I have a page in where users can ask questions.
When they move on to the next page, I need to do a mysql query and post all the asked question into the database. I use jquery to hide the answers and show them when clicking the corresponding button.
The structure of the page looks like this:
<!-- questions.php -->
<form action="submitquestions.php" method="post">
<div>
<span>This is a question</span>
<button name="question" value="question1">Ask the question</button>
<span>This is the answer</span>
</div>
<div>
<span>This is a question</span>
<button name="question" value="question2">Ask the question</button>
<span>This is the answer</span>
</div>
<div>
....
</div>
<button name="submit">Go to the next page</button>
</form>
<!-- submitquestions.php -->
<?php if (isset($_POST['submit'])) {
var_dump($_POST);
} ?>
How can I put all the clicked buttons into the $_POST array and that way submit the data to my database?
Considered using checkboxes? You could style them nicely with jQuery as well. You really shouldn't use <button>s anyway.
Simply use <input type="checkbox" name="question1"> then the jQueryUI buttons and checkboxes to style it. Make sure your disable it once it has been checked so it doesn't get undone.
Then in PHP, check if(isset($_POST['question1'] )) { to see if a box has been checked.
Thanks for feedback from comments.
Here's my solution:
<form action="submitquestions.php" method="post">
<div>
<span>This is a question</span>
<input type="checkbox" name="question[]" value="question1" style="display:none">
<button>Ask the question</button>
<span>This is the answer</span>
</div>
<div>
<span>This is a question</span>
<input type="checkbox" name="question[]" value="question2" style="display:none">
<button>Ask the question</button>
<span>This is the answer</span>
</div>
<div>
....
</div>
<button name="submit">Go to the next page</button>
</form>
<script>
$(document).ready(function(){
$("form button").click(function(){
$(this).prev(":checkbox").attr("checked", true);
});
});
</script>
<!-- submitquestions.php -->
<?php if (isset($_POST['submit'])) {
if(!isset($_POST['question'])) $_POST['question'] = array(); //Just in the case no button is pressed
//$_POST['question'] will have an array of all clicked questions.
var_dump($_POST);
} ?>
As you can see, we use 'hidden' checkboxes 'behind' each button, that check when a button is pressed. And, as our buttons don't have name but checkboxes do, we send only the checked checkboxes to the server.
$_POST['question'] will have an array of all clicked questions. No 'isset' per question needed
If you use <button type="submit" name="this button's unique name goes here" value="1">Button text goes here</button> then you can check for the button that triggered the submit with $_POST ['this button's unique name goes here'] == 1
At least in theory you can. Internet Explorer prior to version 8 mishandles the <button> tag quite badly. In internet explorer 6 it is in fact basically impossible to determine which button was clicked if you use the <button> tag.
http://www.w3schools.com/tags/tag_button.asp
Related
I have a form that has one hidden input field, the hidden field includes the value of email.
the problem when the button clicked, the form didn't submit any values at all and nothing happens at all.
the HTML form as shown below:
<form method="post" class="table-responsive" action="alerts.php">
<?php foreach ($admins as $key => $admin): ?>
<input type="hidden" name="email" value="<?php echo $admin['email']; ?>">
<?php endforeach;?>
<button type="submit" class="btn btn-outline-light btn-lg btn-block add"
name="e_conf">confirm</button>
</form>
i tried to test if the form submit the values or not but set output message in the server side:
if(isset($_POST["e_conf"])){
echo "test";
}
but nothing displayed at all which I understood that the form didn't submit any values.
I hope someone can figure out this problem
thanks
Can you try below jquery code to submit form, Make sure jquery is included in your project.
<script>
$(".add").click(function(){
$(".table-responsive").submit();
});
</script>
Hi I try to research my problem via Stack about 3 hours but I still not found.
So I decide to create the topic to ask about my problem.
I am creating search engine and the below are the result:
If I type test text into input form then click "enter" button from keyboard, the search result will working correctly.
If I type test text into input form then click "Search" button from webpage, the search result is not working.
My problem is result No 2.
This is my code:
<form action="search_content.php" method="POST" >
<div class="input-group mainsearch-home">
<input type="text" class="input-group-field" name="homesearchfield" id="homesearchfield2" placeholder="What are you looking for?" autocomplete="off">
<div class="input-group-button">
<button type="button" class="button button--search" >search</button>
<input type="hidden" name="homesearchfield" value="search">
</div>
</div>
</form>
What I do wrong?
I thought that my problem is happens from input type hidden data.
So I would like to know how to get value from input text box and send value to my target page.
I have added some php code from my "response" page on below.
$viewstate = isset( $_POST["homesearchfield"] ) ? $_POST["homesearchfield"] : "" ;
$sql="SELECT * FROM `article` WHERE topic_article LIKE '%$viewstate%' order by id_article DESC";
Currently your form doesn't know that the button is meant to submit the form, which can be fixed by changing the type on the button:
<button type="submit" class="button button--search" >search</button>
You could also use:
<input type="submit" class="button button--search" value="search" />
An option for controlling the data is using JavaScript / jQuery to control the action of the form. This way also allows you to view the data being posted before its actually sent and you can even comment out the post and just work on getting the form with the right data you are looking to get back.
also for serialize to work, you need to have a name for each item you want to pass back data.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script lang="JavaScript">
$(function(){
$("#button").click(fuction()
{
var formData = $("#form").serialize();
alert(formData);
/*
$.post({"search_content.php",
formData,
function(returndata)
{
//do something
//this will load the return data into the div tag on the fly
$("#divReturn").html(returndata);
},
"text"
});
//*/
});
});
</script>
<form id="form" onsubmit="return false;" >
<div class="input-group mainsearch-home input-group--search inputs--raspberry">
<input type="text" class="input-group-field" name="homesearchfield" id="homesearchfield2" placeholder="What are you looking for?" autocomplete="off">
<div class="input-group-button">
<button type="button" class="button button--search" id="button" name="button" value="search" >search</button>
</div>
</div>
</form>
<div id="divReturn">
</div>
I have a form that contains a WYSIWYG editor, and two submit buttons :
<input type='submit' name='pdf' value='PDF Preview'/>
<input type='submit' name='save' value='Save'/>
"pdf" action displays the content of the editor as a PDF output. "save" action is a regular form submit. I want the PDF output to open in a new tab, and can't figure how to do that.
There is no "target" attribute for "input" tag. I could add a "target=_blank" to the "form" tag, but that would submit my "save" action in a new tab as well, which I don't want.
I tried to replace the "pdf" submit button with this :
<a href="same_page" target="_blank" onclick="submitForm();">
That didn't work. The form is submitted in its current tab and the new tab query receives nothing in $_POST.
Is there a magic trick I don't know yet ?
Note : server-side code is PHP
Use button and onclick event with jQuery.
<button type='submit' name='pdf' onclick="$('form').attr('target', '_blank');">PDF Preview</button>
<button type='submit' name='save' onclick="$('form').attr('target', '');">SAVE</button>
So in short you have one form + two submit buttons
first button: open in same tab
second button : open in new tab
after submit you want to know which one is submitted
Solution:
add two submit buttons with different behavior is impossible
so you need JS help or Jquery ( Ravi Hirani solution is perfect )
To know which button is submitted, you should give different names ( newage comment is perfect)
So this is just simple example does the magic you are looking for:
<?php
//print the post data
var_dump($_POST);
?>
<script type="application/javascript" src="https://code.jquery.com/jquery-3.0.0.min.js"></script>
<form action="test.php" method="POST">
<!-- just simple textarea -->
<textarea rows="4" cols="50" name="textarea">
text here
</textarea>
<!-- new tab submit button -->
<input type="submit" name="New_Window" value="New Window" onclick="$('form').attr('target', '_blank');" />
<!-- same tab submit button -->
<input type="submit" name="Same_Window" value="Same Window" onclick="$('form').attr('target', '');" />
</form>
You could maybe try using jQuery for this.
For example when the PDFPreview button is clicked jQuery could save the values of the form inputs into cookies. Then it would redirect to the PDFPreview page in a new tab. The PDFPreview page would then read the cookies.
E.g:
<script>
var input1 = null;
function previewPdf()
{
input1 = $("#input1").text();
document.cookie = "input1=" + input1;
window.open("/path/to/pdfPreview.php", '_blank')
}
</script>
<form action="whateverpage" method="post">
<input type="text" name="input1" id="input1">
<input type="button" onClick="previewPdf();" value="Preview PDF">
<input type="submit" value="Save">
</form>
You can use HTML5 formtarget attribute of input tag to change form behavior. This won't work with outdated browsers, however. In your case it will look something like:
<input type='submit' name='pdf' formtarget="_blank" value='PDF Preview'/>
<input type='submit' name='save' formtarget="_self" value='Save'/>
It can be used with button tag either.
References:
https://developer.mozilla.org/en-US/docs/Web/HTML/Element/input/submit#formtarget
https://www.w3schools.com/tags/att_input_formtarget.asp
https://developer.mozilla.org/en-US/docs/Web/HTML/Element/button#Attributes
i got following code i want to know which button pressed then pass the value to input box.
<button type="button" name="buttonpassvalue" value="1" onclick="">Value1</button>
<button type="button" name="buttonpassvalue1" value="2" onclick="">value 2 </button>
<?php
if buttonpassvalue pressed then add the buttonpassvalue value
<input type="text" name="value">
else
add value of buttonpassvalue1
?>
i am tried to solve but stock here.
please help me
thanks
The best way to do this is with Javascript.
As PHP is a server side language, it requires you to send some information to the server, meaning you would have to submit the form, and reload the page with the details of the request from the user.
With a javascript library like jQuery you can do something like the following.
<button class="some-button" value="1">Button 1</button>
<button class="some-button" value="2">Button 2</button>
<input type="hidden" name="buttonValue" class="button-value-hidden" />
<script>
$(document).ready(function(){
$('button.some-button').on('click', function(){
$('input.button-value-hidden').val($(this).val());
});
});
</script>
Now $_GET['buttonValue'] will contain your button value when the form is submitted.
Make sure you are including the jQuery library!
I have a form with multiple submit buttons.
Each submit button is an IMG SRC trash can which denotes the delete icon for messages in a web based messaging mail inbox
what is the best way to figure out which submit button icon was clicked so that I can then write the PHP/MySQL code to DELETE the message?
if(!empty($_POST)){
// How do I figure out which submit button has been clicked to get the ID of the message to delete?
}
<form method="POST">
<input src="http://www.foo.com/img.png" id="button_1">
<input src="http://www.foo.com/img.png" id="button_2">
<input src="http://www.foo.com/img.png" id="button_3">
<input src="http://www.foo.com/img.png" id="button_4">
...
<input src="http://www.foo.com/img.png" id="button_100">
</form>
Set value for each submit button and check that in php and find which one is clicked
<form method="POST">
<img src="http://www.foo.com/img.png" id="button_1" name="submit_btn" value="1">
<img src="http://www.foo.com/img.png" id="button_2" name="submit_btn" value="2">
<img src="http://www.foo.com/img.png" id="button_3" name="submit_btn" value="3">
<img src="http://www.foo.com/img.png" id="button_4" name="submit_btn" value="4">
...
<img src="http://www.foo.com/img.png" id="button_100" name="submit_btn" value="100">
</form>
echo $_POST['submit_btn']; will give you the value of which submit button is clicked
Give each button a name=""
Then you can do something like
isset($_POST['button_name']) {
// execute code here if true
}
THE solution of this problem is to use the NAME attribute of the tag input/button.
<input type="submit" name="submitSave" value="Save"/>
<input type="submit" name="submitAddComment" value="Add comment"/>
or
<button type="submit" name="submitSave">Save</button>
<button type="submit" name="submitAddComment">Add comment</button>
I think you can also use the value attribute of button tag, this is definitively not possible with input tag.
If you need to use an ID or another variable, use name="submitDelete[888]"
Then, check it with PHP:
if( isset($_POST['submitDelete']) ) {
echo key($_POST['submitDelete']);// Displays the ID to delete, e.g. 888.
}
So many years later, I like button because it allows to display a text or an image independently of the value returned.
Here is an illustration of possibilities which fits the title of this post and more cases than the OP.
<?php
if(!empty($_POST['id'])){
echo 'button '. $_POST['id'] .' clicked';
} elseif ('create' === ($_POST['action'] ?? '')) {
echo 'create clicked'; // ?action=create
} elseif (isset($_POST['action'])) {
echo 'refresh clicked'; // ?action
} elseif (isset($_POST)) {
echo 'Default clicked'; // ?
}
?>
<form method="POST">
<!-- Original Post examples -->
<button type="submit" name="id" value="1"><img src="http://www.foo.com/img.png"></button>
<button type="submit" name="id" value="2"><img src="http://www.foo.com/img.png"></button>
...
<button type="submit" name="id" value="100"><img src="http://www.foo.com/img.png"></button>
<!-- Additional possibilities -->
<!-- ?action=create -->
<button type="submit" name="action" value="create">New element</button>
<!-- ?action -->
<button type="submit" name="action">Refresh</button>
<!-- ? -->
<button type="submit">Default</button>
</form>
you can give a name and a value to each of your buttons. It will then show up under $_POST['submit']
<img src="http://www.foo.com/img.png" id="button_4" name='submit' value='4' />
You have to pass your value to the current file by declearing name and value for each.. then you can echo in your php script in order to know which one is clicked.