mysqli never returns anything - php

As part of a PHP web application, I'm querying a MySQL database using mysqli and prepared statements.
I've used exactly the same code on a few queries and it works, but on one particular query, it always returns an empty record set. I've run exactly the same query from the MySQL command line, and it correctly returns the result. I've checked the parameters being passed in, and they're fine.
I've spent the best part of a day trying to figure out why I'm always getting an empty record set with no errors or warnings. I've got PHP's errors set to display on the page, and I've got them set to E_ALL|E_STRICT. I still don't get any warnings or errors.
I've tried all the obvious things, like making sure I can actually connect to the database, checking the parameters that are being passed in, and making sure the row I'm trying to return actually exists in the database. I've had var_dump()s and die()s all over the page to check what's coming back, and it's always a legitimate, but empty, recordset.
function salt() {
return("I've removed my salt from this sample code");
}
function openDatabase() {
$conn = new mysqli("127.0.0.1", "username", "password", "database")
or die("Error: Could not connect to database.");
return($conn);
}
function checkUserCredentials($username, $password) {
$goodPassword = md5(salt().$username.$password);
$conn = openDatabase();
$query = $conn->stmt_init();
$query->prepare("SELECT id FROM users WHERE email = ? AND passwordHash = ?")
or die('Problem with query');
$query->bind_param("ss", $username, $goodPassword)
or die('Error binding parameters');
$query->execute() or die("Could not execute");
$query->bind_result($col1) or die ("Could not bind result");
if ($col1 !== 0) {
die("Authentication Complete");
} else {
die("Authentication Failure! Number of Rows: ".$query->num_rows." Username: " . $username . " Password Hash: " . $goodPassword);
}
}
Any feedback is appreciated. I'm sure I'm missing something simple, but if I didn't shave my head I'd be tearing my hair out right now.
Thanks

I'm not familiar with the mysqli library (I usually use PDO which provides a very similar cross platform API) so I can't immediately see any problem. However, you might try watching the mysqld log. See here for info:
http://dev.mysql.com/doc/refman/5.1/en/query-log.html
By tailing the log, you should be able to see the exact query that was submitted.
One final note, I notice you're using a fixed salt value. Wouldn't it be better to generate this value randomly each time you need it and then store it in the users table? Generally, a salt is not intended to be secret, it's just there to prevent people precomputing tables of passwords using the hash algorithm that you use.

In case anyone else runs into similar issues, it really helps if you run fetch() on your mysqli_stmt object.
In my code above, the solution looks like this:
$query->bind_result($col1) or die ("Could not bind result");
$query->fetch(); // <--- How could I forget to do this?
if ($col1 !== 0) {
return true;
} else {
return false;
}
Added on behalf of OP

Related

mysql dies everytime I try to create a new table

I am attempting to create new tables every time I post to this method, but for some reason I can not figure out why it dies.
<?php
$host = "127.0.0.1";
$username = 'cotten3128';
$pwd = 'pwd';
$database = "student_cotten3128";
$pin = $_REQUEST['pinSent'];
$words = $_REQUEST['resultSent'];
$tableName = $pin;
$db = new mysqli($host, $username, $pwd, $database);
if ($sql = $db->prepare("CREATE TABLE $pin (id INT(11) AUTO_INCREMENT);")) {
$sql->execute();
$sql->close();
}else{
echo $mysql->error;
die('Could not create table');
}
for($i=0;$i<count($words);$i++){
if($sql = $db->prepare("INSERT INTO ".$pin.$words[$i].";")) {
$sql->execute();
$sql->close();
}else{
echo $mysql->error;
die("Could not add data to table");
}
}
mysqli_close();
?>
Any help or insight would be greatly appreciated.
The intention of my post is to help you finding the issue by yourself. As you did not added much information I assume my post is helpful for you.
Based on the code you have shared I guess you mean one of your called die() functions is executed.
Wrong function call
As Jay Blancherd mentioned mysql_close is the wrong function. You rather have to use mysqli_close as you created a mysqli instance.
Beside of that mysql_* is deprecated and should not be used anymore.
Debugging Steps
Not only for this case but in general you should ask yourself:
Is there an error message available? (Frontend output, error log file, ...)
YES:
What's the message about?
Is it an error you can search for? E.g. via a search engine or the corresponding documentation?
Look up in the bug tracker (if available), by the software developer of the software you are using, and if it has not been reported yet report the issue.
NO: (if none error message available OR you cannot search for it as it is a custom error message)
Search in the files of the software you are using for the error message and start a core-debugging.
STILL NO SOLUTION?:
Ask on stackoverflow.com e.g. and tell your issue and the steps you have performed to find and fix the bug. Post only as much code as necessary plus use a proper format.
Debugging in your case:
In order to narrow down the scope. Which of the die() is executed? Depending on that echo the query to execute just before it actually is executed. Then copy the SQL query to an SQL editor and look at it syntax. After that you probably know the problem already.

How to fetch value with Cassandra PDO?

I am using a PHP PDO driver for an application that uses Apache Cassandra and I cannot fetch the information I need. Is anything obviously wrong?
$db = new PDO('cassandra:host=localhost;port=9160');
$db->exec("USE project");
$st = $db->prepare("SELECT fname FROM users WHERE email=:em;");
$st->bindValue(':em', 'email1#gmail.com', PDO::PARAM_STR);
$st->execute();
print_r($st->fetch(PDO::FETCH_ASSOC));
Nothing is printed to the window. The table users was created with the email column as the primary key. I had no trouble inserting and updating information to the users table in my app, but still cannot figure out how to fetch single values successfully. Similarly, when I fetchAll() with some query I can print the arrays (rows) to the screen but cannot index them to grab specific values. Maybe there is some detail about cassandra that I am missing?
Do the following:
Check the return values of each method.
Check if there is an error after executing the statement.
Check the error log of your php interpreter.
$db = new PDO('cassandra:host=localhost;port=9160');
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING);
$db->exec("USE project");
$st = $db->prepare("SELECT fname FROM users WHERE email=:em;");
if ($st == false) {
print_r($db->errorInfo())
exit;
}
if ($st->bindValue(':em', 'email1#gmail.com', PDO::PARAM_STR) == false) {
print_r($db->errorInfo())
exit;
}
if ($st->execute() == false) {
print_r($db->errorInfo())
exit;
}
print_r($st->fetch(PDO::FETCH_ASSOC));
I had a similar problem. I used YACassandraPDO. Unfortunately when use it with php 5.4 I get error 502. Decided to write his or her library that allowed to work with Cassandra binary protocol without experiencing similar problems.
In the future, I plan to speed it up.
Maybe it will help you. Syntax like PDO.

Mysql fails in php but works in phpmyadmin

I've made this a lot of times but now I can't :(
The insert allways return false but if I execute the same SQL script (taked from the output) it inserts in the database without any problem. I'm connected to the database because some values are fetched from another table.
This is my code:
$query = "INSERT INTO normotensiones(fecha,macropera,pozo,equipo_pmx,equipo_compania,paciente,sexo,edad,id_compania,otra_compania,puesto,ta,tum,ove,coordinador)
VALUES('$fecha','$macropera','$pozo','$equipo_pmx','$equipo_compania','$paciente','$sexo',$edad,$id_compania,'$otra_compania','$puesto','$ta','$tum','$ove','$coordinador')";
if (mysql_query($query,$connection)){
//OK
} else {
$errno = mysql_errno();
$error = mysql_error();
mysql_close($connection);
die("<br />$errno - $error<br /><br />$query");
exit;
}
The output is:
0 -
INSERT INTO normotensiones(fecha,macropera,pozo,equipo_pmx, equipo_compania,paciente,sexo,edad,id_compania, otra_compania,puesto,ta,tum,ove,coordinador)
VALUES('20111001','P. ALEMAN 1739','P. ALEMAN 1715','726', 'WDI 838','SERGIO AYALA','M',33,21, '','','110/70','ROBERTO ELIEL CAMARILLO','VICTOR HUGO RAMIREZ','LIC. PABLO GARCES')
Looks like there are no error, but allways execute the code in the else part of the if instruction. Any idea? Thanks in advance.
I think the issue might be you are missing the mysql_select_db line after the connection.
After the connection with the database is established you need to select a DB. Please make sure you have selected the Database that your desired table resides in.
And you can even use the following snippets to get some useful informated through mysql_errors.
$connection = mysql_connect('localhost', 'root', 'password');
if (!$connection) {
die('<br>Could not connect: ' . mysql_error());
}
if (!mysql_select_db('db_name')) {
die('Could not select database: ' . mysql_error());
}
And try you insert query after these lines of code. All the best.
I agree with the others concerning the column types. INT is one of the only data types that do not require single quotes.
There are two blank strings. There is a possibility that the variables are not defined, and therefore giving you a PHP exception (not even in the MySql yet) but that requires stricter-than-normal exception settings. I would personally look into the $connection variable. Before the SQL query statement, put this and send us the cleaned results:
echo '<pre>'.var_dump($connection, true).'</pre>';
Additionally, on your mysql_connect function call, put
OR die('No connection')
afterwords. Do the same thing with the mysql_select_db function, changing it to 'No DB Select' obviously.
Ultimately, we will need more information. But changing to mysqli is very desirable.
Oh! And make sure the permissions for the user you are connecting as are not changed. Sometimes I find people who connect to PhpMyAdmin using one user account but a different account in their PHP code. This is problematic, and will lead to problems eventually, as you forget the different accounts, at times.

mysqli_stmt_prepare returns false from within a function

I am trying my best to object orientate my login scripts and checks for my website. As such, I have created a function that is called named "attempt_login". This function uses a database connection via the "mysqli_connect" function provided by a outside php file that is included and returns the $link variable.
However, when in my "attempt_login" the "mysqli_stmt_prepare" function is reached. It always returns false, and as such, the if statement never runs.
mysql_connect.php
require_once '../conf.php';
$link = mysqli_connect($mysql_server,$mysql_user,$mysql_pass,$mysql_db);
if(mysqli_connect_error())
{
//Fail
echo mysqli_connect_error();
}else{
//Success
}
return $link;
And the code from the "attempt_login" that fails:
$link = require_once 'functions/mysql/mysql_connect.php';
print_r($link);
$stmt = mysqli_stmt_init($link);
echo mysqli_stmt_error($stmt);
echo mysqli_error();
//This if statement always fails.
if(mysqli_stmt_prepare($stmt,"SELECT member_salt FROM members WHERE username=?" ) )
{
mysqli_stmt_bind_param($stmt,'s',$login_details['username']);
mysqli_stmt_execute($stmt);
$member_salt = NULL;
mysqli_stmt_bind_result($stmt,$member_salt);
mysqli_stmt_close($stmt);
}
And calling the function is pretty simple.
attempt_login($login_details);
I have tried many ways to do this, but it seems to only work when it is not within a function. Which defeats the purpose of me trying to have it in a function. If I move the error output to after the if statment, it will print:
No Database Selected
Even though one clearly is set in the link. I also can do a print_r($link); and it does print proper data for the mysql server.
It also has the same issue with procedural and object orientated mysqli styles, and fails as well with "mysqli_prepare".
I do have mysql working on the site, but any attempts to run anything within a function fails.
I have searched for several hours on trying to find a answer, but was unable to locate anything. I look forward to hearing from you! Many thanks in advance.
~Travis
I'd say then you haven't selected a database.
Either $mysql_db isn't set in ../conf.php or there is a typo or $mysql_db isn't visible in mysql_connect.php.
You don't seem to be passing $stmt to your function, I would advise your read this on scopes.

php login script - remember me

Can anyone see anything wrong with this login script:
public function login($username, $pass, $remember) {
// check username and password with db
// else throw exception
$connect = new connect();
$conn = $connect->login_connect();
// check username and password
$result = $conn->query("select * from login where
username='".$username."' and
password=sha1('".$pass."')");
if (!$result) {
throw new depException('Incorrect username and password combination. Please try again.');
} else {
echo $username, $pass;
}
To explain:
At the moment the script is allowing anything through. In other words the query is returning true for any username and password that are passed to it.
I've put the echo statement just as a check - obviously the script would continue in normal circumstances!
I know that the connect class and login_connect method are working because I use them in a register script that is working fine. depException is just an extension of the Exception class.
The function login() is part of the same class that contains register() that is working fine.
I know that the two variables ($username and $pass) are getting to the function because the echo statement is outputting them accurately. (The $remember variable is not needed for this part of the script. It is used later for a remember me process).
I'm stumped. Please help!
UPDATE
Thanks for those responses. I was getting confused with what the query was returning. The complete script does check for how many rows are returned and this is where the checking should have been done. Everything is now working EXCEPT for my remember me function. Perhaps someone could help with that?!?! Here is the full script:
public function login($username, $pass, $remember) {
// check username and password with db
// else throw exception
$connect = new connect();
$conn = $connect->login_connect();
// check username and password
$result = $conn->query("select * from login where
username='".$username."' and
password=sha1('".$pass."')");
if (!$result) {
throw new depException('Incorrect username and password combination. Please try again.');
}
if ($result->num_rows>0) {
$row = $result->fetch_assoc();
//assign id to session
$_SESSION['user_id'] = $row[user_id];
// assign username as a session variable
$_SESSION['username'] = $username;
// start rememberMe
$cookie_name = 'db_auth';
$cookie_time = (3600 * 24 * 30);*/ // 30 days
// check to see if user checked box
if ($remember) {
setcookie ($cookie_name, 'username='.$username, time()+$cookie_time);
}
// If all goes well redirect user to their homepage.
header('Location: http://localhost/v6/home/index.php');
} else {
throw new depException('Could not log you in.);
}
}
Thanks very much for your help.
UPDATE 2!
Thanks to your help I've got the main part of this script working. However, the remember me bit at the end still doesn't want to work.
Could someone give me a hand to sort it out?
$username, $pass and $remember are all short variable names that I assigned before passing them to the function to save writing $_POST['username'] etc. everytime. $remember refers to a checkbox.
What does $conn->query() return, a MySQL resource object like mysql_query() does? If so then it'll always compare "true". mysql_query() only returns FALSE if the query completely fails, like it has a syntax error or a table doesn't exist.
To check if you got any results you need to try to fetch a row from the result set and see if you get anything, via whatever your equivalent of mysql_fetch_row() is.
Important: Your script is vulnerable to SQL injection attacks, or even just odd usernames like o'neil with an apostrophe. You should escape all variables in a query with mysql_real_escape_string() (or equivalent) to make sure your query doesn't get messed up by special characters. Or, even better, use prepared statements which look like
select * from login where username=? and password=sha1(?)
Re: UPDATE
Variables from a form are available via either $_GET or $_POST, depending on which method was used to submit the form. Try if (isset($_POST['remember'])) to see if that check box was checked.
Important: I see that you tried to use a bare $remember to see if the check box was checked. That suggests to me that you are trying to take advantage of the register_globals feature in PHP which makes your GET and POST variables accessible via regular variable names. If that is the case you should heed the warning in the PHP manual!
WARNING
[register_globals] has been DEPRECATED as of PHP 5.3.0 and REMOVED as of PHP 6.0.0. Relying on this feature is highly discouraged.
Use $_GET and $_POST instead. I could tell you how to make if ($remember) work, actually, but given the inherent evil-ness of register_globals I'm not gonna! ;-)
Your query is open for sql-injections...
SELECT * FROM users WHERE
username = '' OR 'a' = 'a'
AND password =
sha1('guessAnyPassword')
I'd also check your result, and base the action on how many records were returned.
if (mysql_num_rows($result) > 0)
In php most queries only return False if there was an error executing them. Your query is returning a value, probably an empty array of values. This is not a false value as far as your if statement is concerned.
Check how many rows are returned. The function to do this will depend on your abstraction layer (connect class etc...)

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