I have this bit of javascript:
var jsonString = "some string of json";
$.post('proxy.php', { data : jsonString }, function(response) {
var print = response;
alert(print);
and this bit of PHP (in proxy.php):
$json = $_POST['json'];
//set POST variables, THIS IS WHERE I WANT TO POST TO!
$url = 'http://my.site.com/post';
//open connection
$ch = curl_init();
//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, 1);
curl_setopt($ch,CURLOPT_POSTFIELDS, "data=" . urlencode($json));
//execute post (the result will be something like {"result":1,"error":"","pic":"43248234af832048","code":"234920348239048"})
$result = curl_exec($ch);
$response = json_decode($result);
$imageHref = 'http://my.site.com/render?picid=' . $response['picid'];
//close connection
curl_close($ch);
echo $imageHref;
I am trying to post data to an external site using a proxy. From there, I append the picid that the site responds with and append it to the URL to get the image URL.
Am I missing something here? I am not getting anything in response and it seems like my data is not even being posted (when I try echo $json after the first line in proxy.php, I get an empty string). Why am I not able to echo the JSON? Is my implementation correct?
Thanks!
In your Javascript code, you are using this :
{ data : jsonString }
So, from your PHP code, should you not be reading from $_POST['data'], instead of $_POST['json'] ?
If necessary, you can use var_dump() to see what's in $_POST :
var_dump($_POST);
Edit after the comment : if you are getting a JSON result such as this :
{"result":1,"error":"","pic":"43248234af832048","code":"234920348239048"}
This is a JSON object -- which means, after decoding it, you should access it as an object in PHP :
$response = json_decode($result);
echo $response->pic;
Note : I don't see a picid element in that object -- maybe you should instead use pic ?
Here too, though, you might want to use var_dump(), to see how your data looks like :
var_dump($response);
try this:
$json = $_POST['data'];
or even better do
var_dump($_POST);
to see what is actually in your post when you start
Related
Below is my code to capture the screenshot of of webpage. But i get the output of the same as how in the image below. Kindly suggest on what is the mistake i am committing. Also kindly suggest the method to save this screenshot to the server?
<?php
$url='https://www.google.com';
$stratedy = 'mobile' ;
$apiReqUrl = 'https://www.googleapis.com/pagespeedonline/v2/runPagespeed';
$apiKey = 'my_api_key' ;
$curl = curl_init();
curl_setopt($curl, CURL_OPTURL, $apiReqUrl.'?url='.$reqUrl.'
&key='.$apiKey.'&screenshot=true&strategy='.$stratedy);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
$result=curl_exec($curl);
$data = json_decode($result, true);
$img = str_replace(array('_','-'), array('/','+'), $data['screenshot']
['data']);
echo '<img src="data:image/jpeg;base64,'.$img.'">';
?>
If you can, try using the HTML version from Generating Screenshots of URLs using Google's secret magic API. All you need to do is to call the API and it's free (I guess).
For example in PHP:
<?php
$url = "https://praveen.science/";
// Hit the Google PageSpeed Insights API.
// Catch: Your server needs to allow file_get_contents() to make this run. Or you need to use cURL.
$response = file_get_contents('https://www.googleapis.com/pagespeedonline/v2/runPagespeed?screenshot=true&url='.urlencode($url));
// Convert the JSON response into an array.
$googlePagespeedObject = json_decode($response, true);
// Grab the Screenshot data.
$screenshot = $googlePagespeedObject['screenshot']['data'];
// Fix url encoded base64
$screenshot = str_replace(array('_','-'), array('/','+'), $screenshot);
// Build the Data URI scheme and spit out an <img /> Tag.
echo "<img src=\"data:image/jpeg;base64,{$screenshot}\" alt=\"Screenshot\" />";
// Or.. base64 decode and store
file_put_contents('...', base64_decode($screenshot));
Or in JavaScript:
$(function() {
// Get the URL.
var url = "https://praveen.science/";
// Prepare the URL.
url = encodeURIComponent(url);
// Hit the Google Page Speed API.
$.get("https://www.googleapis.com/pagespeedonline/v1/runPagespeed?screenshot=true&strategy=mobile&url=" + url, function(data) {
// Get the screenshot data.
var screenshot = data.screenshot;
// Convert the Google's Data to Data URI scheme.
var imageData = screenshot.data.replace(/_/g, "/").replace(/-/g, "+");
// Build the Data URI.
var dataURI = "data:" + screenshot.mime_type + ";base64," + imageData;
// Set the image's source.
$("img").attr("src", dataURI);
});
});
<script src="https://code.jquery.com/jquery-2.2.4.js"></script>
<h1>Hard Coded Screenshot of my Website:</h1>
<img src="//placehold.it/300x50?text=Loading+Screenshot..." alt="Screenshot" />
There are a lot of APIs available on the internet to take screenshots. Something like https://www.purplescreenshots.com/ has example of integrating screenshots too.
I want to pass a string from one PHP file to another using $_GET method. This string has different value each time it is being passed. As I understand, you pass GET parameters over a URL and you have to explicitly tell what the parameter is. What if you want to return whatever the string value is from providing server to server requesting it? I want to pass in json data format. Additionally how do I send it as Ajax?
Server (get.php):
<?php
$tagID = '123456'; //this is different every time
$tag = array('tagID' => $_GET['tagID']);
echo json_encode($tag);
?>
Server (rec.php):
<?php
$url = "http://192.168.12.169/RFID2/get.php?tagID=".$tagID;
$json = file_get_contents($url);
#var_dump($json);
$data = json_decode($json);
#var_dump($data);
echo $data;
?>
If I understand correctly, you want to get the tagID from the server? You can simply pass a 'request' parameter to the server that tells the server what to return.
EDIT: This really isn't the proper way to implement an API (like, at all), but for the sake of answering your question, this is how:
Server
switch($_GET['request']) {
case 'tagID';
echo json_encode($tag);
break;
}
You can now get the tagID with a URL like 192.168.12.169/get.php?request=tagId
Client (PHP with CURL)
When it comes to the client it gets a bit more complicated. You mention AJAX, but that will only work for JavaScript. Your php file can't use AJAX, you'll have to use cURL.
$request = "?request=tagID";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, '192.168.12.169/get.php' . $request);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, '3');
$content = trim(curl_exec($ch));
curl_close($ch);
echo $content;
EDIT: added the working cURL example just for completeness.
Included cURL example from: How to switch from POST to GET in PHP CURL
Client (Javascript with AJAX)
$.get("192.168.12.169/get.php?request=tagId", function(data) {
alert(data);
});
I am executing a curl request and get a response which returns a json response. Below is the code after the response is sent back.
Response: "Zeros Replaced real token"
{"success":true,"result":{"token":"000000000","serverTime":1471365111,"expireTime":1471365411}}1
Code Used (For Testing) and accessing property:
$json = json_decode($result);
print_r($json); // Prints the Json Response
$firsttry = $json->result['token']; //Access Property results in error :Trying to get property of non-object
$secondtry = $json['token'];
echo $firsttry.'<br>';//Code can't continue because of error from $firsttry.
print_r( $secondtry.'<br>');//Nothing Prints at all
I did notice a weird anomaly where it prints a 1 at the end, where as if i do
json_encode($json);
The return response replaces the one at the end of the string with a "true"
Could the "1 or true" at the end be throwing of the json decode?
Maybe I am missing something simple?
As Requested full test code
$url = "https://website.com/restapi.php";
//username of the user who is to logged in.
$userName="adminuser"; //not real user
$fields_string; //global var
$fields = array( //array will have more in the future
'username' => urlencode($userName)
);
//url-ify the data for the POST
foreach($fields as $key=>$value) { global $fields_string;
$fields_string .= $key.'='.$value.'&'; }
rtrim($fields_string, '&');
//open connection
$ch = curl_init();
//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url.'?'.$fields_string.'operation=getchallenge');
curl_setopt($ch,CURLOPT_POST, count($fields));
//execute post
$result = curl_exec($ch);
//close connection
curl_close($ch);
json_decode(), by default makes child objects into stdClass objects rather than arrays unless they are explicitly arrays.
Try something like:
$firsttry = $json->result->token;
The var_dump shows you the data type. Since result itself is an object, access its token with -> rather than []
$response = '{"success":true...}'
$json = json_decode($response); //var_dumping this will show you it's an object
echo $json->result->token; // 000000000
I figured out the issue. In the Curl Options I did not have
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
Once i put this in #GentelmanMax solution worked for me, but the issue was in the curl response responding directly, where as the return transfer sends back a string that php can work with, which then allowed json_decode()to function as is should. I knew it was something simple.
I'm having a bit of a problem reading JSON data that I generate in PHP and then pass back to my Javascript and I'm not sure why.
Here is the PHP:
header("content-type: text/json");
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, count($fields));
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);
//execute post
$result = curl_exec($ch);
// echo the result as a JSON object
echo json_encode($result);
And here is the Javscript:
$.post("payment_do.php", { "token": response.response.token, "ip_address": response.ip_address}).done(function(data) {
console.log(data);
});
It seems as though if I take the header line away in the PHP I get a response that I can read in the Javascript but I cannot access any of the elements the way you would expect. If I leave the header in there, I get no response readable by the javascript.
EDIT: Now getting a response from the php, looks like this:
"{\"response\":{\"token\":\"ch_9knTXHoU0dVZsl7iMHyHGg\",\"success\":true,\"amount\":9900,\"currency\":\"AUD\",\"description\":\"test\",\"email\":\"test#test.com\",\"ip_address\":\"1.1.1.1\",\"created_at\":\"2013-03-18T23:49:12Z\",\"status_message\":\"Success!\",\"error_message\":null,\"card\":{\"token\":\"test_token\",\"display_number\":\"XXXX-XXXX-XXXX-0000\",\"scheme\":\"master\",\"address_line1\":\"123 Fake Street Fakington\",\"address_line2\":null,\"address_city\":\"moon\",\"address_postcode\":\"2121\",\"address_state\":\"NSW\",\"address_country\":\"Australia\"},\"transfer\":[],\"amount_refunded\":0,\"total_fees\":999,\"merchant_entitlement\":999,\"refund_pending\":false}}"
In the end I had to remove the json_encode function in the php and just return the result. In the javascript (using jQuery) I then called:
data = $.parseJSON(data);
With which I could then access the elements of the object.
Change your header to application/json (as opposed to text/json). In addition, if you actually want to further process the results of the curl_exec call then you need to set an additional option:
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
This will cause the curl_exec call to return data on success, as opposed to TRUE.
$result = curl_exec($ch);
if(! $result) {
// handle error
}
echo json_encode($result);
Also, you will want to verify the data you are getting back from the cURL call - make sure that it really needs to be encoded before being returned.
add this:
header("Content-Type: application/json");
echo json_encode($result);
I'm trying to get json data by calling moodle url:
https://<moodledomain>/login/token.php?username=test1&password=Test1&service=moodle_mobile_app
the response format of moodle system is like this:
{"token":"a2063623aa3244a19101e28644ad3004"}
The result I tried to process with PHP:
if ( isset($_POST['username']) && isset($_POST['password']) ){
// test1 Test1
// request for a 'token' via moodle url
$json_url = "https://<moodledomain>/login/token.php?username=".$_POST['username']."&password=".$_POST['password']."&service=moodle_mobile_app";
$obj = json_decode($json_url);
print $obj->{'token'}; // should print the value of 'token'
} else {
echo "Username or Password was wrong, please try again!";
}
Result is: undefined
Now the question:
How can I process the json response format of moodle system? Any idea would be great.
[UPDATE]:
I have used another approach via curl and changed in php.ini following lines: *extension=php_openssl.dll*, *allow_url_include = On*, but now there is an error: Notice: Trying to get property of non-object. Here is the updated code:
function curl($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
$moodle = "https://<moodledomain>/moodle/login/token.php?username=".$_POST['username']."&password=".$_POST['password']."&service=moodle_mobile_app";
$result = curl($moodle);
echo $result->{"token"}; // print the value of 'token'
Can anyone advise me?
json_decode() expects a string, not a URL. You're trying to decode that url (and json_decode() will NOT do an http request to fetch the url's contents for you).
You have to fetch the json data yourself:
$json = file_get_contents('http://...'); // this WILL do an http request for you
$data = json_decode($json);
echo $data->{'token'};