I am looking for some help with jFormer.
The way my site works a form cannot submit to the same place it was built,
yet looking at the demo code it seems that this is how it has to work?
Is this true?
No guarantees as I am unable to test it myself, but you could try:
$contactForm = new JFormer('contactForm', array('action' => 'my_page.php'));
Items added into the array passed to the JFormer constructor are supposed to be added as attributes to the form tag from what I can see in the code. See https://github.com/kirkouimet/jformer/blob/master/source/development/php/JFormer.php
Update
Actually it looks like I was looking at the incorrect class as they have two classes in the JForm.php file when you would expect there to only be the actual JFormer class in there. They have a JFormElement class at the top of the file! Still I cannot readily see if it might still work or not.
The documentation is lack lustre and the inline comments are worse.
Related
I came from CakePHP and just started playing with Django framework. In CakePHP, I have the habit of printing out all the returned array using pr() straight out to the webpage. For example:
A controller spits out a $result to a View, I use pr($result) and it will print out everything right on the webpage so I know how to travel through $result from my View.
A form POST a $request to a Controller, I use pr($request) to see what is sending in before processing it in the Controller. The content of $request will be displayed immediately on the webpage right after I hit Submit the form.
I'm wondering if I could do the same thing in django instead of going to the shell and try pprint (or could I just use pprint to print out to the web???)
This is a really simple example about what I'm talking about:
app_name/views.py:
def detail(request, soc_id):
soc = get_object_or_404(Soc, pk=soc_id)
return render(request, 'socs/detail.html', {'soc': soc})
How can I just view clearly what is in "soc". In cakephp, I could just pr($soc) right there and it will be displayed right on the detail.html page.
I have tried this and it didn't work (I'm sure it's basic but i'm just new to this)
import pprint
def detail(request, soc_id):
soc = get_object_or_404(Soc, pk=soc_id)
pprint.pprint(soc)
return render(request, 'socs/detail.html', {'soc': soc})
I have spent two days doing research but I couldn't find the answer. I'm hoping one of you can help this newbie out.
The way you're trying to print will show the print in the terminal that is running your Django server. If you just need to see it quick, check there.
If you want to output the value on to the rendered page, you'll have to include it in the template using template tages. It looks like you send {'soc': soc} to your template as context. Because of this, you should be able to use it in your template. So, in your template (socs/detail.html), just add {{ soc }} somewhere and it should print out the value. The template has full access to the object, so if you wanted something specific, you can also print that instead (like {{ soc.id }}).
If you want to see everything that's in the object without specifying all of the different fields yourself, send OBJECT.__dir__. For example, for this you'd send {'soc': soc.__dir__} as your context. Keep in mind that this likely should not be used for anything but inspection on your part.
If you'd like to learn more about Django's templating, check out the syntax and more.
To put my question into context, I'm working on an entirely static website where 'post' pages are created by myself manually - there's no CMS behind it. Each page will require a <pre> <code> block to display code as text in a styled block. This could be very few - several which is why I'm trying to do this for ease.
Here's what I've done -
function outputCode($code) {
return "<pre class='preBlock'><code class='codeBlock'>".htmlentities($code)."</code></pre>";
}
The code works as expected and produces an expected outcome when it's able to grab code. My idea is to somehow wrap the code for the code block with this function and echo it out for the effect, fewer lines and better readability.
As I'm literally just creating pages as they're needed, is there even a way to create the needed code blocks with such function to avoid having to manually repeat all the code for each code block? Cheers!
EDIT:
I was previously using this function and it was working great as I was pulling code from .txt documents in a directory and storing the code for code blocks in a variable with file_get_contents(). However, now, I'm trying to get the function to work by manually inputting the code into the function.
Well. Wrapping the function input in ' ' completely slipped my mind! It works just fine now!
If I understand correctly, you want to re-use your outputCode function in several different PHP files, corresponding to posts. If yes, you could put this 1 function in its own file, called outputcode.php for example, and then do
include "outputcode.php";
in every post/PHP file that needs to re-use this function. This will pull in the code, from the one common/shared file, for use in each post/PHP file that needs it. Or maybe I'm misreading your last paragraph :(
Can you put PHP anywhere in a file? Inside tags and quotes? For example, is something like this guaranteed to work (even though it isn't always recognized by an IDE's syntax highlighter):
<tr><tbody <?php if(!$row) echo "style='display: none;'"; ?>>
<!-- stuff that we only want to show if $row exists -->
</tbody></tr>
Or for example:
<a href="http://www.google.com/search?q=<?= echo $searchTerm; ?>"</a>
I know I can test this sort of thing on my machine, but I'm wondering if it is guaranteed/defined behavior and if there are any edge cases that don't work that I've missed.
Also, is there good reason not to do this? Is it dangerous because the next person looking at the code might miss it? Should I put a comment in? Does having to add a comment defeat the purpose of this method - succinctness?
Yes you can put the php tags anywhere in the page (html) there is no stopping you on that.
If we go under the hood, your web server sends the code to the php interpreter via a handler and merges the output with your static html file and sends the merged file as the response.
To add to my answer, developers usually go for MVC based frameworks so that the php code inside html page is restricted to only printing the variables and the business logic is performed in the controllers. I personally prefer CakePHP. Apart from that you might not want to put code that manipulates session or performs redirection between html tags else you will recieve the headers already set error as you have already printed certain html code before modifying the headers.
Is there a plugin for Notepad++ which would allow me to see functions including parameters/returns as I type?
For example, if i type "implode(", I'd see:
string implode ( string $glue , array $pieces )
Update: Wow, I'm surprised so many other people were as interested in this as me. The take-home lesson for me was to always explore all the Settings options!
You don't need a plugin! 5.0 and above have this already.
Go to Settings -> Preferences, then go to the Backup/Auto-Completion tab, and you'll find it at the bottom! Check the box for function parameters hint as well.
You'll get exactly what you've asked for, as long as it knows the file is PHP.
maybe, plugin Auto completion for custom PHP classes (ACCPC) is what you're mean.
basic info:
Show an overview over your classes' attributes & methods in a nice popup!
A popup window appears after typing the "->" or "::" behind a class or an instantiated object variable which displays all attributes and methods of it's class.
more information:
http://sourceforge.net/projects/accpc/
maybe this answer can helpful too:
Get parameter hints from Editing the API XML file
https://stackoverflow.com/a/12609240/2427906
You can read about it in Notepad++'s documentation site found here
http://npp-community.tuxfamily.org/
The auto complete section can be found here
http://npp-community.tuxfamily.org/documentation/notepad-user-manual//editing/auto-completion
Heads up: I dont have the possibility to rename the classes or use name spaces for this.
Im looking for any crazy way to subvert class redeclaration issues in php. I actually only need 3 static variables from a web application, but the only way to get them requires including a file that declares a user class. However I already have a user class, so I get an error.
I tried to no avail to include the file in a class hoping it would isolate the included file - But no.
I tried reading an interface file I created that just echos the 3 values, but that actually just reads the php code and not the rendered values.
Is there anything like an opto-isolation system for code?
The only think I can think of is using ajax to do it, but it seems super sketchy. Is there a plain php version of this?
(Was a comment, but got too long.) Doesn't sound doable with your constraints. (You might need to show some code.) -- But if you are asking for a crazy way, and the option to rename the classes just applies to not editing the php script, then:
Load the include file into a variable, then transform it, and finally eval:
$source = file_get_contents("user.php");
$source = str_replace("class user", "class workaround_123", $source);
eval($source); // will give you a workaround_user instead of class conflict
Someone will probably comment on the advisability of eval... But it foremost depends on your code/situation if that's an applicable wacky workaround.
Alternatively you could invoke the user fetching code with a separate PHP process :
exec("QUERY_STRING=user=123 php-cgi user.php");
You could tokenize the whole file and go through it "by hand" to find the values you need.