(PHP) Checking items in an array - php

Question

I have an array like this:
Array(a,b,c,a,b)
Now, if I would like to check how many instances of "b" I can find in the array, how would I proceed?

Answer 1

See the documentation for array_count_values(). It seems to be what you are looking for.
$array = array('a', 'b', 'c', 'a', 'b');
$counts = array_count_values($array);
printf("Number of 'b's: %d\n", $counts['b']);
var_dump($counts);
Output:
Number of 'b's: 2
array(3) {
["a"]=> int(2)
["b"]=> int(2)
["c"]=> int(1)
}

Answer 2

Use array_count_values($arr). This returns an associative array with each value in $arr as a key and that value's frequency in $arr as the value. Example:
$arr = array(1, 2, 3, 4, 2);
$counts = array_count_values($arr);
$count_of_2 = $counts[2];

Answer 3

You can count the number of instances by using this function..
$b = array(a,b,c,a,b);
function count_repeat($subj, $array) {
for($i=0;$i<count($array);$i++) {
if($array[$i] == $subj) {
$same[] = $array[$i]; //what this line does is put the same characters in the $same[] array.
}
return count($same);
}
echo count_repeat('b', $b); // will return the value 2

Answer 4

Although there are some fancy ways, a programmer should be able to solve this problem using very basic programming operators.
It is absolutely necessary to know how to use loops and conditions.
$count = 0;
$letters= array("a","b","c","a","b");
foreach ($letters as $char){
if ($char == "b") $count = $count+1;
}
echo $count.' "b" found';
NOT a rocket science.