field: content_id, value=1 or value=0, value_type=option
table: votingapi_vote
1,output the content_id field and descending it, the rule is according to the value(the count of each content_id 's value=1 minus the count of each content_id 's value=0 ,each content_id has many value=0 or value=1). where the value_type=option
is there a way to get that?
namely:
$query1=mysql_query(SELECT content_id, COUNT(*) FROM votingapi_vote WHERE value_type = option AND value = 1 GROUP BY content_id)
$query2=mysql_query(SELECT content_id, COUNT(*) FROM votingapi_vote WHERE value_type = option AND value = 0 GROUP BY content_id)
i want to use the count value = 1 minus the count value = 0. this is the content_id's descending rule,
For each content_id, the number of rows with value=1 minus the number of rows with value=0
SELECT content_id,
SUM(CASE WHEN value=1 THEN 1
WHEN value=0 THEN -1
ELSE 0
END) AS ContentSum
FROM votingapi_vote
WHERE value_type = 'option'
GROUP BY content_id
ORDER BY ContentSum DESC
SELECT content_id, SUM(CASE value WHEN 1 THEN 1 WHEN 0 THEN -1 ELSE 0 END) valuesum
FROM votingapi_vote
WHERE value_type = 'option'
GROUP BY content_id
ORDER BY valuesum DESC
Related
I have mysql table that looks like below :
In this table there are minus and plus value. I wants all record in dropdown in a format like.
I need to show first as zero than minus value in descending order and positive value in acsending order. So what query should I have to write?
For example :
0.00
-1
-2
...
...
...
1
2
3
...
...
...
Try this:
ORDER BY CASE
WHEN Value = 0 THEN 0
WHEN Value < 0 THEN 1
ELSE 2
END ASC,
ABS(Value) ASC
The first part of the ORDER BY places 0 value first, followed by negative values, followed by positive values. The second part orders negative values in descending order and positive values in ascending order.
Use 3 querys and join the results together by using union
(select * from sph where value = 0)
union
(select * from sph where value < 0 order by value desc)
union
(select * from sph where value > 0 order by value asc)
select * from sph order by abs( `value` ) asc
simple ;)
The scenario is I have a column named "States" in a table, States can be 0,1,2,3 or 4. What I want to do is get a count of each state using WHERE State = in a single query.
The main purpose is I want to show the count of records (identified by their state). Like this, 20 records have State 0 etc.
Is this possible? If yes, then how can I achieve this?
Edit: I know about Count. Here's what I have tried:
SELECT State, Date_Created, (SELECT COUNT(Id) FROM [ECOS].[eco].[tb_projects_details] WHERE State=1) as State_One, (SELECT COUNT(Id) FROM [ECOS].[eco].[tb_projects_details] WHERE State=2) as State_Two, (SELECT COUNT(Id) FROM [ECOS].[eco].[tb_projects_details] WHERE State=0) as State_Zero, (SELECT COUNT(Id) FROM [ECOS].[eco].[tb_projects_details] WHERE State=4) as State_Four FROM [ECOS].[eco].[tb_projects_details] WHERE Date_Created < dateadd(week,-3,getdate());
If I understand it correctly, you want to group and count:
SELECT mt.States, COUNT(*) total
FROM my_table mt
GROUP BY mt.States
To generate a list of values and their counts you can do this:
SELECT State, COUNT(*) AS C
FROM mytable
GROUP BY State
To generate one row that contains value counts as columns you can do this:
SELECT
COUNT(CASE State WHEN 0 THEN 1 ELSE NULL END) AS State_0_Count,
COUNT(CASE State WHEN 1 THEN 1 ELSE NULL END) AS State_1_Count,
COUNT(CASE State WHEN 2 THEN 1 ELSE NULL END) AS State_2_Count,
COUNT(CASE State WHEN 3 THEN 1 ELSE NULL END) AS State_3_Count,
COUNT(CASE State WHEN 4 THEN 1 ELSE NULL END) AS State_4_Count
FROM [...]
WHERE [...]
It will be very easy if you use group by clause after where condition. Then you will get the number of each state very easily.
SELECT state, count(*)
FROM table_name
GROUP BY state
Next time read a sql for beginers book first.
Select state, count(*)
from table
group by state
This is a snapshot of my MySQL table:
Is it possible to write a query to get such a pivot table like output...
How about something like
SELECT url_host,
SUM(CASE WHEN post_id = -1 THEN 1 ELSE 0 END) as post_id_minus1,
SUM(CASE WHEN post_id = 0 THEN 1 ELSE 0 END) as post_id_0,
etc...
FROM YOUR_TABLE
GROUP BY url_host
You can use CASE statement on this to pivot your table.
SELECT url_host,
COUNT(CASE WHEN post_ID = -1 THEN 1 ELSE NULL END) Negative_One,
COUNT(CASE WHEN post_ID = 0 THEN 1 ELSE NULL END) Zero,
COUNT(CASE WHEN post_ID > 0 THEN 1 ELSE NULL END) Greater_Zero
FROM tableName
GROUP BY url_host
SQLFiddle Demo
I have a table with a field called type, where 3 various rows are possible: 1, 2 and 3.
Now, I don't care about 3 at all. I need to count how many rows there are with type = 1 and with type = 2. I am doing this with 2 queries, like this:
Query1: SELECT COUNT(id) as count FROM users WHERE type='1'
Query2: SELECT COUNT(id) as count FROM users WHERE type='2'
Can I do this with only 1 single query? If so, should I, or not? How would the query look?
SELECT type,
COUNT(id) AS count
FROM users
WHERE type IN ('1','2')
GROUP BY type
SELECT type, COUNT(id) AS count
FROM users
GROUP BY type
HAVING type < 3
SELECT sum(case when type = '1' then 1 else 0 end) as count_for_one,
sum(case when type = '2' then 1 else 0 end) as count_for_tow
FROM users
WHERE type IN ('1','2')
If you want separate numbers,
SELECT SUM(IF(type='1', 1, 0)), SUM(IF(type='2', 1, 0))
FROM users WHERE type IN ('1', '2')
I want to have an only query with 2 queries but i don't know how to start...
My queries count the positive/negative votes for a comment.
SELECT COUNT(id) AS votes_no FROM comments_votes WHERE vote = 0 AND id_comment = 1
SELECT COUNT(id) AS votes_no FROM comments_votes WHERE vote = 1 AND id_comment = 1
I set vars to put negative and positives votes : $votes_no and $votes_yes
Then i have a final var : $votes_calc = $votes_yes - $votes_no;
How can i get the number of votes_yes, votes_no and votes_calc in only one query?
Thanks a lot!
select votes_no, votes_yes, votes_yes-votes_no as votes_calc
from (select sum(case when vote = 0 then 1 else 0 end) as votes_no,
sum(case when vote = 1 then 1 else 0 end) as votes_yes
from comments_votes
where id_comment = 1) a
select vote,count(id)
from Comment_votes
group by vote
WHERE id_comment = 1
with rollup
The with Rollup will add a row with a NULL value in the vote column and the total in the second column
I merge the query getting the comments and the comments votes and it seems to work :)
SELECT a.*, nb_votes, votes_yes-votes_no AS votes_calc
FROM comments AS a
LEFT JOIN (
SELECT id_comment, COUNT(id) AS nb_votes,
SUM(CASE WHEN vote = 0 THEN 1 ELSE 0 END) AS votes_no,
SUM(CASE WHEN vote = 1 THEN 1 ELSE 0 END) AS votes_yes
FROM comments_votes GROUP BY id_comment
) AS c ON (a.id = c.id_comment)
WHERE a.status = 'approved' AND a.id_post = 1 ORDER BY a.time ASC
Thanks for your answers :)