PHP help with styling content from a database - php

I'm new to PHP as building a site for my company as a college project. I'm looking to style and split the text into two columns on the following page... http://c-hall.the-word.com/assignment/artwork.php Was wondering the best way to go about this. I get that some of this will be done using CSS, but as the text is pulled in from a database how do I split this into two columns? As for styling am I right in using for example <h1> tags etc in the text on the database?
Thanks for your help - Charley

In what format is the text that you retrieve from the database? Here is a semi-pseudo-code that shows how to retrieve text from db and show it in two columns:
echo "<table>";
$result = mysql_query(...)
while($row = mysql_fetch_assoc($result))
{
echo "<tr><td>" . $row['lefttext'] . "</td><td>" . $row['righttext'] . "</td></tr>";
}
echo "</table>";
Still we can't help you until we know in what format the retrieved text is.

Related

How do I get custom PHP to use existing CSS styling in Wordpress

I am using woody snippets to insert php code to make an API call to return information in a table. How do I get the table to display using the default css from my wordpress theme?
I am new to PHP, but not to wordpress. And I know just enough CSS to get myself in trouble. So, I need ELI5 instructions.
My programmer provided the basic PHP code to call the API and return the data in a basic table. But, it looks horrid and there's no spacing or styling.
$tableStart = "<table>";
$tableEnd = "</table>";
$trStart = "<tr>";
$trEnd = "</tr>";
$tdStart = "<td >";
$tdEnd = "</td>";
$fname = 'alabama_energy_data.json';
$data = json_decode(file_get_contents($fname));
echo $tableStart;
foreach($data as $bill_data)
{
echo $trStart;
echo $tdStart . $bill_data->bill_id . $tdEnd . $tdStart . $bill_data->title . $tdEnd;
echo $trEnd;
}
echo $tableEnd;
This returns a basic table with the data I need, but it's not styled. How do I get it to use the default CSS from our wordpress site that it's displaying in so that the table renders in a format that looks decent?
If your table isn't styled like it should be, then you're probably missing and id or class attribute at your table. You could check on what current attributes your "wordpress" tables have, and just add them to your table.
Example:
<table class="wp-class-table">
# OR
<table id="wp-id-table">
And one other thing, I personally don't really like the way you "echo" your data. If you want, you can read this answer. It shows a nicer way to do it in my opinion.

html_entity_decode nesting php

running php 5.6.29 here.
Processing about 6,000 rows of data from a MYSQL Table. Looking at the HTML Description column and making changes. Using html_entity_decode to show the changed result in the Browser.
The problem is, each row is displaying the HTML result nested inside the previous row, which makes the display impossible. Obviously I want each row to have a clean break. As these are tables, it seems not to break?
while ($row = mysqli_fetch_array($result))
{
$i++;
echo "<br>$i";
echo "<br>Product: ".$row['id'];
echo "<br>Title: ".$row['title'];
echo "<br>";
$a = $row['html'];
echo "htmlspecialchars_decode($a)";
//...change the html process here ...
$b = html_entity_decode($row['html']);
echo "<br><br><br>".$b;
echo "<br>";
echo "<br>";
echo "<br>";
echo "<br>";
}
I checked this in multiple browsers, so it's not just Chrome. Basically I somehow need to close the HTML before I move onto the next row right? Or is this some kind of limitation or bug? tia.

build link using postgresql and php

)
I have a question:
I have a databse with the following information:
Name of report [name]
Link to report [link]
The various reports are displayed in tables in my page (using db_tables filed with static, month, week etc)
But i want to generate a link to the report based on "link" and "name"
so i set up a pgsql query :
result = select name, link from db where type = 'week'
This works fine.
To display the above i have:
echo "<div id=\"selMaand\">" ;
echo "<table id = \"t2\">\n ";
echo "\t<tr class=\"head\">\n";
echo "<th colspan=\"2\">Select Maand</th>";
while ($line = pg_fetch_array($result5, null, PGSQL_ASSOC)) {
echo "\t<tr>\n";
foreach ($line as $col_value) {
echo "\t\t<td width=\"100%\">$col_value</td>\n";
}
echo "\t</tr>\n";
}
echo "</table>\n";
echo "</div>";
which works fine to.
Now, the link from database is http://192.168.178.1:8080/etc/etc/page.html"onclick humptydumpty>name
each time i want to adjust something in either the onlclick or address, i have to change all my links.
What can i insert in my querys so i will be able to build a link like;
echo "<a href = "http://192.168.178.1:8080/etc/etc/**$link**"onlclick humptydumpyu>**$name**</a>
I cant figure out how to break down my array!
Thanks in advance
Sjoerd
If you just need a portion of your URL in the database (i.e. only a portion of it would change for each record), then only store that portion of the URL in the database. You can then generate the remaining portion of the URL (call it the URL base) in your code.
So something like this:
define('URL_BASE', 'http://some.url.base/that/you/can/change/globally/');
Then you get the remaining piece of the URL from the database for each item. So you would have something like this inside your query loop to build the full URL.
$link = $line['link'];
$final_url = URL_BASE . $link;
As far as the onclick stuff goes, I would have that set sepearately as well, since I assume the onclick behavior is not dependent on the individual link (if it is you can make a separate DB column for it).
define('LINK_ONCLICK', 'onclick="some_onclick_function()"');
And in your query loop you can put this together like this:
$name = $line['name'];
$link = $line['link'];
$final_url = URL_BASE . $link;
echo '<a href="' . $final_url . '" ' . LINK_ONCLICK . '>' . $name . '</a>';
Note that it is not really necessary to define the strings for the url base and onclick behavior as constants. I just showed it this way as it is common practice to set globally defined values that do not need to change at run-time ion such a manner.

Hyperlink across table cells?

I am trying to create a hyperlink from two pieces of text split over two cells in a table row.
I am generating my table using PHP to echo out the results from my database to a table.
When it echo's it generates a hyperlink with GET variables at the end which allow the user to visit a page relevant to that information.
The problem is that I can't seem to generate a hyperlink that will go across those table cells, I have looked around the web and there is nothing that says I cannot do this.
As you can see from the screenshot below I am generating a hyperlink inside one table cell but I want the other table cell to have the same hyperlink.
Code
while ($row = $db->fetch_assoc($newest))
{
echo "<tr>";
echo "<td>";
echo "<a href='manager.php?method=view&id=".$row['id']."'>".$row['first_name']." ". $row['second_name']. "</td><td>".$row['company_name']."</a>";
echo "</td>";
echo "</tr>";
}
I have a feeling that I will just have to generate two separate hyperlinks for the table cells.
However I am hoping someone here can prove me wrong and save me a few lines of code.
Thanks :)
Using native hyperlinks, you will have to create separate wrappers for each cell.
However, if you want to use JS for linking and redirecting, you could do something like:
.....
<tr class="clickable" data-href="http://google.com">
<td>cell-1</td>
<td>cell-2</td>
<td>cell-3</td>
</tr>
....
and then:
$(function(){
$('tr.clickable').click(function(){
window.location.href = $(this).attr('data-href');
});
});
Simply work around it with JS:
echo "<tr onclick=\"location.href='manager.php?method=view&id=".$info.";'\">";
If you do not want to break the table structure (ie. putting the name and the company into one (multi-column) cell), there is IMHO no way other than generating two hyperlinks.
What you might want to do is to use some CSS for a hover effect and some JavaScript to register a user clicked on a cell (which you can, given the structure above, associate with the tr element).
You can not do it like this. Try instead:
while ($row = $db->fetch_assoc($newest))
{
$url = "manager.php?method=view&id=".$row['id'];
echo "<tr>";
echo "<td>" . $row['first_name']." ". $row['second_name']. "</td>";
echo "<td>" . $row['company_name'] . "</td>";
echo "</tr>";
}
while ($row = $db->fetch_assoc($newest))
{
echo "<tr>";
echo "<td>";
echo "<a href='manager.php?method=view&id=".$row['id']."'>".$row['first_name']." ". $row['second_name']."</a></td><a href='manager.php?method=view&id=".$row['id']."'>".$row['company_name']."</a><td></td>";
echo "</td>";
echo "</tr>";
}

return json string with html characters?

i want to call a php with jquery ajax to perform some database things and then return 2 lists of links. so i have to pass these two link lists back to jquery so it can display list 1 in the left side of the webpage and list 2 in the right side.
i created the lists in separate arrays that i send back to jquery with json_encode but i noticed that it escapes all the html characters.
<a>dog</a> became <a>dog<\/a>
so when i displayed the list in the html they werent links anymore.
how can i preserve the html codes in my returned arrays to jquery?
EDIT: is this the right way to go if you want to split up data from php so that jquery can display them in different locations in html?
// list 1
while($row = mysqli_fetch_assoc($saved_tags))
{
$display_saved_tags[] = "<a id='showtag' href='answer.php?id=" . $row['id'] . "'>" . $row['name'] . "</a><br />";
}
// list 2
while($row = mysqli_fetch_assoc($related_tags))
{
$display_related_tags[] = "<a id='showtag' href='answer.php?id=" . $row['id'] . "'>" . $row['name'] . "</a><br />";
}
// return lists to jquery
echo json_encode('display_saved_tags' => $display_saved_tags, 'display_related_tags' => $display_related_tags));
json_encode's escape characters directly conflict with HTML output. I have had the same issue but decided to use an alternative solution at the time. I just had a thought that you could perhaps do this:
$data = new stdClass();
$data->html1 = base64_encode('<h1>html in here</h1>');
$data->html2 = base64_encode('<p><strong>more html</strong></p>');
echo json_encode($data);
On the frontend:
callbackFunction(json) {
alert(base64_decode(json.html1));
alert(base64_decode(json.html2));
}
You would need the javascript implementations of base64_decode and utf8_decode which can be found at:
http://phpjs.org/functions/base64_decode:357
use can use below function to un-escape the chars when reading or sending on to the browser:
html_entity_decode('your response here');
Also because your are using json_encode, make sure that you don't need the below function in your code:
json_decode

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