php web image search - php

Question

I want to do a picture search engine. I use simple_html_dom and preg_match_all to get all the images, then use getimagesize to get all the image sizes.
Here is one part of my code.
<?php
header('Content-type:text/html; charset=utf-8');
require_once 'simple_html_dom.php';
$v = 'http://www.jqueryimage.com/';
$html = file_get_html($v);
foreach($html->find('img') as $element) {
if( preg_match('#^http:\/\/(.*)\.(jpg|gif|png)$#i',$element->src)){
$image = $element->src;
//$arr = getimagesize($image); //get image width and height
//$imagesize = $arr[0] * $arr[1];
echo $image.'<hr />';
}
}
?>
First question, how to add a judgement so that I can echo the biggest size image? (only one image).
Second question, I can get the image real url in these two possibilities, first where image is as a 'http' began, second where image is as a / began.
But how to get the image real url in the situation where image is as a './' or ../ or ../../ began? it is difficulty for me to judge how many ../ in a image, then cut the site url to complement a image real url?
Thanks.

Answer 1

Insert this before foreach loop:
$maxsize = -1;
$the_biggest_image = false;
Insert this below $image = $element->src; line
$arr = getimagesize($image);
if (($arr[0] * $arr[1]) > $maxsize) {
$maxsize = $arr[0] * $arr[1];
$the_biggest_image = $image;
}
After foreach loop you'll have $the_biggest_image variable set or false if nothing found. This will take first one if more than one 'biggest image' found.
For second question, I don't know!
Edit: fixed something!