PHP Hash Removal - php

How can I remove all hashes from a string with PHP?
I've tried str_replace("#","",$message), but it didn't work.


Remember that str_replace() return replaced text.
Example:
$a = '### Foo ###';
$a = str_replace('#', '', $a);
echo $a;
DEMO

Related

how to omit double quotes and array brackets from a string in php

i have a string in the format ["gated","gas"] i want this to be in the format as : gated,gas.
for this i have used str_replace function and i also get the required output but i want some alternate to do this task.
$newArray['Ameneties'] = ["gated","gas"] this is a string not an array
$a = str_replace('"', '',$newArray['Ameneties']);
$b = str_replace('[', '',$a);
$c = str_replace(']', '', $b);
echo $c;
i got the right output but i think there should be correct way of doing this as i have used the str_replace multiple times

One quick way is to json_decode and implode
echo implode( ",", json_decode( '["gated","gas"]' ));
This will return to:
gated,gas

You can replace string more than 1,
$string = str_replace(array('[', '"', ']'), '', '["gated","gas"]');
echo $string; // Output: gated,gas
Docs : str_replace

PHP str_replace not working with query

I'm having this:
$a = "t4.length = "50" AND t4.type = "F" AND (t3.minutes*60*1000+t3.seconds*1000+t3.milliseconds) < 22000";
I want to replace this string with other string, I tried str_replace but this function doesn't replace this string.
I'm trying this.
$c = str_replace($a , '', $b);

Wrong code
$c = str_replace($b , '', $a);
$b is key to find and replace
'' is replacement
$a is subject to replace
http://php.net/manual/en/function.str-replace.php

It was my fault, there were other extra spaces that's why this function was not working. I truncated all extra spaces then it was working fine.

Remove identical succesive characters from string PHP

I have this string
$string = "000000014Y00j:7";
I want to turn it into
$string = "14Y00j:7";
I want to remove all the zeros from the start of the string, in PHP

If you want to delete any chars (not only 0) you could use
$a = "000000014Y00j:7";
if($a[0]==$a[1]){
$a = ltrim($a,$a[0]);
}
echo $a;

$str = "000000014Y00j:7";
$str = ltrim($str, '0');
echo $str ;

PHP remove commas from numeric strings

In PHP, I have an array of variables that are ALL strings. Some of the values stored are numeric strings with commas.
What I need:
A way to trim the commas from strings, and ONLY do this for numeric strings. This isn't as straightforward as it looks. The main reason is that the following fails:
$a = "1,435";
if(is_numeric($a))
$a = str_replace(',', '', $a);
This fails because $a = "1435" is numeric. But $a = "1,435" is not numeric. Because some of the strings I get will be regular sentences with commas, I can't run a string replace on every string.

Do it the other way around:
$a = "1,435";
$b = str_replace( ',', '', $a );
if( is_numeric( $b ) ) {
$a = $b;
}

The easiest would be:
$var = intval(preg_replace('/[^\d.]/', '', $var));
or if you need float:
$var = floatval(preg_replace('/[^\d.]/', '', $var));

Not tested, but probably something like if(preg_match("/^[0-9,]+$/", $a)) $a = str_replace(...)

It sounds like the ideal solution for what you're looking for is filter_var():
$a = filter_var($a, FILTER_VALIDATE_FLOAT, FILTER_FLAG_ALLOW_THOUSAND);
(Note that it's using FILTER_VALIDATE_FLOAT instead of FILTER_VALIDATE_INT because that one doesn't currently have a FILTER_FLAG_ALLOW_THOUSAND option).

Try this .this worked for me
number_format(1235.369,2,'.','')
if you use number_format like this
number_format(1235.369,2) answer will be 1,235.37
but if you use like below
number_format(1235.369,2,'.','') answer will be 1235.37
it's removing the "," of "1,235.37"

function cleanData($a) {
if(is_numeric($a)) {
$a = preg_replace('/[^0-9,]/s', '', $a);
}
return $a;
}

If you want to remove commas from numbers inside a string that also contains words, the easiest way I think would be to use preg_replace_callback:
Example:
$str = "Hey hello, I've got 12,500 kudos for you, spend it well"
function cleannr($matches)
{
return str_replace("," , "" , $matches["nrs"]);
}
$str = preg_replace_callback ("/(?P<nrs>[0-9]+,[0-9]+)/" , "cleannr" , $str);
Output:
"Hey hello, I've got 12500 kudos for you, spend it well"
In this case the pattern (regex) differs from the one given in the accepted answer since we don't want to remove the other commas (punctuation).
If we'd use /[0-9,]+/ here instead of /[0-9]+,[0-9]+/ the output would be:
"Hey hello I've got 12500 kudos for you spend it well"

How about this:
/**
* This will parse the money string
*
* For example 1, 234, 456.00 will be converted to 123456.00
*
* #return
*/
function parseMoney(string $money) : float
{
$money = preg_replace('/[ ,]+/', '', $money);
return number_format((float) $money, 2, '.', '');
}
Example;
parseMoney('-1, 100, 000.01'); //-1100000.01

how do i remove the matched character from a string?

here is my code
$a = "Hey there, how do i remove all, the comma from this string,";
$a = str_replace($a,',','';)
echo $a;
i want to remove all the commas available in the string, how do i do it?

$a = str_replace(",", "", $a);

$a = "Hey there, how do i remove all, the comma from this string,";
$a = str_replace(',','',$a);
echo $a;
Misplaced semi-colon and wrong function arguments.

Categories