I want to find a string like 'Jobs' in a title. Suppose i have 10 rows in a file.
i.e
Jobs for Accountant.
Featured Jobs for public Services.
Website Development Jobs in Delhi.
.
.
.
.
How to find jobs keyword in these type of titles?
You can use strpos
Just check if (strpos($string,$search)===0) and you are good
You can use strpos.
if(strpos($string, 'Jobs') !== false)
Make sure you do it exactly like that, since if(strpos($string, 'Jobs') would return 0 if the string started with 'Jobs', which would be casted to the boolean value of 0: false.
Use substr() to achieve this. Here is the manual php.net/manual/en/function.substr.php
You can use strpos. Look here for documentation.
it reurns the first occurence of what you are seraching in a string.
you can do:
$pos = strpos($string, "jobs")
and it returns the offset where it found "jobs".
Then you can $pos to look for further occurences passing it to the function
$pos2 = strpos($string, "jobs", $pos+1)
if you want to check if it doesn't find a string you must use === because if it finds the string in the first position it returns 0 (that if you just check with == resolves to false)
Use regular expressions.
Here is a tutorial: http://www.phpf1.com/tutorial/php-regular-expression.html
Or, just google php regular expressions for all the info you need.
Related
I am using the strpos function to validate a url that is submitted by a user and I want to make sure I'm not missing anything that would allow the user to bypass the validation and submit a url that is inappropriate.
Take the following as an example, if I only want a user to be able to input a url associated with the youtube domain, I don't want them to be able to put a wildcard (*) or something in that would "trick" the strpos function.
$url = $request->input('url');
// Check if Youtube url is found
if (strpos($url, 'http://youtube.com') > -1)
{
// some code
}
// some code
Thanks!
strpos returns false when in a not found condition and 0 if the string appears in the first column, which also looks like false to PHP, so it would be more accurate to use === or !==
$url = $request->input('url');
// Check if Youtube url is found
if (strpos($url, 'http://youtube.com') !== FALSE)
{
// some code when youtube is found in url
}
You would be better off using a Regular expression.
^(https?\:\/\/)?(www\.)?(youtube\.com|youtu\.?be)\/.+$
Try it out.
Remember to test with type safe equation.
strpos will find the position of first occurrence in the string. So
if there is a match in the beginning of string (position 0)
if (strpos($url, 'http://youtube.com') > -1)
will return 0 which will be interpreted as false. You're in trouble here.
Instead, do it type safely:
if (strpos($url, 'http://youtube.com') !== false)
This means no matter where in the string your substring is found, it will be considered true and you know there is a match.
I was looking into trying to revise some old code in an application that I work on. Currently the app parses out portions of a response string received from an API to determine if a request is good or if it failed. The response from the API sends back a string that contains the characters "DP" if the request was processed successfully. Right now there's a line of code in the app that is as follows:
if(stripos($result, "DP") !== false)
This is working fine now, but I can foresee an issue coming from this. stripos can return a "falsey" value even when the needle is in fact found within the haystack. Since the haystack string is zero-indexed with stripos the function will return 0 if the characters "DP" are found at the very beginning of the haystack string, which will incorrectly be read as false. This code is working now, but if for any reason the developers who maintain the API we work with decide to reformat their response, we will have problems. I was thinking of changing this to the following:
if(stristr($result, "DP") !== false)
From what I can tell this should be OK because according to php.net stristr only returns false if the needle is not found in haystack. I'm curious though if anybody has seen any problems similar to the one described above occurring with the stristr function.
0 doesn't equal false if you use === (or !==).
See this fiddle for proof: http://phpfiddle.org/main/code/nih-esg
More info on the PHP site here: http://www.php.net/manual/en/language.operators.comparison.php
Since your using !== it is a non issue, since the tripple operators checks both value and type
false != 0 : false
false !== 0 : true
<?php
$result="DP";
if (stripos($result, "DP") !== false)
{
echo stripos($result, "DP");
}
?>
Returns 0 from within brackets.
My latest issue involves trying to find "http://" in a variable. This variable contains the contents of a comments section on a clients website. I have seen all kinds of answers but none of them seem to work. I looked at a few other posts on here and I have yet to get the best answer. Here is what I have so far:
if(strpos($comments, 'http://') == true) {
// Does stuff here
}
I noticed other people use preg_match and some said to do it in an array. I am getting confused, too many options. Just kidding. I would like some clarification though and any advice would be greatly appreciated.
You'll need to say:
if(strpos($comments, 'http://') !== false) {
...since it can return 0 (which is falsey) if http:// is at the beginning of the string.
NOTE: This will only find the first occurrence of http:// in the string.
Take a close look at the reference: http://php.net/manual/en/function.strpos.php
You need to change code like that:
if(strpos($comments, 'http://') === false) {
//no link
}
because strpos return integer which is position your string.
Example:
full string: "http://stackoverflow.com hello"
you finding: "http"
Naturally it return 0.
But
full string: "ahttp://stackoverflow.com"
you finding: "http"
it return 1.
So you must use === operator to check is really 'boolean false'.
If you try to check with == operator, you maybe get fail because it get 0 as false.
more detail: http://php.net/strpos
I found this was a better match: (recommended by phpstorm ide)
if(str_contains($e, '1062 Duplicate entry')) {
}
Does anyone know any other way that I can use (beside of #strpos()) to ignored the error message that display from strpos() (Warning: strpos() [function.strpos]: Offset not contained in string in ....)
Instead of doing something like this:
$pos = strpos($haystack, $needle, $offset);
do something like
if($offset < strlen($haystack))
$pos = strpos($haystack, $needle, $offset);
else
$pos = false; // Mimics the actual output of strpos
Hope this helps!
Sounds like your third argument is not valid. From the docs
The optional offset parameter allows you to specify which character in haystack to start searching. The position returned is still relative to the beginning of haystack.
So, how about fixing your code instead of ignoring errors?
To answer the question, you can write your own error handler and catch that specific warning and suppress it... but I agree with the others; it's better that you just go and fix your code.
How can you search a partial string when typing (not to use MySQL) like the LIKE function in MySQL but using PHP when searching a string, e.g.
<?php
$string = "Stackoverflow";
$find = "overfl";
if($find == $string)
{
return true;
}
else
{
return false
}
?>
But that will obviously work won't, but is there a function where you can search partially of a string? That would be great :)
EDIT:
What if it was in an array?
if i use the strpos, it does the echo, If I use it, it goes like truetruetruetruetrue.
I tend to use strpos
$needle='appy';
$haystack='I\'m feeling flappy, and you?';
if(strpos($haystack,$needle)!==false){
//then it was found
}
If you want it to ignore case, use stripos.
Note that a subtlety about this is that if the needle is at the very start of the haystack, in position 0, integer 0 is returned. This means you must compare to false, using strict comparison, or it can produce a false negative.
As noted in the manual, linked above
Warning
This function may return Boolean
FALSE, but may also return a
non-Boolean value which evaluates to
FALSE, such as 0 or "". Please read
the section on Booleans for more
information. Use the === operator for
testing the return value of this
function.
As far as using arrays, strpos is meant to take two strings. Using an array will produce Warning: strpos() expects parameter 1 to be string, array given or 1Warning: strpos(): needle is not a string or an integer`.
Okay, let's say you have an array of strings for which to search.
You can
$needles=array('hose','fribb','pancake');
$haystack='Where are those pancakes??';
foreach($needles as $ndl){
if(strpos($haystack,$ndl)!==false){ echo "'$ndl': found<br>\n"; }
else{ echo "'$ndl' : not found<br>\n"; }
}
Another way of searching for multiple strings in one string, without using an array... This only tells you whether at least one match was found.
$haystack='Where are those pancakes??';
$match=preg_match('#(hose|fribb|pancake)#',$haystack);
//$match is now int(1)
Or, use preg_match_all to see how many matches there are, total.
$all_matches=preg_match_all('#(hose|fribb|pancake)#',$haystack,$results);
//all_matches is int(2). Note you also have $results, which stores which needles matched.
In that, the search term is a regular expression. () groups the terms together, and | means 'or'. # denotes the beginning and end of the pattern. Regexes can get pretty complicated quickly, but of course, they work! They are often avoided for performance reasons, but if you're testing multiple strings, this might be more efficient than they array looping method described above. I'm sure there are also other ways to do this.
strstr() / stristr() (the latter being case-insensitive)
if(strstr($string,$find)!==false){
//true
}
strpos() can do that.
if(strpos($string, $find) !== false)
. . .
Note that it may return 0, so do use the type-equals operator.