I have a string and it contains some words that I want to reach, seperators can be any string that consist of , ; or a space.
Here is a example:
;,osman,ali;, mehmet ;ahmet,ayse; ,
I need to take words osman ali mehmet ahmet and ayse to an array or any type that I can use them one by one. I tried it by using preg function but i couldn't figure out.
If anyone help, I will be appreciative.
$words = preg_split('/[,;\s]+/', $str, -1, PREG_SPLIT_NO_EMPTY);
[,;\s] is a character group which means match any of the characters contained in this group.
\s matches any white space character (space, tab, newline, etc.). If this is too much just replace it with a space: [,; ].
+ means match one or more of the preceding symbol or group.
DEMO
http://www.regular-expressions.info/ is a good site to learn regular expressions.
You want to use preg_split and use [;, ]+ for your regex to split on
$keywords = preg_split("/[;, ]+/", $yourstring);
Split on non-word characters:
$array=preg_split("/\W+/", $string);
Related
I have 2 texts in a string:
%Juan%
%Juan Gonzalez%
And I want to only be able to get %Juan% and not the one with the Space, I have been trying several Regexes witout luck. I currently use:
/%(.*)%/U
but it gets both things, I tried adding and playing with [^\s] but it doesnt works.
Any help please?
The issue is that . matches any character but a newline. The /U ungreedy mode only makes .* lazy and it captures a text from the % up to the first % to the right of the first %.
If your strings contain one pair of %...%, you may use
/%(\S+)%/
See the regex demo
The \S+ pattern matches 1+ characters other than a whitespace, and the whole [^\h%] negated character class that matches any character but a horizontal space and % symbol.
If you have multiple %...% pairs, you may use
/%([^\h%]+)%/
See another regex demo, where \h matches any horizontal whitespace.
PHP demo:
$re = '/%([^\h%]+)%/';
$str = "%Juan%\n%Juan Gonzalez%";
preg_match_all($re, $str, $matches);
print_r($matches[1]);
I can't select multiple lines between two characters on regex.
how can i solve this?
{
example
example 1
}
I want to select 'example'. but i cant.
I tried this regex
#\n.*#
thank you
Your pattern does not do what you expect; it matches a newline character followed by any character except newline "zero or more" times. You need to use the s (dotall) modifier which forces the dot to match across newline sequences.
For example — matching everything between the two curly braces.
preg_match('/{(.*)}/s', $str, $match);
echo $match[1];
I need to split multiple lines in multiple files by different delimiters. I think preg_split should do the job but i never worked with PCRE REGEX stuff. I could also change all my delimiters to be consistent but that adds unnecessary calculations.
Q: My delimiters consist of (,)(;)(|)(space) and i am curious how to build such a REGEX.
Put the characters in square brackets []:
$parts = preg_split('/[,;| ]/', $string, null, PREG_SPLIT_NO_EMPTY);
You can also use \s instead of a space character, which matches all kinds of whitspace, such as tabs and newlines.
Try this:
$string = "foo:bar|it;is:simple";
print_r(preg_split ( '/,|;|\||\s/' , $string ));
I have a Problem with RegEx and WhiteSpaces.
I want to split a Text in an Array which is marked with (....)
preg_match_all("/\([a-z0-9\s]+\)/i", $str,$a);
To catch whithe spaces I tried to use [\040] [\s] but nothing worked for me!
Is there a posibiltity to say [ANY Character DIGIT and WHITESPACES and special character] ?
greetz
fluxa
You can also said "any characters but not a )"
With your example :
preg_match_all("/\([^\)]+\)/i", $str, $a);
You could use a lazy search using.*? instead (which will stop matching as soon as it can, compared to greedy, .* which will match as much as possible).
Regex: \((.*?)\)
In code:
preg_match_all("#\((.*?)\)#", $str, $a);
How would I go about removing numbers and a space from the start of a string?
For example, from '13 Adam Court, Cannock' remove '13 '
Because everyone else is going the \d+\s route I'll give you the brain-dead answer
$str = preg_replace("#([0-9]+ )#","",$str);
Word to the wise, don't use / as your delimiter in regex, you will experience the dreaded leaning-toothpick-problem when trying to do file paths or something like http://
:)
Use the same regex I gave in my JavaScript answer, but apply it using preg_replace():
preg_replace('/^\d+\s+/', '', $str);
Try this one :
^\d+ (.*)$
Like this :
preg_replace ("^\d+ (.*)$", "$1" , $string);
Resources :
preg_replace
regular-expressions.info
On the same topic :
Regular expression to remove number, then a space?
regular expression for matching number and spaces.
I'd use
/^\d+\s+/
It looks for a number of any size in the beginning of a string ^\d+
Then looks for a patch of whitespace after it \s+
When you use a backslash before certain letters it represents something...
\d represents a digit 0,1,2,3,4,5,6,7,8,9.
\s represents a space .
Add a plus sign (+) to the end and you can have...
\d+ a series of digits (number)
\s+ multiple spaces (typos etc.)
The same regex I gave you on your other question still applies. You just have to use preg_replace() instead.
Search for /^[\s\d]+/ and replace with the empty string. Eg:
$str = preg_replace(/^[\s\d]+/, '', $str);
This will remove digits and spaces in any order from the beginning of the string. For something that removes only a number followed by spaces, see BoltClock's answer.
If the input strings all have the same ecpected format and you will receive the same result from left trimming all numbers and spaces (no matter the order of their occurrence at the front of the string), then you don't actually need to fire up the regex engine.
I love regex, but know not to use it unless it provides a valuable advantage over a non-regex technique. Regex is often slower than non-regex techniques.
Use ltrim() with a character mask that includes spaces and digits.
Code: (Demo)
var_export(
ltrim('420 911 90210 666 keep this part', ' 0..9')
);
Output:
'keep this part'
It wouldn't matter if the string started with a space either. ltrim() will greedily remove all instances of spaces or numbers from the start of the string intil it can't anymore.