Help with PHP and MYSQL select function - php

Question

I am creating a browser statistics script in PHP.
When PHP finds a match in a table how do I retrieve the row and pull all three fields of the table into separate variables.
My table rows are (browser, version, amount)
so I want to select everything from the TB were
browser = $browser and version = $version.
But when this happens how do I add one to the amount field and resubmit the row. Without altering anything else. Below is the code I have.
$browser_name= "MSIE";
$version = "7";
$query = ("SELECT * FROM $TB
WERE browser = '$browser_name' AND version = '$version'");
$result = mysql_query($query);
$count = mysql_num_rows($result);
if($count == 1)
{
$mysql = ("SELECT * FROM $TB
WERE browser = '$browser_name' AND version = '$version'");
//code to add 1 to amount would be here
}
else
{
//if browser is not detected insert fresh row.
$mysql = "INSERT INTO $TB (browser, version, amount)
VALUES ('$browser_name', '$version', 1)";
}
I have been looking around for answers for ages but they just tell me how to select information out of a DB as a whole.

Answer 1

update table set amount_field = amount_field + 1 where browser = '$browser_name' and version = '$version'
I don't understand why you make twice the same select.

Answer 2

$browser_name= "MSIE";
$version = "7";
$query = "SELECT * FROM $TB WHERE browser = '$browser_name' AND version = '$version'";
$result = mysql_query($query);
if($data = mysql_fetch_assoc($result))
{
print_r($data);
//use UPDATE from other answers if you need one here.
}
else
{
//if browser is not detected insert fresh row.
mysql_query("INSERT INTO $TB (browser, version, amount)
VALUES ('$browser_name', '$version', 1)");
}
Beware of SQL injections!

Answer 3

SELECT * FROM $TB WHERE browser
you have a mistake it must be WHERE instead of WERE.

Answer 4

You update query will be like this
UPDATE $TB SET ammount = 1 WHERE browser = $browser and version = $version

Answer 5

There are hundreds of issues with your query like sanitization etc. I suggest you read a good mySQL book to improve the queries. But to answer your question:
//code to add 1 to ammount would be here
mysql_query("update $TB set amount = amount + 1 where browser = '".mysql_real_escape_string($browser_name)."' and version = '".mysql_real_escape_string($version)."'");

Answer 6

First of all, you should connect to db using
$db = new mysqli('host','user','pass','dbname');
Then, your query isn't right. You have a sql syntax error.
SELECT * FROM table WHERE column = value
So, without prepare, your code should look like:
$tb = 'table_name'; // to avoid sql injections use addslashes() to your input
$browserName = addslashes('browser_name'); // like this
$version = '7';
$db = new mysqli('host','user','pass','dbname');
$result = $db->query("SELECT * FROM $tb WERE browser = '$browserName' AND version = '$version'");
// Than, you can fetch it.
while ($result->fetch as $row) {
echo $row['yourColumn']; // will display value of your row.
}
$db->query("INSERT INTO $tb (browser, version) VALUES ('$browser_name', '$version')";
}");
And, that's all. You can count your records using mysql count() method. Your code will work. I advice you, at first go to php.net and check the doc. There are many examples.