store a node into (object) into an array - php

Question

I've this piece of code, it retrieves a node from my node type 'Student'.
I try different things to, save all values in '$node' into an array. But $node is a object.
My question is how doe I store 'all' values in $node into a array. In Java an C# it's simpler to do that.
$results = db_query(db_rewrite_sql("SELECT nid FROM {node} WHERE type =
'student'"));
while($nid = db_result($results)) {
$node = node_load($nid);
// Do something with $node
}
in java or c# you can say in a for/foreach/while 'loop'
String item[] = null;
for(int i = 0; i<=myNode; i++) {
item.add(myNode[i]); // the item and value UgentID, name student, location student are been stored in item array.
}
I don't know if PHP has that too. "yourObject.Add(otherObject)"

Answer 1

The following let's your object behave (access-wise) as an array:
$result = new ArrayObject( $node );
If you truly want an array, simply cast it afterwards:
$result = (array) $result;
Heck, come to think of it, you could even simply do:
$result = (array) $node;
:-)
Both methods of casting to array will actually expose protected/private properties as well, I just found out. :-S Horrible.
edit:
// initiate array
$nodes = array();
while($nid = db_result($results)) {
// either do one of the following, to push
$nodes[] = node_load($nid);
// or:
array_push( $nodes, node_load($nid) );
// Do something with $node
}