array_filter with assoc array? - php

Question

I am using array_filter to do something like this:
function endswithy($value) {
return (substr($value, -1) == 'y');
}
$people = array("Johnny", "Timmy", "Bobby", "Sam", "Tammy", "Danny", "Joe");
$withy = array_filter($people, "endswithy");
var_dump($withy);
BUT with the more option in filter for example
$people = array(
"Johnny"=>array("year"=>1989, "job"=>"prof"),
"Timmy"=>array("year"=>1989, "job"=>"std"),
"Bobby"=>array("year"=>1988),
"Sam"=>array("year"=>1983),
"Tammy"=>array("year"=>1985),
"Danny"=>array("year"=>1983),
"Joe"=>array("year"=>1989,"job"=>"prof"));
OR
$people = array(
array("name"=>"Johnny","year"=>1989, "job"=>"prof"),
array("name"=>"Timmy","year"=>1989, "job"=>"std"),
array("name"=>"Bobby""year"=>1988),
array("name"=>"Sam","year"=>1983),
array("name"=>"Tammy","year"=>1985),
array("name"="Danny","year"=>1983),
array("name"="Joe","year"=>1989,"job"=>"prof"));
How Can I got the only this people (endwith y and year=1989 and job=prof) ,Can I use array_filter?
or any build-in function to do this?
$people = array(
"Johnny"=>array("year"=>1989, "job"=>"prof")
);
OR
$people = array(
array("name="Johnny","year"=>1989, "job"=>"prof")
);

Answer 1

PHP 5.6 introduces the optional flag ARRAY_FILTER_USE_KEY that will allow this:
function endswithy($name) {
return (substr($name, -1) == 'y');
}
$people = array(
"Johnny"=>array("year"=>1989, "job"=>"prof"),
"Timmy"=>array("year"=>1989, "job"=>"std"),
"Bobby"=>array("year"=>1988),
"Sam"=>array("year"=>1983),
"Tammy"=>array("year"=>1985),
"Danny"=>array("year"=>1983),
"Joe"=>array("year"=>1989,"job"=>"prof")
);
$peopleEndingInY = array_filter($people, 'endswithy', ARRAY_FILTER_USE_KEY);
// Outputs: 5
var_dump(count($peopleEndingInY));
If you need to maintain and key and the value, another flag ARRAY_FILTER_USE_BOTH will do that as seen in this example:
$ar = array(
'key1' => 'value1',
'key2' => 'value2'
);
//Note that this doens't actually filter anything since it doesn't return a bool.
$output = array_filter($ar, function($value, $key){
echo sprintf("%s => %s\n", $key, $value);
}, ARRAY_FILTER_USE_BOTH);

Answer 2

Either use foreach with your current array's structure:
$people = array(
"Johnny" => array("year" => 1989, "job" => "prof"),
"Timmy" => array("year" => 1989, "job" => "std"),
"Bobby" => array("year" => 1988),
"Sam" => array("year" => 1983),
"Tammy" => array("year" => 1985),
"Danny" => array("year" => 1983),
"Joe" => array("year" => 1989, "job" => "prof"),
);
foreach ( $people as $name => $info ) {
if ( substr($name, -1) !== 'y' || $info['year'] != 1989 ) {
unset($people[$name]);
}
}
print_r($people);
// output:
Array
(
[Johnny] => Array
(
[year] => 1989
[job] => prof
)
[Timmy] => Array
(
[year] => 1989
[job] => std
)
)
Or convert your array so that name is value of inner array:
$people = array(
array('name' => 'Johnny', 'year' => 1989, 'job' => 'prof'),
array('name' => 'Timmy' , 'year' => 1989, 'job' => 'std'),
array('name' => 'Bobby' , 'year' => 1988),
array('name' => 'Sam' , 'year' => 1983),
array('name' => 'Tammy' , 'year' => 1985),
array('name' => 'Danny' , 'year' => 1983),
array('name' => 'Joe' , 'year' => 1989, 'job' => 'prof'),
);
function filter($item) {
return substr($item['name'], -1) === 'y' && $item['year'] == 1989;
}
$filteredPeople = array_filter($people, 'filter');
print_r($filteredPeople);
// output:
Array
(
[0] => Array
(
[name] => Johnny
[year] => 1989
[job] => prof
)
[1] => Array
(
[name] => Timmy
[year] => 1989
[job] => std
)
)