I have previously constructed an array manually, e.g.:
<?php
$noupload = array('nick', 'cliff');
?>
but now I am trying to populate the array automatically from users in a MySQL database. So far I have this:
<?php
// Make a MySQL Connection
$debug=false;
$conn = mysql_connect("host","user","password"); // your MySQL connection data
$db = mysql_select_db("database");
$query = "SELECT * FROM users WHERE access LIKE '%listen%'";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
$listen = "'". $row['login']. "', ";
}
?>
$listen constructs the user list in the way that I previously entered it manually (I tested this using echo), but I am not sure how to pass this to $noupload. I tried:
$noupload = array($listen);
but this didn't work. I think I'm close and would be grateful for some help over the final hurdle,
Thanks,
Nick
You can declare $listen as an array
$listen = array();
while ($row = mysql_fetch_array($result)) {
$listen[] = "'". $row['login']. "'";
}
Related
I am trying to store the result from a MySQL statement for later use in PHP. I have this code which gets me the result:
// Get the categories from the db.
$categories = array();
$catSql = "SELECT id, name FROM categories";
if ($catStmt = mysqli_prepare($db, $catSql))
{
$catStmt->execute();
$result = $catStmt->get_result();
// Fetch the result variables.
while ($row = $result->fetch_assoc())
{
// Store the results for later use.
}
}
So I know i will have the results in $row["id"] and $row["name"] and I want to save all of the rows so whenever i need them i can loop through them and for example echo them. I have searched for structures and arrays for keeping them in PHP but I cannot seem to find any information about that or maybe I am not searching in the right direction. Can anyone point me where i should read about this to find out how to do this efficiently and if possible post a small example?
Use sessions:
if (session_status() == PHP_SESSION_NONE) {
session_start();
}
// Get the categories from the db.
$categories = array();
$catSql = "SELECT id, name FROM categories";
if ($catStmt = mysqli_prepare($db, $catSql))
{
$catStmt->execute();
$result = $catStmt->get_result();
// Fetch the result variables.
while ($row = $result->fetch_assoc())
{
// Store the results for later use.
$_SESSION['category_' . $row['id']] = $row['name'];
}
}
Then access it later from a different page
$_SESSION['session_variable_name']
You can also create an array of the information and store the entire array in a single session variable.
Just make sure you add the session_start function at the beginning of each page. The if statement prevents you from trying to start it multiple times.
$categories = array();
$catSql = "SELECT id, name FROM categories";
if ($catStmt = mysqli_prepare($db, $catSql))
{
$catStmt->execute();
$result = $catStmt->get_result();
while ($row = $result->fetch_assoc())
{
$categories[$row['id']]=$row['name'];
}
}
And If you want the name anywhere use below :
$categories[$id]
I am still new to PHP. I have tried a few stuff, but I just can't get it to work.
Question: I want all the data from my users table to be in a string, separated by comma. Then when the ID is 2 to be ; for net new row, so on and so forth. If someone can please help me.
$server = "localhost";
$user_name = "root";
$password = "";
$database = "users";
$conn = new mysqli($server, $user_name, $password, $database);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM Users;";
$result = $conn ->query($sql);
while($row = mysqli_fetch_array( $result )) {
$rows = implode (";",$result);
$array = $rows;
echo $array;
}
Question2: But if I want first row of DB data to be, separated and then at the end with a ;. How would I do that?
Output: The output of this code is:
Warning: implode(): Invalid arguments passed
You've simply used the wrong variable in your call to ìmplode.
You've assigned all the columns as an array to $row - but you're trying to implode $result.
Update that line to this:
$rows = implode(";", $row);
Let's say your user table has 2 fields Firstname and Lastname. What I understood from your question is you want your output to be something like
$array = ['steve,jobs;', 'mark,zukerberg;'];
To achieve this you can append ';' at the end of the string.
while($row = mysqli_fetch_array( $result )) {
$rows = implode(',',$row) . ';'; //you have named this variable $rows but it is going to have data of a single row
$array = $rows; //you could directly var_dump($rows) instead of assigning it to a new variable
echo $array; //you could rather use var_dump($array) for this
}
I dont know if this is possible, but am trying to create a php variable using an entry from a mysql database.
For example, lets say I want to create the following variables, but i want to replace google with whatever the company name is in the database.
$google = $row['companyname'];
$google_ticker = $row['ticker'];
$google_holding = $row['holding'];
So if I had a row in my database with the company name as Yahoo, the following would appear instead:
$yahoo = $row['companyname'];
$yahoo_ticker = $row['ticker'];
$yahoo_holding = $row['holding'];
I have tried different variations of the following however I cant get it to work (I know the code below wont work, its just an example of the sort of thing I have tried):
$query = mysqli_query($conn, $sql);
while ($row = mysqli_fetch_assoc($query)){
$$row['companyname'] = $row['companyname'];
$$row['companyname']_ticker = $row['ticker'];
$$row['companyname']_holding = $row['holding'];
}
I can get it to work using something similar to the following, however doing it this way means I have to create each variable manually (as far as i know). I am trying to get it to create my variables automatically depending on what company names I have in my database.
$values = [];
$query = mysqli_query($conn, $sql);
while ($row = mysqli_fetch_assoc($query)){
$values[$row['companyname']] = $row;
}
$google = $values['google']['companyname'];
$google_ticker = $values['google']['ticker'];
$google_holding = $values['google']['holding'];
Any ideas on how I can achieve this?
Many Thanks
Use a (multidimensional-)Array with KEYS that function as variable names:
$query = mysqli_query($conn, $sql);
while ($row = mysqli_fetch_assoc($query)){
$data[$row['companyname']]['name'] = $row['companyname'];
$data[$row['companyname']]['ticker'] = $row['ticker'];
$data[$row['companyname']]['holding'] = $row['holding'];
}
Now you can access the holding variable like this:
echo $data['google']['holding'];
That should get you started...
Succes!
You can use like this:
${$row['companyname']} = $row['companyname'];
doc
Looking to select multiple values from the database and echo with PHP. (Newbie)
For instance:
SELECT sponser, contract, script FROM Copy WHERE day = '11092014' and time = 4
SELECT sponser, contract, script FROM Copy WHERE day = '11092014' and time = 5
SELECT sponser, contract, script FROM Copy WHERE day = '11092014' and time = 6
How would I set the variables.. something along the lines of this using MYSQLi for multiple variables?
$sqlStremail = "SELECT subcheckr
FROM login
WHERE username = '$u'";
$result = mysql_query($query);
$row = mysql_fetch_assoc($result);
$variable = $row["subcheckr"];
Truly appreciate any help.
Yes. Though if your query returns multiple rows, you'll need to use:
while ($row = mysqli_fetch_assoc($result))
{
//do something here
}
you need to make a loop for , foreach or a while loop
ex
while ($row = mysqli_fetch_assoc($result))
{
}
This should do it. First you need to connect, then you build your query. If query fails display an error so you know what went wrong. Then build your data array and use it.
$db = mysql_connect("localhost", "mysql_user", "mysql_password");
$sqlStremail = "SELECT `subcheckr`
FROM `login`
WHERE `username` = '".$u."'"; //needs to be concatenated
$result = mysql_query($sqlStremail, $db);
if(!$result) {
echo "query failed:". mysql_error();
exit;
}
$data = array();
while ($row = mysql_fetch_assoc($result)) {
$data = $row;
}
echo $data['sponsor'];
echo $data['contact'];
echo $data['script'];
//etc
I would want to create an array that will hold records retrieved from a database using a query of SELECT statement.
The records to be retrieved have multiple fields such as lastname, firstname, mi and 20 more fields. What would be the best approach on coding this function?
alright i have followed what prisoner have given below.. the next question is how do i search through this kind of array using queries? for example i want to search for a username..
<?php
// run query
$query = mysql_query("SELECT * FROM table");
// set array
$array = array();
// look through query
while($row = mysql_fetch_assoc($query)){
// add each row returned into an array
$array[] = $row;
// OR just echo the data:
echo $row['username']; // etc
}
// debug:
print_r($array); // show all array data
echo $array[0]['username']; // print the first rows username
You shouldn't search through that array, but use database capabilities for this
Suppose you're passing username through GET form:
if (isset($_GET['search'])) {
$search = mysql_real_escape_string($_GET['search']);
$sql = "SELECT * FROM users WHERE username = '$search'";
$res = mysql_query($sql) or trigger_error(mysql_error().$sql);
$row = mysql_fetch_assoc($res);
if ($row){
print_r($row); //do whatever you want with found info
}
}
$mysearch="Your Search Name";
$query = mysql_query("SELECT * FROM table");
$c=0;
// set array
$array = array();
// look through query
while($row = mysql_fetch_assoc($query)){
// add each row returned into an array
$array[] = $row;
$c++;
}
for($i=0;$i=$c;$i++)
{
if($array[i]['username']==$mysearch)
{
// name found
}
}
$memberId =$_SESSION['TWILLO']['Id'];
$QueryServer=mysql_query("select * from smtp_server where memberId='".$memberId."'");
$data = array();
while($ser=mysql_fetch_assoc($QueryServer))
{
$data[$ser['Id']] =array('ServerName','ServerPort','Server_limit','email','password','status');
}