jQuery(document).ready(function(){
// Set the data text
var dataText = "
{
name: 'John',
time: '2pm'
}";
alert(dataText);
// Create the AJAX request
$.ajax({
type: "POST", // Using the POST method
url: "/ajax/analytics/push", // The file to call
data: dataText, // Our data to pass
success: function() { // What to do on success
alert("Data Loaded: " + dataText);
}
});
});
</script>
hello im still learning ajax. how can we push a array of $_POST?
1.im trying to do something like
var dataText['name'] = 'Jhon';
var dataText['time] = '2pm';
then somehow turns it into
$_POST['name'] = 'Jhon';
$_POST['time'] = '2pm';
then send it to the url..
2.is there a way to debug this ? what im doing now is im writing
# somehow doesnt work becouse its not auto refresh when the ajax sends a post
var_dump($_POST);
# ok heres how i debug it right now.
ob_start();
// write content
$content = $_POST;
ob_end_clean();
file_put_contents('CACHE',$content);
in to a file, i hope there is a better solution for this..
Thankyou for looking in.
Adam Ramadhan
I'm not entirely sure what you're doing. You seem to be building JSON manually (and not doing it correctly) and then passing that (in the JSON-serialised string form) to your file. You then seem to expect it to be parsed by PHP automatically.
It would be better to send it as key-value pairs. You can let jQuery do this for you if you pass in an object. This won't look much different to your existing code:
var dataText =
{
name: 'John',
time: '2pm'
};
Note that I have removed the double quotes. This is primarily because it is illegal to have a JS string covering more than one line without escaping the line breaks. It is also because you want the object to pass into your $.ajax call.
These should be available as $_POST['name'] and $_POST['time'] now.
file_put_contents('CACHE',serialize($content));
or
foreach($_POST as $k => $v) $content .= $k .'='.$v;
jQuery(document).ready(function(){
// Set the data text
var dataText =
{
name: 'John',
time: '2pm'
};
alert(dataText);
// Create the AJAX request
$.ajax({
type: "POST", // Using the POST method
url: "/ajax/analytics/push", // The file to call
data: dataText, // Our data to pass
success: function() { // What to do on success
alert("Data Loaded: " + dataText);
}
});
});
# ok heres how i debug it right now.
ob_start();
# somehow doesnt work becouse its not auto refresh when the ajax sends a post
var_dump($_POST);
$content = ob_get_contents();
ob_end_clean();
file_put_contents('CACHE',$content);
Related
I want to send an array to PHP (POST method) using jQuery.
This is my code to send a POST request:
$.post("insert.php", {
// Arrays
customerID: customer,
actionID: action
})
This is my PHP code to read the POST data:
$variable = $_POST['customerID']; // I know this is vulnerable to SQLi
If I try to read the array passed with $.post, I only get the first element.
If I inspect the POST data with Fiddler, I see that the web server answers with "500 status code".
How can I get the complete array in PHP?
Thanks for your help.
To send data from JS to PHP you can use $.ajax :
1/ Use "POST" as type, dataType is what kind of data you want to receive as php response, the url is your php file and in data just send what you want.
JS:
var array = {
'customerID': customer,
'actionID' : action
};
$.ajax({
type: "POST",
dataType: "json",
url: "insert.php",
data:
{
"data" : array
},
success: function (response) {
// Do something if it works
},
error: function(x,e,t){
// Do something if it doesn't works
}
});
PHP:
<?php
$result['message'] = "";
$result['type'] = "";
$array = $_POST['data']; // your array
// Now you can use your array in php, for example : $array['customerID'] is equal to 'customer';
// now do what you want with your array and send back some JSON data in your JS if all is ok, for example :
$result['message'] = "All is ok !";
$result['type'] = "success";
echo json_encode($result);
Is it what you are looking for?
I want to send fields data from a form to a file via AJAX and I found this solution online: http://techglimpse.com/pass-localstorage-data-php-ajax-jquery/
The only problem is that I have multiple fields instead of a single field and I want to save the output (localStorage) in an HTML (or any other format) file instead of showing it in an #output div.
How can I do that?
You can see my work that I've done till now here: Save form data using AJAX to PHP
And here's my HTML/JS code: http://jsbin.com/iSorEYu/1/edit & PHP code http://jsbin.com/OGIbEDuX/1/edit
PHP:
<h1>Below is the data retrieved from SERVER</h1>
<?php
date_default_timezone_set('America/Chicago'); // CDT
echo '<h2>Server Timezone : ' . date_default_timezone_get() . '</h2>';
$current_date = date('d/m/Y == H:i:s ');
print "<h2>Server Time : " . $current_date . "</h2>";
$dataObject = $_POST; //Fetching all posts
echo "<pre>"; //making the dump look nice in html.
var_dump($dataObject);
echo "</pre>";
//Writes it as json to the file, you can transform it any way you want
$json = json_encode($dataObject);
file_put_contents('your_data.txt', $json);
?>
JS:
<script type="text/javascript">
$(document).ready(function(){
localStorage.clear();
$("form").on("submit", function() {
if(window.localStorage!==undefined) {
var fields = $(this).serialize();
localStorage.setItem("eloqua-fields", JSON.stringify( fields ));
alert("Stored Succesfully");
$(this).find("input[type=text]").val("");
alert("Now Passing stored data to Server through AJAX jQuery");
$.ajax({
type: "POST",
url: "backend.php",
data: fields,
success: function(data) {
$('#output').html(data);
}
});
} else {
alert("Storage Failed. Try refreshing");
}
});
});
</script>
NOTE: Replace the file format of your_data file to html in the PHP code if you want your JSON data in HTML format.
You are overcomplocating things. The check for localStorage can be way simpler (other options). jQuery has a serialze() function that takes all form elements and serializes it. You can store them under "eloqua-fields" so you can find it again. No need to do some fancy random retrival.
I'd like to add that not all of you code makes sense. Why use localstorage if you clear it every time the DOM is ready? Your validation does not abort the sending process if there are errors but I assume you just want to play around with stuff.
$(document).ready(function(){
localStorage.clear();
$("form").on("submit", function() {
if(window.localStorage!==undefined) {
var fields = $(this).serialize();
localStorage.setItem("eloqua-fields", JSON.stringify( fields ));
alert("Stored Succesfully");
$(this).find("input").val(""); //this ONLY clears input fields, you also need to reset other fields like select boxes,...
alert("Now Passing stored data to Server through AJAX jQuery");
$.ajax({
type: "POST",
url: "backend.php",
data: {data: fields},
success: function(data) {
$('#output').html(data);
}
});
} else {
alert("Storage Failed. Try refreshing");
}
});
});
For the server part if you just want to store your data somewhere.
$dataObject = $_POST['data'];
$json = json_decode($dataObject);
file_put_contents('your_data.txt', $json) ;
I want to send an array from javascript to php via ajax function.
And I don't want show the result as callback, but immediately open the target php file and show the images.
I mean, I want open the php file directly on the server side.
I think this is quite simple, but I just have no idea.
My javascript looks like:
var stringArray = new Array("/images/1.jpg", "/images/2.jpg", "/images/3.jpg");
$.ajax({
url: 'test.php',
data: {stringArray:stringArray},
success: function() {
window.open('test.php'); // It opens test.php in a window but shows nothing!
},
});
the test.php file:
$stringArray = $_GET['stringArray'];
foreach($stringArray as $value) {
echo "<img src=" . $value . "></img>";
}
Thanks for any help!
Likely the window.open command is being called without the POST data needed.
Now, I don't know what you want to do here but, why send an Ajax request when you don't really want to make use of it?.
Edit: just to make it a bit clearer, you seem to be calling the php file with no data trough POST. There is no clean way of opening a window in JS with POST data, just try GET for no critical information. Let is know how it goes.
As I can see, You are sending data by post method and accessing in test.php
but when u open file via window.location it doesn't get POST data hence no data get populated
You can achieve it via $_SESSION.
in test.php
session_start();
if(!empty($_POST['stringArray'])) {
$_SESSION['stringArray'] = $_POST['stringArray'];
}
$stringArray = (isset($_SESSION['stringArray']) && $_SESSION['stringArray'] != '') ? $_SESSION['stringArray'] : $_POST['stringArray'];
foreach($stringArray as $value) {
echo "<h3>" . $value . "</h3>";
}
Hope this will work for you...
you should write
var stringArray = new Array("apple", "banana", "orange");
$.ajax({
type: 'post',
url: 'test.php',
data: {stringArray:stringArray},
success: function(message) {
window.open(message); // It will open a window with contents.
},
});
I doesn't show the output because when you open the page on the callback you are not sending anything through to the test page through the post variable. Why you would want to do this I don't know. Send the information through the url, get.
I have a function which saves an array each time the button is clicked to localStorage.The button will be clicked multiple times and I need to put this Array list into PHP somehow which is on another page from this file.
Thanks
a.js
(this function listens onLoad of the page)
function doFirst(){
var button = document.getElementById("button");
button.addEventListener("click", save, false);
var buttons = document.getElementById("clear");
buttons.addEventListener("click", clear, false);
var buttonss = document.getElementById("submittodb");
buttonss.addEventListener("click", toPHP, false);
$.ajax({
method: 'post',
dataType: 'json',
url: 'edit.php',
data: { items: oldItems }, //NOTE THIS LINE, it's QUITE important
success: function() {//some code to handle successful upload, if needed
}
});
}
function save(){
var oldItems = JSON.parse(localStorage.getItem('itemsArray')) || [];
var newItem = {
'num': document.getElementById("num").value,
'methv': document.getElementById("methv").value,
'q1': document.getElementById("q1").value,
'q2':document.getElementById("q2").value,
'q3':document.getElementById("q3").value,
'q4':document.getElementById("q4").value,
'comm':document.getElementById("comm").value,
};
oldItems.push(newItem);
localStorage.setItem('itemsArray', JSON.stringify(oldItems));}
edit.php
$parsed_array = json_decode($_POST['items']);
and i get the error: Notice: Undefined index: items in /home/project/edit.php on line 9
In order to pass this array to PHP you need to:
JSon-encode it
Make an AJAX or POST request to PHP
Parse the passed array into PHP array
If you're using jQuery (if you're not you should start - it is really handy tool) steps (1) and (2) is as simple as
$.ajax({
method: 'post',
dataType: 'json',
url: 'the URL of PHP page that will handle the request',
data: { items: oldItems }, //NOTE THIS LINE, it's QUITE important
success: function() {//some code to handle successful upload, if needed
}
});
In PHP you can parse the passed array with just
$parsed_array = json_decode($_POST['items']);
There is a direct connection between { items: oldItems } and $_POST['items']. The name of variable you give to the parameter in javascript call will be the name of key in $_POST array where it ends up. So if you just use data: oldItems in javascript you'll have all your entities scattered around the $_POST array.
More on $.ajax, and json_decode for reference.
You can create an AJAX function (use jQuery) and send the JSON data to the server and then manage it using a PHP function/method.
Basically, you need to send the data from the client (browser) back to the server where the database hosted.
Call JSON.stringify(oldItems); to create the json string
Do a Do a POST request using AJAX.
Probably the simplest way is using jQuery:
$.post('http://server.com/url.php', { items: JSON.stringify(oldItems) }, function(response) {
// it worked.
});
I am creating a site where the user fills out a form, has that data sent to a php script and display result in a div and have been struggling to complete it for a while now. Below is the code i have created:
the button activates this function:
function callFunc()
{
var testVar = "Example 01";
$.ajax(
{
url: "public/includes/userCreate.php",
type: "POST",
data: testVar,
success: function(html)
{
$('#web_Content').html(html);
}
});
};
The PHP file is this:
<?php
$test = $_POST['testVar'];
echo $test;
?>
For some reason though i doesnt work. I mean it doesnt inject the value of the echo command into the div, If however i take out the variable data from the PHP and just have it echo a simple element, it does work and injects the echo value into the div, Below is the code that will run:
<?php
$test = $_POST['testVar'];
echo "<h3>User ???? Created.</h3>";
?>
I think it is because i am not sending data correctly, Could anyone tell me the correct way to send the data to the PHP script and also, how to send more than one variable?
you need data: { testVar: "Example 01"} it is a key value pair. This will generate a query string parameter like testVar=Example%2001
The correct way to send data via the AJAX function is with either an object or string. Examples:
var pData = "testVar=Example.";
$.ajax({
/* Other ajax params */
data: pData,
/* Other ajax params */
});
or
var pData = { testVar: "Example." };
$.ajax({
/* Other ajax params */
data: pData,
/* Other ajax params */
});