I am trying to post a file upload form to a php file that is located on another server but I do not know how to retrieve the results that are outputed using an iframe (i.e. basically a json object containing URL's being echoed by the upload.php). Is there any other way to retrieve the data?
code:
<form action="http://mydomain/upload.php" method="post" enctype="multipart/form-data" target="upload_target">
<input type="hidden" name="MAX_FILE_SIZE" value="1000000" />
Choose a file to upload: <input id="fileName" name="uploaded_file" type="file" />
<input type="submit" value="Upload"/>
<iframe id="upload_target" name="upload_target" src="#" style="width:0;height:0;border:0px solid #fff;"> </iframe>
</form>
Thanks
Explode function just get the contents of the file you need with get filecontents then explode the part of HTML you need
Related
My source code is to print upload SWF file tmp_name ?
<?php
echo json_encode($_FILES);
?>
<form method="POST" action="#" enctype="multipart/form-data" novalidate>
<input type="file" id="image" name="image" />
<input id="send" type="submit" name="data" value="Submit" />
</form>
But result i'm getting
{"image":{"name":"file.swf","type":"","tmp_name":"","error":1,"size":0}}
I have tried image uploading method no use on that !
{"image":{"name":"file.swf","type":"","tmp_name":"","error":1,"size":0}}
^^^^^^^^^
This error isn't specific to Flash at all. You'd run into the same issue with other formats as well.
Error 1 is UPLOAD_ERR_INI_SIZE. It means that the file you tried to upload was larger than your server's maximum upload size (upload_max_filesize), so the server didn't accept it.
Change this configuration value, or upload a smaller file.
I have the following form that allows uploading a file:
<form id="form1" name="form1" method="post" action="page1.php" enctype="multipart/form-data">>
CSV list: <input type="file" name="file" id="file">
<input type="submit">
</form>
When I go to my action/submit page I can retrieve the file and the temp location of the file, but I need to send it through again to a new page, so I do the following:
<form method="post" action="page2.php" name="details" >
<input type="hidden" id="type" name="type" value="1">
<input type="hidden" id="filename" name="filename" value="<? echo $_FILES["file"]["tmp_name"]; ?>">
<input type="submit" value="Insert Into Database">
</form>
This doesn't work because the temp file is already gone.... how can I pass the file through?
I think you want to rethink how you are getting this data. If it was me, I would want to have the first form upload the file to a temporary directory and pass the path to the file through a $_REQUEST. Then use a hidden input field pass the file path name through PHP and if they confirm their selection on the second form, do whatever you want with the file using the file's path. This means you don't have to upload two files(not efficient) and you can pass the data onto the second form.
I have a very basic PHP multiple file upload form:
<form action="file.upload.php" method="post" enctype="multipart/form-data">
<input type="hidden" name="id" value="<?php echo $_REQUEST['id']; ?>" />
<input type="hidden" name="bypass" value="1" />
<input multiple type="file" name="file[]" id="file">
<input type="submit" name="submit" value="Submit">
</form>
Everything works fine for a few files, but when I upload too many large files, the hidden variables are no longer posted to PHP (!)
I am not sure what is causing the from variables to be ignored by PHP (?)
(I've checked with fiddler and the form indeed sends the right data from clientside... i.e., form fields bypass and id are both properly populated on clientside...)
I want to post an entire IMAGE when SUBMIT button is clicked.
<FORM action=".." method=post>
<img src="...."/>
<input type="submit" value="Click"/>
</FORM>
Is it possible?
Please help me......
Thanks in advance.....
Are you looking to upload an image? If so, then you'll want the "file" HTML input element type:
<input type="file"/>
And include enctype="multipart/form-data" in your form tag.
Here's a basic tutorial and more info:
http://www.tizag.com/phpT/fileupload.php
if you want to post an image inside a form, you should have that image already on your server. In which case all you have to do is put a hidden element on the form with the location of that image and voila you have the image in the form
<input type="hidden" name="image_location" id="image_location" value="/images/bleh.jpg" />
You can do it like this:
<FORM action=".." method="POST" enctype="multipart/form-data">
<input type="file" id="file" placeholder="upload a file"
name="file">
<button type="submit">Submit</button>
</FORM>
I have a form and a div. I want the user to select an text file and hit submit and that will populate the div with the content of the file. I would like to do that without having to refresh the page.
<form action="action.php" method="post" enctype="multipart/form-data">
Click the "Choose File" button and browse for the file to import.<br /><br />
<input type="file" name="filelocation" value="Browse" /><br />
<input type="submit" name="submitform" value="Submit" />
</form>
<div id="filecontent">
</div>
There is no easy way to submit/upload the files via ajax. However, you can go for the jQuery Uploadify plugin to the trick for you.
Uploadify is a jQuery plugin that
integrates a fully-customizable
multiple file upload utility on your
website. It uses a mixture of
Javascript, ActionScript, and any
server-side language to dynamically
create an instance over any DOM
element on a page.
Theres is no easy way to do that, but u can use an Iframe with an ajax call to get your file to the server and work with it the normal ajax way
<form action="upload.php" method="post" enctype="multipart/form-data" target="upload_target" onsubmit="startUpload();" >
File: <input name="myfile" type="file" />
<input type="submit" name="submitBtn" value="Upload" />
</form>
look at target="yourhiddeniframe"
here is a complete howto:
http://www.ajaxf1.com/tutorial/ajax-file-upload-tutorial.html
greetings