foreach($ret as $object)
{
$res = $object->...;
$img_src = $res[0]->src;
echo $img_src . '<br />';
echo str_replace("&size=2", "", $img_src) . '<br /><br />';
}
$img_src ~ 'http://site.com/img.jpg&size=2'
And I have to receive same link but without &size=2. Why doesn't work my last line in code. It shows the same url.
Are you absolutely certain there are any goofy unprintable characters in your source string? Try debugging with this:
printf("%s\n", join(':', str_split($img_src)));
And make sure you really have &size=2 in your string. If you see two consecutive colons, you've got something like a \0 or some other character mucking up the works in the middle of your string.
Seems to work on this end:
http://site.com/img.jpg&size=2
http://site.com/img.jpg
from
<?php
$img_src = 'http://site.com/img.jpg&size=2';
echo $img_src.'<br />';
echo str_replace("&size=2", "", $img_src).'<br/><br/>';
?>
use preg_replace:
$c=preg_replace("/&size=2/","",$img_src);
Example of usage
<?php
$sr="http://site.com/img.jpg&size=2";
echo preg_replace("/&size=2/","",$sr);
?>
This will output
http://site.com/img.jpg
Related
I wrote a short test code in PHP7:
<?php
$str1=' bigapple ';
echo strlen($str1);
trim($str1) ;//or trim($str1," ")
echo strlen($str1);
?>
But whenever I use trim on $str1 ,the strlen would be return 10.
Can someone tell me the reason why? I've been searching it but find nothing.
You need to store trim string to any variable or you need to print trim string as following:
echo strlen(trim($str1));
You have not assigned the trimmed value in another variable. Try as below :
<?php
$str1=' bigapple ';
echo strlen($str1).'<br>';
$str2 = trim($str1);
echo strlen($str2).'<br>';
?>
Before giving negative response please read.
It's given
[et_pb_image admin_label="Image" src="https://scontent-mia1-1.xx.fbcdn.net/hphotos-xaf1/v/t1.0-9/10848034_8974277986_916022442694_n.jpg?oh=9edafcdfb85e2c1b30ed77e6fb8&oe=566091B0" show_in_lightbox="off" url="" url_new_window="off" animation="left" sticky="off" align="left" force_fullwidth="off" always_center_on_mobile="on" use_border_color="off" border_color="#ffffff" border_style="solid" /]
How can i take the first src url?
this is not working for me
$new = preg_match('/src="(.*)|[^"]"/iS', $y->post_content, $img);
echo '<pre>'; print_r($new); echo '</pre>';
The following should work:
$myString = '[et_pb_image admin_label="Image" src="https://scontent-mia1-1.xx.fbcdn.net/hphotos-xaf1/v/t1.0-9/10848034_8974277986_916022442694_n.jpg?oh=9edafcdfb85e2c1b30ed77e6fb8&oe=566091B0" show_in_lightbox="off" url="" url_new_window="off" animation="left" sticky="off" align="left" force_fullwidth="off" always_center_on_mobile="on" use_border_color="off" border_color="#ffffff" border_style="solid" /]';
if(preg_match('/src="([^"]*)/i', $myString , $img)) {
echo '<pre>';
print_r($img);
$src = $img[1];
echo '</pre>';
echo '<hr />' . $src;
}
What's wrong with your code:
preg_match returns a boolean. True when something is found.
src="(.*)|[^"]" is wrong. src=" is correct. After that you're going to match everything until the end of the line. That's not what you want.
Furthermore $img should contain your result.
Why the above is working:
/src=" # match the src
(
[^"] # matches everything except "
*) # capture the content between the quotes "[the src]"
/ix
You can find a working version here: http://sandbox.onlinephpfunctions.com/code/c71983343308a29272d90a441486474148ab3995
$str = '<div class="rss"><img src="http://www.wired.com/images_blogs/gadgetlab/2013/10/1125_hbogo_660-660x436.jpg" alt="You Can Now Get HBO GO Without Paying for Other Channels">
</div>Fans of';
I'm trying to get hold of the text after the <div class="rss"></div> but each expression I use doesn't seem to work.
matching .rss
if(preg_match('/^(<div class=\"rss\">[\S\s]+?</div>([\S\s]*)$/i', $item_content, $matches)) {
Could someone please help with this expression?
Originally I had this expression to match an image tag instead of a div and this worked fine by using
if(preg_match('/^(<img[\S\s]+?>)([\S\s]*)$/i', $item_content, $matches)) {
I didn't go deeply for the regex but yours work well with just solving some syntax problems.
It should be:
^<div class=\"rss\">[\S\s]+?<\/div>([\S\s]*)$/i
Live demo
This may help:
<?php
$item_content = '<div class="rss"><img src="http://www.wired.com/images_blogs/gadgetlab/2013/10/1125_hbogo_660-660x436.jpg" alt="You Can Now Get HBO GO Without Paying for Other Channels">
</div>Fans of';
if(preg_match('/^(<div class=\"rss\">[\S\s]+?<\/div>)([\S\s]*)$/i', $item_content, $matches)) {
$div = $matches[1];
$text = $matches[2];
echo "<textarea style=\"width: 600px; height: 300px;\">";
echo $div . "\n";
echo $text . "\n";
echo "</textarea>";
}
?>
Hey there,
I have this little php code:
<p class="category_text"><? echo $category_text; ?></p>
I waht to split the $category_text and get something like this:
This is sentence 1 of category_text
This is sentence 2 of category_text
and so on...
$category_text has about 300 words and lets say 6 sentences. How could I split the text in multiple paragraphs (delimited by the stop sings ".")
Thank you very much!
echo '<p class="category_text">'
. implode('</p><p class="category_text">', explode('.',$string))
.'</p>';
You can just replace the "." by the tag "":
<p class="category_text"><? echo str_replace('.', '.<br />', $category_text); ?></p>
It's not a perfect solution! But if you text is simple enough this little trick should work.
For example if you have a line with 3 dots:
$category_text = "Ok...";
It will show up like that:
OK.
.
.
Also if your sentences finish by "?" or "!" you can also use that:
<p class="category_text"><? echo str_replace(array('.', '!', '?'), array('.<br />', '!<br />', '?<br />'), $category_text); ?></p>
PS: My solution will create one paragraph "" but with multiple line break
Try creating an array, and then output the lines one by one. A sentence ending in ... would still be recognized as still ends in ". ".
$sentences = explode('. ', $category_text)
foreach($sentences as $val)
{
echo $val . ".<br /><br />";
}
You want to split a text into sentences, which is not trivial - using explode(".", $string) does often not give good results.
Search Stackoverflow for "php split sentence", or directly try the solution to PHP: Parse document / text into sentences :
http://www.zubrag.com/scripts/text-splitter.php
Once you have an array with sentences, use
echo '<p>' . implode('</p><p>', $sentences) . '</p>';
to echo them out.
In the following code, I need to remove <div class="grid_8"></div>.
They will always be at the start and finish of my string, for example:
<div class="grid_8"><img src="http://rps.sanscode.com/site/assets/media/images/rps_mini_logo.png" border="0" alt="Rapid Print Solutions" style="margin-bottom: 30px;" />
<h1></h1>
</div>
What is a suitable regex for preg_replace to remove it? 8 can be any number between 1 and 16.
Thanks
Jason
#Amjad...
Here is my code
public function fix_grid(){
$result = db::query("select * from sc_content_components where component_value_1 like '%grid_%'")->fetchAll(PDO::FETCH_ASSOC);
foreach($result as $item){
$json = json_decode($item['component_value_1']);
if(is_null($json)) continue;
$x = reset($json);
echo htmlspecialchars($x);
echo "<p>=======================<b>Changes to: </b></p>";
$patterns = array('/^<(div)((?:\s+\w+(?:\s*=\s*(?:(?:"[^"]*")|(?:\'[^\']*\')|[^>\s]+))?)*)\s*(\/?)>/'
, '/<\/(\div+)[^>]*>$/');
$x = preg_replace($patterns, array('',''), trim($x));
echo htmlspecialchars($x);
echo "<hr>";
$json[0]=$x;
// $ne['component_value_1'] = json_encode($json);
// db::where('component_id', $item['component_id']);
// db::update('sc_content_component', $ne);
}
}
I'm using the regex below (#Amjad Masad) and it doesn't remove the last div.
As you can see I am using trim and it doesn't seem to work
For the stated problem, this is the solution:
Edit: expanded regex =
/^\s*<div\s (?:".*?"|\'.*?\'|[^>]*?)*
(?<=\s)class\s*=\s*(["\'])\s*grid_(?:1[0-6]|[1-9])\s*\1
(?:".*?"|\'.*?\'|[^>]*?)*
>
(.*)
<\/div\s*>
\s*$/xs
replacement = "$2"
For the open
$patterns = array('/^<(div)((?:\s+\w+(?:\s*=\s*(?:(?:"[^"]*")|(?:\'[^\']*\')|[^>\s]+))?)*)\s*(\/?)>/'
, '/<\/div[^>]*>$/');
preg_replace($patterns, array('','');, trim($htmlString));
Somewhat simpler.
If the 1 to 16 is significant and part of a greater range...
$match = preg_replace("/^<([^>]*)grid_(1[0-6]|[1-9])([^>\d]*)>(.+)<([^>]*)>$/s","$4",trim($str),-1,$hmany);
if($hmany){
echo "$match <br>";
}else{ echo "No match found! <br>"; }
If the 1 to 16 is the only possible range and therefore irrelevant...
$match = preg_replace("/^<([^>]*)>(.+)<([^>]*)>$/s","$2",trim($str),-1,$hmany);
if($hmany){
echo "$match <br>";
}else{ echo "No match found! <br>"; }
Regards.