ends with a number, it will increment the number (eg: 'abc123'++ = 'abc124').
If the string ends with a letter, the letter will be incremeted (eg: '123abc'++ = '123abd')
Try this
preg_match("/(.*?)(\d+)$/","Chicago-Illinos1",$matches);
$newstring = $matches[1].($matches[2]+1);
(can't try it now but it should work)
$string = 'Chicago-Illinois1';
preg_match('/^([^\d]+)([\d]*?)$/', $string, $match);
$string = $match[1];
$number = $match[2] + 1;
$string .= $number;
Tested, works.
explode could do the job aswell
<?php
$str="Chicago-Illinos1"; //our original string
$temp=explode("Chicago-Illinos",$str); //making an array of it
$str="Chicago-Illinos".($temp[1]+1); //the text and the number+1
?>
I would use a regular expression to get the number at the end of a string (for Java it would be [0-9]+$), increase it (int number = Integer.parse(yourNumberAsString) + 1), and concatenate with Chicago-Illinos (the rest not matched by the regular expression used for finding the number).
You can use preg_match to accomplish this:
$name = 'Chicago-Illinos10';
preg_match('/(.*?)(\d+)$/', $name, $match);
$base = $match[1];
$num = $match[2]+1;
print $base.$num;
The following will output:
Chicago-Illinos11
However, if it's possible, I'd suggest placing another delimiting character between the text and number. For example, if you placed a pipe, you could simply do an explode and grab the second part of the array. It would be much simpler.
$name = 'Chicago-Illinos|1';
$parts = explode('|', $name);
print $parts[0].($parts[1]+1);
If string length is a concern (thus the misspelling of Illinois), you could switch to the state abbreviations. (i.e. Chicago-IL|1)
$str = 'Chicago-Illinos1';
echo ++$str;
http://php.net/manual/en/language.operators.increment.php