Distinct Table field tags - php

Question

I have a table with a field (cat_tags) which contain the following rows:-
id - cat_tags - date_added
1 - yam, potato, onion, pepper,beans - 23-12-2011
row1 - yam, potato, onion, pepper 23-12-2011
row2 - onion, pepper, beans - 23-12-2011
row3 - pepper, beans, rice - 23-12-2011
row4 - rice, potato, pepper, yam - 23-12-2011
row5 - beans, rice, onion, food - 23-12-2011
.....
.....
.....
pls how can I get a DISTINCT list of items and the number of times(frequency) they occurred in the entire table field?
Eg. pepper x 4
onion x 3
yam x 2
thank you in advance

Answer 1

First normalize your table(s).
Table tags
id unsigned integer autoincrement primary key,
tag varchar(40) not null,
unique index tag(tag)
Table Item_tags
id unsigned integer autoincrement primary key,
tag_id integer not null,
item_id integer not null
Table items
id unsigned integer autoincrement primary key,
date_added date not null
Insert an item into your database using the following series of queries:
INSERT INTO Items VALUES (null, NOW());
SELECT #last_item_id:= LAST_INSERT_ID();
REPLACE IGNORE INTO tags (tag) VALUES ('pepper', 'onion', 'rice')
INSERT INTO Item_tags
SELECT
null as id
, tags.id
, last_item_id
FROM tags WHERE tags.tag IN ('pepper', 'onion', 'rice')
If you want to simplify the addition of items and streamline your php code,
use a blackhole table and a trigger on that table.
CREATE TABLE bh_items (
id unsigned integer autoincrement primary key,
date_added timestamp,
tag1 varchar(45) not null,
tag2 varchar(45) default null,
tag3 varchar(45) default null,
tag4 varchar(45) default null,
tag5 varchar(45) default null,
tag6 varchar(45) default null,
tag7 varchar(45) default null,
tag8 varchar(45) default null,
tag9 varchar(45) default null,
tag10 varchar(45) default null) ENGINE = blackhole;
DELIMITER $$
CREATE TRIGGER ai_bn_items_each AFTER INSERT ON bh_items FOR EACH ROW
BEGIN
DECLARE last_item_id integer;
INSERT INTO Items VALUES (null, new.date_added);
SELECT LAST_INSERT_ID() INTO last_item_id;
REPLACE IGNORE INTO tags ((null, new.tag1)
,(null, new.tag2)
,(null, new.tag3)
,(null, new.tag4)
,(null, new.tag5)
,(null, new.tag6)
,(null, new.tag7)
,(null, new.tag8)
,(null, new.tag9)
,(null, new.tag10));
INSERT IGNORE INTO item_tags (item_id, tag_id)
SELECT last_item_id, tags.tag FROM tags
WHERE tags.tag
IN (new.tag1, new.tag2, new.tag3, new.tag4, new,tag5
, new.tag6, new.tag7, new.tag8, new.tag9, new.tag10);
END $$
DELIMITER ;
If you use the trigger you can just insert into the blackhole table and the trigger will then update all your 3 tables.
INSERT INTO bh_items VALUES (null, null, 'onion', 'rice', 'pepper'
, null, null, null, null, null, null, null)
All your tables will be automagically updated.
Back to your question
You can then select from this using this query:
SELECT tags.tag, COUNT(*) as freq FROM item_tags
INNER JOIN tags ON (item_tags.tag_id = tags.id)
GROUP BY item_tags.tag_id
Links:
blackhole: http://dev.mysql.com/doc/refman/5.1/en/blackhole-storage-engine.html
replace into: http://dev.mysql.com/doc/refman/5.1/en/replace.html
Triggers: http://dev.mysql.com/doc/refman/5.1/en/triggers.html
Create table: http://dev.mysql.com/doc/refman/5.1/en/create-table.html

Answer 2

If I have understood your question correctly, this should work:
$result = mysql_query("SELECT cat_tags FROM table");
while($row = mysql_fetch_array($result))
{
//Split the row into an array based on the comma
$detail_array = explode(",", $row['cat_tags']);
//Go through that array and index a master count for each occurence of the same value
//Trim due to the spaces after the comma in your field
foreach($detail_array as $key=>$val)
{
$output_array[trim($val)] = $output_array[trim($val)] + 1;
}
}
print_r($output_array);

Answer 3

You should first normalize your table structure.
It is not compliant with the first normal form, making the requested operation way more complicated than it needs to be.