I want to know how to get the original URL from php
For example:
example.php
<?php
header('location:test.php');
?>
I want to get test.php from example.php.
example.php
<?php
header('location:' . $_SERVER['HTTP_REFERER']);
?>
This should work fine.
Redirection with some delay say after 5 sec wait.
function js_redirect($url, $seconds)
{
echo "<script language=\"JavaScript\">\n";
echo "<!-- hide code from displaying on browsers with JS turned off\n\n";
echo "function redirect() {\n";
echo "window.parent.location = \"" . $url . "\";\n";
echo "}\n\n";
echo "timer = setTimeout('redirect()', '" . ($seconds*1000) . "');\n\n";
echo "-->\n";
echo "</script>\n";
return true;
}
js_redirect("http://www.exapmle.com",5); // Redirect after 5 sec
you forget to use
ob_start();
in first of your code :D
elsewhere you can use js in this case , for example :
echo 'javascript:window.location="http://example.com";';
Related
I have just a quick question. i was using a normal html link tag to redirect to a paypal checkout page and it was working fine even when i had php inside the url. but when i was using it in a php header
the url cuts off where i enter the php.
header('location: https://www.paypal.com/cgi-bin/webscr?cmd=_xclick&business=XXXX&lc=UK&item_name=<? echo $product . " " . $server ?>&amount=<? echo $xprice1; ?>%2e00¤cy_code=GBP&button_subtype=services&no_note=0&bn=PP%2dBuyNowBF%3abtn_buynowCC_LG%2egif%3aNonHostedGuest');
You are placing the PHP code inside of the location redirect as a string. The code is not being evaluated as PHP.
Try this instead:
<?php
$url = "https://www.paypal.com/cgi-bin/webscr?cmd=_xclick&business=XXXX&lc=UK&item_name=" . $product . " " . $server ."&amount=" . $xprice1 . "%2e00¤cy_code=GBP&button_subtype=services&no_note=0&bn=PP%2dBuyNowBF%3abtn_buynowCC_LG%2egif%3aNonHostedGuest";
header('location: ' . $url);
Or, you could keep it in one line like so:
<?php
header('location: ' . "https://www.paypal.com/cgi-bin/webscr?cmd=_xclick&business=XXXX&lc=UK&item_name=" . $product . " " . $server ."&amount=" . $xprice1 . "%2e00¤cy_code=GBP&button_subtype=services&no_note=0&bn=PP%2dBuyNowBF%3abtn_buynowCC_LG%2egif%3aNonHostedGuest");
header('location: https://www.paypal.com/cgi-bin/webscr?cmd=_xclick&business=XXXX&lc=UK&item_name=<? echo $product' . " " . '$server ?>&amount=<? echo $xprice1; ?>%2e00¤cy_code=GBP&button_subtype=services&no_note=0&bn=PP%2dBuyNowBF%3abtn_buynowCC_LG%2egif%3aNonHostedGuest');
This may solve your problem. Please dont forget to tick the answer right if it works.
i built a CMS and my image shows succesfully in the admin page(back-end) once i upload an image with the form but once on the main index page(front-end) it shows that "broke image link"
here is my function to post the uploaded image on my admin page:
function gettestimony() {
$query = mysql_query("SELECT * FROM testimony") or die(mysql_error());
while($post = mysql_fetch_assoc($query)){
echo "<img src =\"" . $post['photo']."\">";
echo "<p>" . $post['imagename'] . "</p>";
echo "<br>";
echo "<p>" . $post['test'] . "</p>";
echo "<br>";
echo "<p>" . $post['author'] . "</p>";
echo "<br>";
echo "Delete";
echo "Edit";
echo "<br>";
}
}
and the directory is htdoc/blah/admin/include/functions.php
and the image is saved in htdoc/blah/admin/image/
for my main index, this is the function to post it:
function gettestimony() {
$query = mysql_query("SELECT * FROM testimony") or die(mysql_error());
while($post = mysql_fetch_assoc($query)){
echo "<div class='column second'>";
echo "<p>" . $post['test'] . "</p>";
echo "<img src =\"" . $post['photo']."\">";
echo "</div>";
}
}
this is the code i use in both functions:
echo "<img src =\"" . $post['photo']."\">";
so like i said it works fine in admin page but my main page it doesn't....someone please help
Your image's path relative to the path of your function is irrelevant. As far as that function is concerned the path to the image is just a string.
You need to make sure the path to the image is correct relative to the HTML file that's viewing it. The easy way to make it work is to just use the full URL to the image:
www.something.com/admin/images/myimage.php
Hi I want to show URL as a link in PHP the URL is shown by query from database but it is not a link so I want to make it link like using but I don't know what I am doing wrong
My data show like this in browser
ID Name URL
2 This localhost/p_uploads/00.jpg
3 Nissan localhost/p_uploads/7a.jpg
I want these URL's to be link so anyone can click on the url to open the image
Here is my PHP Code:
<?php
if(!isset($_COOKIE['loggedin'])){
header("location:index.php");
}
session_start();
if(!isset($_SESSION['user'])){
header("location: index.php");
}
else {
?>
<?php
$con=mysqli_connect("localhost","root","123","user");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"Select * from private_uploads where username = '".$_SESSION['user']."'")
or die(mysql_error());
echo "<table border='1'>
<tr>
<th>ID</th>
<th>Name</th>
<th>URL</th>
</tr>";
while($row = mysqli_fetch_array($result, MYSQL_ASSOC))
{
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['Name'] . "</td>";
echo "<td>",'<a href=' . $row['Link'] . '></a>',"</td>";
echo "</tr>";
}
echo "</table>";
//Views Counter
mysqli_close($con);}
?>
<?php
$url = htmlspecialchars($_SERVER['HTTP_REFERER']);
echo "<a href='$url'>back</a>";
?>
replace
echo "<td>",'<a href=' . $row['Link'] . '></a>',"</td>";
for this
echo '<td>[a name here would be nice]</td>';
you are missing the "" in the generated href
You're producing links that look like this:
That's both an invalid URL (unless you really do have a localhost/p_uplaods folder) and a link with no body, so you'll never see it.
If you want to access localhost the host, and not the folder, you should use use an absolute path on the current host, /p_uploads/00.jpg, or a fully qualified URL: http://localhost/p_uploads/00.jpg.
Your link looks like this:
It doesn't have a HTTP protocol. The link should look like this:
You might have a problem on this line:
echo "<td>",'<a href=' . $row['Link'] . '></a>',"</td>";
As you are referring to Link whereas in your database the column is called URL. Also add a text to the tag:
echo '<td>View</td>';
For example if I had the script:
<?php
$page = "My Page";
echo "<title>" . $page . "</title>";
require_once('header.php');
require_once('content.php');
require_once('footer.php');
?>
Is there something I can add to the bottom of that page to show the entire pre-compiled php?
I want to literally echo the php code, and not compile it.
So in my browser I would see the following in code form...
// stuff from main php
$page = "My Page";
echo "<title>" . $page . "</title>";
// stuff from require_once('header.php');
$hello = "Welcome to my site!";
$name = "Bob";
echo "<div>" . $hello . " " . $name . "</div>";
// stuff from require_once('content.php');
echo "<div>Some kool content!!!!!</div>";
// stuff from require_once('footer.php');
$footerbox = "<div>Footer</div>";
echo $footerbox;
Is this possible?
There's no way to do it native to PHP, but you could try to hack it if you just wanted something extremely simplistic and non-robust:
<?php
$php = file_get_contents($_GET['file']);
$php = preg_replace_callback('#^\s*(?:require|include)(?:_once)?\((["\'])(?P<file>[^\\1]+)\\1\);\s*$#m', function($matches) {
$contents = file_get_contents($matches['file']);
return preg_replace('#<\?php(.+?)(?:\?>)?#s', '\\1', $contents);
}, $php);
echo '<pre>', htmlentities($php), '</pre>';
Notes:
Warning: Allowing arbitrary file parsing like I've done with the fist line is a security hole. Do your own authentication, path restricting, etc.
This is not recursive (though it wouldn't take much more work to make it so), so it won't handle included files within other included files and so on.
The regex matching is not robust, and very simplistic.
The included files are assumed to be statically named, within strings. Things like include($foo); or include(__DIR__ . '/foo.php'); will not work.
Disclaimer: Essentially, to do this right, you need to actually parse the PHP code. I only offer the above because it was an interesting problem and I was bored.
echo '$page = "My Page";';
echo 'echo "<title>" . $page . "</title>";';
echo file_get_contents('header.php');
echo file_get_contents('content.php');
echo file_get_contents('footer.php');
For clarity I'd put the title generation in it's own file, then just use a series of echo file_get_contents()...
echo file_get_contents('title.php');
echo file_get_contents('header.php');
echo file_get_contents('content.php');
echo file_get_contents('footer.php');
I'm getting some fairly odd behavior here... I noticed that only localhost, a header statement I have worked just fine, but when copied over (SAME EXACT CODE) to my live site, the header statement no longer triggers.
I added some echos to help debug. This if statement will only trigger if the URL variable id is NOT set. So with this same exact code on localhost, I never see these debug statements. On the live site, I do... which I shouldn't. I should get redirected instead. Anyone know why a header statement would be ignored?
if((!isset($_GET['id'])) && $rows != 0) {
$result = mysql_query('SELECT videoinfo FROM videos where game_id=' . $gameid . ' LIMIT 1');
$row = mysql_fetch_array($result);
$tubeID = $row['videoinfo'];
echo '<script type="text/javascript">';
echo 'window.location = "videos.php?id=' . $tubeID . '&awayid=' . $awayid . '&homeid=' . $homeid . '&date=' . $date . '&time=' . $time . '&gameid=' . $gameid . '&play=0"';
echo '</script>';
}
EDIT 4 people have told me already that I can't have any echo calls before my header function. This code WORKS on localhost and the header function DOES trigger. Regardless, REMOVING the echo statements DOES NOT fix it.
AFAIK
Can't send header() after some echo.
You cannot output ANYTHING before you call header(), i.e. echo etc...
I don't think you can have a header after any sort of output. I just came up with that.
You need to enable output buffering. This is probably enabled on your localhost but not on your live system (or the value on the live system is too small).
This will keep your output buffered, and then the Header will work fine.
Your debug statements are making the problem worse.
header statements will not work if there is any output before they are called. In this case, your echos are killing it. Also, make sure there is no other output before this is called (white space, HTML, etc.).
at start of script, add
ob_start();
and just before calling header();, use
ob_clean();
ob_clean();
header('Location: videos.php?id=' . $tubeID . '&awayid=' . $awayid . '&homeid=' . $homeid . '&date=' . $date . '&time=' . $time . '&gameid=' . $gameid . '&play=0');
Edit
Check to ensure that your files are encoded correctly. For instance, if you are encoding in UTF-8, make sure you encode in UTF-8 without BOM (Byte Order Mark).
How to check depends on what you use to edit and save your file. For instance, I use Notepad++ so I just go to the 'Encoding' menu and select 'Encode in UTF-8 without BOM' and then save the file.
function goto_url($url) {
// must not have output anything prior to calling this function
if (!headers_sent()){
header('Location: '.$url); exit;
} else {
echo '<script type="text/javascript">';
echo 'window.location.href="'.$url.'";';
echo '</script>';
echo '<noscript>';
echo '<meta http-equiv="refresh" content="0;url='.$url.'" />';
echo '</noscript>'; exit;
};
};
http://www.w3schools.com/php/func_http_headers_sent.asp