I want to know how to display report by month using PHP and Mysql
Example of Report on the web page:
January 2011
==============
Store Name | Total Order Cost
SHOP A | £123
SHOP B | £100
February 2011
==============
Store Name | Total Order Cost
SHOP A | £123
SHOP B | £100
SHOP C | £99.40
I have mysql tables
tbl_shop
ShopID
ShopName
tbl_order
OrderID
ShopID
OrderDate
Total
You will need to iterate trough the result of the query and create an multidimensional array using the month/year combination as keys. The query below should be a good indication on how to fetch the required information from your database.
SELECT
MONTH(to.OrderDate),
YEAR(to.OrderDate),
SUM(to.Total),
to.*
FROM tbl_order as to
INNER JOIN tbl_shop as ts ON ts.ShopID = to.ShopID
GROUP BY to.ShopID, MONTH(to.OrderDate), YEAR(to.OrderDate)
Note that I havn't tested this query - please handle it as pseudo-code. You might need to throw around the GROUP BY fields a little and test if it works.
Use
SELECT ShopName,SUM(Total),MONTHNAME(OrderDate) from tbl_shop
left join tbl_order
on tbl_shop.ShopID = tbl_order.ShopID
GROUP By(ShopID),MONTHNAME(OrderDate)
will give you All months report.
Use this query:
SELECT monthname(o.OrderDate) as Month, year(o.OrderDate) as Year,
s.ShopName, sum(o.Total) as Total
FROM tbl_Shop s JOIN tbl_Order o
ON s.ShopID=o.ShopID
GROUP BY o.shopID,year(o.Orderdate),month(o.Orderdate)
ORDER BY year(o.OrderDate),month(o.OrderDate)
then for every row from result if month+year has changed (a variable $last_date could help) then print
$Month $Year
==============
Store Name | Total Order Cost
$ShopName | $Total
else print
$ShopName | $Total
Related
The scenario is I am the admin and I have a session to make, the session table consists of a session_id, coach_name, date(format Y-m-d).
Now I want to count the total activity of the coach every "MONTH".
So my point is how will I get this kind of output in a SQL query.
The desired output is the amount of activity per month, per coach.
Name | No. of session this month
Coach_name1 = 13
Coach_name2 = 5
This is my current query that gives me the coach name but I don't know how to get for each MONTH
public function getAll(){
$query = $this->db->query('SELECT DISTINCT coach_name FROM sessions);
return $query->result();
}
Use this query to get the result.
Use mysql MONTH() to get Month number from date and group by it. You will get all month wise data.
SELECT coach_name,
Count(*) AS activities
FROM sessions
WHERE Month(date) = 8 //for specfic month
GROUP BY coach_name, Month(date) // for all months
Use this query to dynamincally get current month based on system date
SELECT coach_name,
Count(*) AS activities
FROM sessions
WHERE Month(date) = MONTH(CURRENT_DATE()) //for selecting current month.
GROUP BY coach_name
You have to prepare query like below:
select
coach_name,
month(your_date_field),
count(1)
from
your_table
where
month(your_date_field) = 8
group by
coach_name, month(your_date_field)
Which would return records like below,
| coach_name | month(your_date_field) | count(1) |
+---------------+------------------------+------------+
| Coach_name1 | 8 | x |
| Coach_name2 | 8 | x |
| Coach_name3 | 8 | x |
+---------------+------------------------+------------+
In codeigniter
$this->db->select("coach_name, month(your_date_field) as month_number,count(1) as counts");
$this->db->where('month(your_date_field)',8);
$this->db->group_by('coach_name,MONTH(your_date_field)');
$query = $this->db->get('your_table');
// results
foreach ($query->result_array() as $row)
{
// do this to see array
print_r($row);
// to access individual fields
echo $row['coach_name'];
echo $row['month_number'];
echo $row['counts'];
}
Use MySQL's MONTH() in your query. So basically if all your data is in your sessions table try the following in your query.
SELECT DISTINCT(`name`),COUNT(`name`) AS `activity` FROM `session`
WHERE MONTH(`date`)=8 GROUP BY `name`;
Check in SQLFiddle
I have two tables with the name of customers and installments.i.e.
Customer Table:
id | name |contact |address
1 | xyz |33333333|abc
2 | xrz |33322333|abcd
Installments Table:
id | customer_id |amount_paid |amount_left | date
1 | 1 |2000 |3000 | 13/05/2017
2 | 1 |2000 |1000 | 13/06/2017
Now, I want to fetch the latest installment row from installments table for every user, I can use that with the following query,
SELECT * FROM installments WHERE customer_id=1 ORDER BY `id` DESC LIMIT 1
Now, the issue is that I want to do it for all the customer ids. I tried sub query thing but that doesn't supports multiple rows. I tried to store all customer IDs in an array in PHP and used "IN" but because the number of customers is more than 3000, it takes too long and returns an error of execution time exceeded.
Any kind of help or tip will be really appreciated. Thanks
SELECT
Customers.CustomerId,
Customers.Name,
Customers.Contact,
Customers.Address,
Installments.InstallmentId,
Installments.AmountPaid,
Installments.AmountLeft,
Installments.Date
FROM
Customers
INNER JOIN
(
SELECT
MAX( InstallmentId ) AS MaxInstallmentId,
CustomerId
FROM
Installments
GROUP BY
CustomerId
) AS LatestInstallments ON Customers.CustomerId = LatestInstallments.CustomerId
INNER JOIN Installments ON LatestInstallments.MaxInstallmentId = Installments.InstallmentId
you can do something like this
SELECT c.*,I.* FROM Customer_Table c LEFT JOIN Installments_Table I ON c.id=I.customer_id ORDER BY c.id DESC LIMIT 1
If You wants to add limit of list then only set limit else leave limit part. Untill I got Your Question this will be help you. else your problem can be something else.
SELECT cust.*,inst_disp.* FROM Customer AS cust
LEFT JOIN (
SELECT MAX(id) AS in_id, customer_id
FROM installments
GROUP BY customer_id
) inst
ON inst.customer_id = cust.id
LEFT JOIN installments as inst_disp ON inst_disp.id = inst.in_id
I have the following tables, in a standard shop:
(id is always primary key, auto-increment, ts is always type TIMESTAMP, updated ON_UPDATE CURRENT_TIMESTAMP)
table sales:
id | total | tendered | flag | userID | ts
1 0.6 0.6 0 4 2013-11-21 08:12:23
Sales is the parent table, userID is related to the user that made the sale. total and tendered are both of type FLOAT. flag is of type VARCHAR and could be Free Order.
table receipts:
id | oID | pID | quantity | ts
1 1 26 1 2013-11-21 08:11:25
Receipts holds a line for each unique type of product sold. oID is type INT and relates to the id of table sales. pID is of type INT and relates to the id of table products.
table products:
id | name | price | cID | display | ts
1 Mars 0.6 3 1 2014-01-17 07:55:25
Products is the central data for each product in the database. Here is a line for mars bars. cID relates to the id in table categories.
table categories
id | name | display | ts
3 Snacks 1 2013-11-14 12:06:44
Categories is the table holding all the data about each category, and can have multiple products relating to a single row. display is of type INT and dictates when the category is enabled or disabled (1 = 'true')
My question is, I want to output information like this:
**Snacks**
(name) (quantity) (price) (total)
Fruit 3 50p £1.50
Twix 1 60p 60p
Boost 1 60 60p
**Hot Drinks**
(name) (quantity) (price) (total)
English Tea 15 60p £9.00
Speciality Teas 2 60p £1.20
Which I have the following SQL for:
SELECT categories.name AS category, products.name, pID,
(SELECT SUM(quantity) FROM receipts WHERE pID=r.pID AND DATE(ts) = CURDATE()) AS quantity,
products.price,r.ts
FROM receipts r
LEFT JOIN products ON r.pID = products.id
LEFT JOIN categories ON products.cID = categories.id
WHERE DATE(r.ts) = CURDATE()
GROUP BY r.pID
ORDER BY categories.name;
Which seems to give me the correct information, but I am not 100% certain. If anyone could verify that this works, I would be most grateful. But when I want to see a particular day, I get unusual figures with the following SQL:
$postfrom = $_POST['from_mm']."/".$_POST['from_dd']."/20".$_POST['from_yy'];
$postto = $_POST['to_mm']."/".$_POST['to_dd']."/20".$_POST['to_yy'];
$from = strtotime($postfrom . " 6:00");
$to = strtotime($postto . " 23:59");
$itemised = select("SELECT categories.name AS category, products.name, pID,
(SELECT SUM(quantity) FROM receipts WHERE pID = r.pID AND UNIX_TIMESTAMP(r.ts) > '{$from}' AND UNIX_TIMESTAMP(r.ts) < '{$to}')
AS quantity, products.price
FROM receipts r
LEFT JOIN products ON r.pID = products.id
LEFT JOIN categories ON products.cID = categories.id
WHERE UNIX_TIMESTAMP(r.ts) > '{$from}'
AND UNIX_TIMESTAMP(r.ts) < '{$to}'
GROUP BY r.pID
ORDER BY categories.name;");
(function 'select' simply returns an array of the SQL table). The thing is, I could find the results easily by looping through in PHP and adding it up that way. But I know this is possible with SQL, I just don't know why It isnt working. Can somebody please help?
Edit SQL sample fiddle is here: http://sqlfiddle.com/#!2/23af4 although I couldn't do more than half a day of data due to 8000 character restrictions.
Try this:
SELECT categories.name AS category, products.name AS name,
receipts.quantity AS quantity, products.price AS price,
(receipts.quantity * products.price) AS total
FROM categories
JOIN products
ON categories.id = products.cID
JOIN receipts
ON receipts.pID = products.ID
WHERE DATE(receipts.ts) = CURDATE()
ORDER BY categories.name
SQLFiddle demo
With regard to the date restriction, you could use BETWEEN ... AND ... to specify the date and time. Using an absolute date and time moment or relative to the current day and time, for example WHERE DATE(receipts.ts) BETWEEN concat(curdate() -5,' 6:00:00 AM') AND curdate() -4
I have these tables:
table 1 : attendance
-------------------------------
ID | DATE | EMPLOYEE_ID |
-------------------------------
1 2013-09-10 1
2 2013-09-10 2
3 2013-09-10 3
-------------------------------
table 2: employee
---------------
ID | NAME |
---------------
1 Smith
2 John
3 Mark
4 Kyle
5 Susan
6 Jim
---------------
My actual code to show employee option.
while($row=mysql_fetch_array($query)){
echo "<option value='$row[employee_id]'>$row[first_name] $row[last_name]</option>";
}
?>
How can i show the list of employee that not registered in table 1?
The condition is if an employee already registered in table 1, they won't appear on the option.
I want to show the list in <option>'s of <select> element. So it will return: kyle, susan, jim.
Please tell me the correct query or if there is any better option, it'll be good too. Please give some solution and explain. Thank you very much
UPDATE / EDIT:
it also based on current date, if in table 1 have no latest date e.g. today it's 2013-09-15. It will show all of employee.
You can do this with a left join and then checking for no matches:
select e.*
from employee e left outer join
attendance a
on e.id = a.employee_id
where a.employee_id is null;
This is probably the most efficient option in MySQL.
EDIT:
To include a particular date, add the condition to the on clause:
select e.*
from employee e left outer join
attendance a
on e.id = a.employee_id and a.date = date('2013-09-20')
where a.employee_id is null;
If I understood correctly this should work, get all employees whose ID is not in the attendance table.
SELECT * FROM employee WHERE employee.ID NOT IN
(SELECT EMPLOYEE_ID FROM attendance)
I have a table which stores bookings of rooms, the schema is:
ID | ROOM_ID | CHECK_IN_DATE | CHECK_OUT_DATE | USER_ID
I need to run a search query for rooms which are available/unavailable between a set range of dates.
Also keep in mind that there exists another table which holds dates when the room is prebooked and its in the format:
ROOM_ID | DATE
SO I need to run a query which looks for rooms available within a set range, How would I formulate the query?
I'm using MySQL here.
---edit---
Theres also a Rooms table of the schema:
ID | ROOM DETAILS etc
The unavailability/prebooked dates table basically holds sporadic single dates, each date in the unavailability table refers to a date when the room for some reason cannot be booked eg: maintenance etc
SELECT
ROOM_ID
FROM
Rooms r
LEFT JOIN Bookings b ON (
r.ROOM_ID = b.ROOM_ID
AND b.CHECK_IN_DATE > '$MAX_DATE'
AND b.CHECK_OUT_DATE < '$MIN_DATE'
)
I'm not sure how pre-booked rooms factors in as there is no date range. Do pre-booked rooms also get an entry on bookings or not?
SELECT id FROM rooms WHERE id NOT IN (
SELECT room_id FROM bookings
WHERE check_in_date < 'end date' AND check_out_date > 'start date'
);
there are like 5 possible ways:
---s-----e---
s-e----------
--s-e--------
-----s-e-e---
--------s-e--
----------s-e
s = start / e=end firste line is your database set and the other are possible searches
only the first and last one are the ones that you want so what you look for is:
search.end < entry.start OR search.start > entry.end