Hello every one i have a problem with mysql dbms i never had a date storage in this format yyyy-mm-dd i always have it in this format dd-mm-yyyy i used this methode to change the date format while inserting data but it does not work
function dateConvert($dateInser) {
$dateTime = new DateTime($dateInser);
$dateFormate=date_format ( $dateTime, 'Y-m-d' );
return $dateFormate;
}
is there any solution ?
The DateTime constructor also expects specific formats, and I doubt dd-mm-yyyy is one of them. First parse your dd-mm-yyyy date to transform it into a DateTime object, and then format this DateTime object using the yyyy-mm-dd format :
$dateTime = date_create_from_format('d-m-Y', $dateInser);
$dateFormate = date_format($dateTime, 'Y-m-d');
Related
I'm trying to save events into my table that contain date_start and date_end timestamps. From another PHP page, I get four inputs: two date inputs and two time inputs. I'm trying to insert these values but I keep getting the following value on inserting it:
0000-00-00 00:00:00
Here's my script:
$rep=$bdd->query('SELECT * FROM association WHERE nom="'.$_SESSION['usertag'].'"');
$data=$rep->fetch();
$debut="\'".$_POST['date_start']." ".$_POST['time_start'].":00\'";
$fin="\'".$_POST['date_end']." ".$_POST['time_end'].":00\'";
$debut=date('Y-m-d H:i:s');
$fin=date('Y-m-d H:i:s');
$timestamp_debut =strtotime($debut);
$timestamp_fin = strtotime($fin);
$req=$bdd->query('INSERT into evenement values (NULL,'.$_POST['name'].','.$_POST['content'].',\''.$timestamp_debut.'\',\''.$timestamp_fin.'\','.$data['id'].')');
PHP's strtotime() outputs a Unix timestamp. If your database column type is DATETIME, a Unix timestamp is not the correct format. You can just insert the formatted date() string.
For example:
strtotime(date('Y-m-d H:i:s'))
1562117846
date('Y-m-d H:i:s')
2019-07-02 21:36:40
For MySQL:
MySQL recognizes DATETIME and TIMESTAMP values ... [a]s a string in either 'YYYY-MM-DD hh:mm:ss' or 'YY-MM-DD hh:mm:ss' format. A "relaxed" syntax is permitted here, too: Any punctuation character may be used as the delimiter between date parts or time parts. For example, '2012-12-31 11:30:45', '2012^12^31 11+30+45', '2012/12/31 11*30*45', and '2012#12#31 11^30^45' are equivalent.
String and Numeric Literals in Date and Time Context
However, it seems that you're using the current timestamp when you might want to use the values posted from your form. PHP's date() uses "the current time if no timestamp is given".
If you want to use your posted values instead, you can indeed use strtotime() to convert them to Unix timestamps and then date() to format them.
$date = '2019-07-02';
$time = '15:28';
date('Y-m-d H:i:s',strtotime($date.' '.$time));
2019-07-02 15:28:00
Alternatively, I might recommend using PHP's DateTime class:
$date = '2019-07-02';
$time = '15:28';
$datetime = new Datetime($date.' '.$time);
echo $datetime->format('Y-m-d H:i:s');
2019-07-02 15:28:00
I am using DateTime function of php. I get a date from a calendar in format d-m-Y and pass it via ajax to my function. I am getting the date right till this step.
When I try to store the date in unix format using:
$ai_ff_date=DateTime::CreateFromFormat('d-m-Y', $data['date']);
$final_date=$ai_ff_date->format('U');
The date stored is wrong. Suppose the date I passed via ajax is 26-12-2016 then in database 27-12-2016 is stored. Why its counting one more day then the input.
use this code :
$date = date('Y-m-d H:i:s', strtotime('-1 day', $stop_date));
$ai_ff_date=DateTime::CreateFromFormat('d-m-Y',$date);
$final_date=$ai_ff_date->format('U');
and please check the variable (code not tested)
You might want to convert the Date-Format to "Y-m-d" First and then call-in the DateTime() Constructor. However, since what you are trying to do is just get the TimeStamp you might also do that directly without using DateTime. The Snippet below shows what is meant here:
<?php
$data = ['date'=>"13-12-2016"]; //<== JUST AN EXAMPLE FOR TESTING!!!
// SIMPLY CONVERT THE DATE TO Y-m-d FIRST.
$dateYMD = date("Y-m-d", strtotime($data['date']));
// THEN USE DateTime CONSTRUCTOR TO CREATE A NEW DateTime INSTANCE
// AND THEN RUN THE FORMAT YOU WISH::
$final_date = (new DateTime($dateYMD))->format('U');
var_dump($final_date); //<== YIELDS: string '1481583600' (length=10)
var_dump(date("Y-m-d", $final_date)); //<== YIELDS: string '2016-12-13' (length=10)
I'm trying to insert a time written in h:mm am/pm format into a database that is stored as standard DATETIME format ( hh:mm:ss ) but I can't figure out how to convert the posted time into standard format so the database will accept it.
This is what I've been trying so far:
$title = $_POST['inputTitle'];
$date = $_POST['inputDate'];
$time = date('h:i:s a', strtotime($_POST['inputTime']));
$desc = $_POST['inputDesc'];
//msql query to insert data
$query = "INSERT INTO events(title, date, time, description) VALUES ('$title','$date','$time','$desc')";
but this doesn't work(time still won't submit) any ideas?
You should use TIME type not DATETIME type.
DATETIME format is: yyyy-mm-dd hh:ii:ss
DATETIME format
TIME format is: hh:ii:ss
TIME format
I have a loop and in it the date is coming in different formats like for some values it will be like '10-13-2013 04:31' and for some it is like '2013-10-14T22:14:40-0700'. I tried to store this in DB as the value of a datetime/timestamp column but it is failing for the first format that is 10-13-2013 04:31. So I tried to convert it into UNIX timestamp using strtotime(). It is working for some values and is storing zero for values like '10-13-2013 04:31'. I think this is because it is considering the second value as month and so failing. My code is as follows :
foreach($reports as $report){
echo strtotime($report->transactionDate);
}
strtotime() is unable to parse mm-dd-yyyy format. Instead you should use DateTime::createFromFormat(), like this:
$date = '10-13-2013 04:31';
$obj = DateTime::createFromFormat('m-d-Y H:i', $date);
$date = $obj->format('Y-m-d H:i:s');
I cannot seem to find any info on this..
I need to convert a string to a date so that it will import properly to an SQL DATE field. When I import 12/25/2012 to the DB, it appears as 0000-00-00.
What's the proper way to do this?
Links and refs appreciated.
MySQL accepts dates in this format YYYY-MM-DD either change your date format 12/25/2012 to 2012-12-25 or modify them to match the correct format.
EDIT
If you want to continue using your own format try this
list($d,$m,$y) = explode("/", "12/25/2012"); //replace 12/25/2012 with your date
$hyphenDate = $y . '-' . $m . '-' . $d;
echo $hyphenDate;
As #Ravi pointed out in his answer, MySQL accepts dates in the format YYYY-MM-DD. Quoted from 11.1.5. Date and Time Types1:
Although MySQL tries to interpret values in several formats, date
parts must always be given in year-month-day order
For this, you can use str_todate()2 function to format it:
str_to_date('12/25/2012', '%m/%d/%Y);
SQL Fiddle Demo
This way, these input strings will be stored in your database as date objects(without any specific date format). Later, if you want to output these dates in a specific format you can use DATE_FORMAT3 to format it. Something like:
SELECT DATE_FORMAT(datefield, '%Y-%m-%d') FROM Test;
--2012-12-25
1, 2, 3: Links and refs, that you asked for.
Use class DateTime. Examples:
$SomeDate = new DateTime();
echo $SomeDate->format( 'Y-m-d H:i:s' ); //Must be MySQL compatible (YYYY-MM-DD)
$ThisDate = new DateTime( date( 'Y-m-d H:i:s' ) );
echo $ThisDate->format( 'Y-m-d H:i:s' ); //Must be MySQL compatible (YYYY-MM-DD)